Oracle PL/SQL/Regular Expressions/Range

Ranges (Minus Signs): Create a range for a match using a minus sign

SQL> create table TestTable(
  2    ID                    VARCHAR2(4 BYTE)         NOT NULL,
  3    Description           VARCHAR2(40 BYTE)
  4  )
  5  /
Table created.
SQL>
SQL>
SQL> insert into TestTable (ID, Description) values("1","1234 5th Street");
1 row created.
SQL> insert into TestTable (ID, Description) values("2","1 Culloden Street");
1 row created.
SQL> insert into TestTable (ID, Description) values("3","1234 Road");
1 row created.
SQL> insert into TestTable (ID, Description) values("4","33 Thrid Road");
1 row created.
SQL> insert into TestTable (ID, Description) values("5","One than another");
1 row created.
SQL> insert into TestTable (ID, Description) values("6","2003 Movie");
1 row created.
SQL> insert into TestTable (ID, Description) values("7","Start With Letters");
1 row created.
SQL>
SQL> select * from TestTable;
ID   DESCRIPTION
---- ----------------------------------------
1    1234 5th Street
2    1 Culloden Street
3    1234 Road
4    33 Thrid Road
5    One than another
6    2003 Movie
7    Start With Letters
7 rows selected.
SQL>
SQL>
SQL>
SQL>
SQL> -- Ranges (Minus Signs): Create a range for a match using a minus sign
SQL>
SQL> -- Create a range for a match using a minus sign.
SQL>
SQL> -- Ask for the letters "a" through "j" followed by an "n"
SQL>
SQL> SELECT description, REGEXP_INSTR(description,"[a-j]n") where_it_is
  2  FROM testTable
  3  WHERE REGEXP_INSTR(description,"[a-j]n") > 0;
DESCRIPTION                              WHERE_IT_IS
---------------------------------------- -----------
1 Culloden Street                                  9
One than another                                   7
SQL>
SQL>
SQL> drop table TestTable;
Table dropped.
SQL>
SQL>
SQL>