Oracle PL/SQL/Regular Expressions/Range

Ranges (Minus Signs): Create a range for a match using a minus sign

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SQL> create table TestTable(

 2    ID                    VARCHAR2(4 BYTE)         NOT NULL,
 3    Description           VARCHAR2(40 BYTE)
 4  )
 5  /

Table created. SQL> SQL> SQL> insert into TestTable (ID, Description) values("1","1234 5th Street"); 1 row created. SQL> insert into TestTable (ID, Description) values("2","1 Culloden Street"); 1 row created. SQL> insert into TestTable (ID, Description) values("3","1234 Road"); 1 row created. SQL> insert into TestTable (ID, Description) values("4","33 Thrid Road"); 1 row created. SQL> insert into TestTable (ID, Description) values("5","One than another"); 1 row created. SQL> insert into TestTable (ID, Description) values("6","2003 Movie"); 1 row created. SQL> insert into TestTable (ID, Description) values("7","Start With Letters"); 1 row created. SQL> SQL> select * from TestTable; ID DESCRIPTION

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1 1234 5th Street 2 1 Culloden Street 3 1234 Road 4 33 Thrid Road 5 One than another 6 2003 Movie 7 Start With Letters 7 rows selected. SQL> SQL> SQL> SQL> SQL> -- Ranges (Minus Signs): Create a range for a match using a minus sign SQL> SQL> -- Create a range for a match using a minus sign. SQL> SQL> -- Ask for the letters "a" through "j" followed by an "n" SQL> SQL> SELECT description, REGEXP_INSTR(description,"[a-j]n") where_it_is

 2  FROM testTable
 3  WHERE REGEXP_INSTR(description,"[a-j]n") > 0;

DESCRIPTION WHERE_IT_IS

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1 Culloden Street 9 One than another 7 SQL> SQL> SQL> drop table TestTable; Table dropped. SQL> SQL> SQL>

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