Oracle PL/SQL Tutorial/Numerical Math Functions/MOD — различия между версиями
Admin (обсуждение | вклад) м (1 версия) |
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Версия 13:45, 26 мая 2010
Содержание
- 1 Combine case statement with mod function
- 2 List all employee with odd employee number
- 3 MOD(8, 3)
- 4 MOD(8, 4)
- 5 MOD function in action
- 6 MOD(x, y) gets the remainder when x is divided by y.
- 7 select mod(8,3), mod(13,0)
- 8 Use floor(), mod() and date calculation to show how many weeks and days an employee has been working here
- 9 Use mod() function to get all event employee id
Combine case statement with mod function
SQL>
SQL>
SQL> create table employees(
2 empno NUMBER(4)
3 , ename VARCHAR2(8)
4 , init VARCHAR2(5)
5 , job VARCHAR2(8)
6 , mgr NUMBER(4)
7 , bdate DATE
8 , msal NUMBER(6,2)
9 , comm NUMBER(6,2)
10 , deptno NUMBER(2) ) ;
Table created.
SQL>
SQL>
SQL> insert into employees values(1,"Jason", "N", "TRAINER", 2, date "1965-12-18", 800 , NULL, 10);
1 row created.
SQL> insert into employees values(2,"Jerry", "J", "SALESREP",3, date "1966-11-19", 1600, 300, 10);
1 row created.
SQL> insert into employees values(3,"Jord", "T" , "SALESREP",4, date "1967-10-21", 1700, 500, 20);
1 row created.
SQL> insert into employees values(4,"Mary", "J", "MANAGER", 5, date "1968-09-22", 1800, NULL, 20);
1 row created.
SQL> insert into employees values(5,"Joe", "P", "SALESREP",6, date "1969-08-23", 1900, 1400, 30);
1 row created.
SQL> insert into employees values(6,"Black", "R", "MANAGER", 7, date "1970-07-24", 2000, NULL, 30);
1 row created.
SQL> insert into employees values(7,"Red", "A", "MANAGER", 8, date "1971-06-25", 2100, NULL, 40);
1 row created.
SQL> insert into employees values(8,"White", "S", "TRAINER", 9, date "1972-05-26", 2200, NULL, 40);
1 row created.
SQL> insert into employees values(9,"Yellow", "C", "DIRECTOR",10, date "1973-04-27", 2300, NULL, 20);
1 row created.
SQL> insert into employees values(10,"Pink", "J", "SALESREP",null,date "1974-03-28", 2400, 0, 30);
1 row created.
SQL>
SQL>
SQL> select case mod(empno,2)
2 when 0 then "EVEN "
3 else "ODD "
4 end as empno
5 , sum(msal)
6 from employees
7 group by mod(empno,2);
EMPNO SUM(MSAL)
----- ----------
ODD 8800
EVEN 10000
SQL>
SQL>
SQL> drop table employees;
Table dropped.
SQL>
SQL>
List all employee with odd employee number
SQL>
SQL>
SQL> create table employees(
2 empno NUMBER(4)
3 , ename VARCHAR2(8)
4 , init VARCHAR2(5)
5 , job VARCHAR2(8)
6 , mgr NUMBER(4)
7 , bdate DATE
8 , msal NUMBER(6,2)
9 , comm NUMBER(6,2)
10 , deptno NUMBER(2) ) ;
Table created.
SQL>
SQL>
SQL> insert into employees values(1,"Jason", "N", "TRAINER", 2, date "1965-12-18", 800 , NULL, 10);
1 row created.
SQL> insert into employees values(2,"Jerry", "J", "SALESREP",3, date "1966-11-19", 1600, 300, 10);
1 row created.
SQL> insert into employees values(3,"Jord", "T" , "SALESREP",4, date "1967-10-21", 1700, 500, 20);
1 row created.
SQL> insert into employees values(4,"Mary", "J", "MANAGER", 5, date "1968-09-22", 1800, NULL, 20);
1 row created.
SQL> insert into employees values(5,"Joe", "P", "SALESREP",6, date "1969-08-23", 1900, 1400, 30);
1 row created.
SQL> insert into employees values(6,"Black", "R", "MANAGER", 7, date "1970-07-24", 2000, NULL, 30);
1 row created.
SQL> insert into employees values(7,"Red", "A", "MANAGER", 8, date "1971-06-25", 2100, NULL, 40);
1 row created.
SQL> insert into employees values(8,"White", "S", "TRAINER", 9, date "1972-05-26", 2200, NULL, 40);
1 row created.
SQL> insert into employees values(9,"Yellow", "C", "DIRECTOR",10, date "1973-04-27", 2300, NULL, 20);
1 row created.
SQL> insert into employees values(10,"Pink", "J", "SALESREP",null,date "1974-03-28", 2400, 0, 30);
1 row created.
SQL>
SQL>
SQL> select empno as odd_empno
2 , ename
3 from employees
4 where mod(empno,2) = 1;
ODD_EMPNO ENAME
---------- --------
1 Jason
3 Jord
5 Joe
7 Red
9 Yellow
SQL>
SQL>
SQL> drop table employees;
Table dropped.
SQL>
SQL>
MOD(8, 3)
SQL> select MOD(8, 3) from dual;
MOD(8,3)
----------
2
MOD(8, 4)
SQL> select MOD(8, 4) from dual;
MOD(8,4)
----------
0
MOD function in action
SQL>
SQL>
SQL>
SQL> -- create demo table
SQL> create table myTable(
2 id NUMBER(2),
3 value NUMBER(6,2)
4 )
5 /
Table created.
SQL>
SQL> -- prepare data
SQL> insert into myTable(ID, value)values (1,9)
2 /
1 row created.
SQL> insert into myTable(ID, value)values (2,2.11)
2 /
1 row created.
SQL> insert into myTable(ID, value)values (3,3.44)
2 /
1 row created.
SQL> insert into myTable(ID, value)values (4,-4.21)
2 /
1 row created.
SQL> insert into myTable(ID, value)values (5,10)
2 /
1 row created.
SQL> insert into myTable(ID, value)values (6,3)
2 /
1 row created.
SQL> insert into myTable(ID, value)values (7,-5.88)
2 /
1 row created.
SQL> insert into myTable(ID, value)values (8,123.45)
2 /
1 row created.
SQL> insert into myTable(ID, value)values (9,98.23)
2 /
1 row created.
SQL>
SQL> select * from myTable
2 /
ID VALUE
---------- ----------
1 9
2 2.11
3 3.44
4 -4.21
5 10
6 3
7 -5.88
8 123.45
9 98.23
9 rows selected.
SQL>
SQL> SELECT id, value, MOD(id,3)FROM myTable
2 /
ID VALUE MOD(ID,3)
---------- ---------- ----------
1 9 1
2 2.11 2
3 3.44 0
4 -4.21 1
5 10 2
6 3 0
7 -5.88 1
8 123.45 2
9 98.23 0
9 rows selected.
SQL>
SQL>
SQL>
SQL> -- clean the table
SQL> drop table myTable
2 /
Table dropped.
SQL>
SQL>
MOD(x, y) gets the remainder when x is divided by y.
The following example uses MOD() to display the remainder when 8 is divided by 3 and 4, respectively:
SQL>
SQL> SELECT MOD(8, 3), MOD(8, 4) FROM dual;
MOD(8,3) MOD(8,4)
---------- ----------
2 0
SQL>
select mod(8,3), mod(13,0)
SQL>
SQL>
SQL>
SQL> select mod(8,3), mod(13,0)
2 from dual;
MOD(8,3) MOD(13,0)
---------- ----------
2 13
SQL>
Use floor(), mod() and date calculation to show how many weeks and days an employee has been working here
SQL> create table emp
2 ( empno NUMBER(4) constraint E_PK primary key
3 , ename VARCHAR2(8)
4 , init VARCHAR2(5)
5 , job VARCHAR2(8)
6 , mgr NUMBER(4)
7 , bdate DATE
8 , sal NUMBER(6,2)
9 , comm NUMBER(6,2)
10 , deptno NUMBER(2) default 10
11 ) ;
Table created.
SQL> insert into emp values(1,"Tom","N", "Coder", 13,date "1965-12-17", 800 , NULL, 20);
1 row created.
SQL> insert into emp values(2,"Jack","JAM", "Tester",6,date "1961-02-20", 1600, 300, 30);
1 row created.
SQL> insert into emp values(3,"Wil","TF" , "Tester",6,date "1962-02-22", 1250, 500, 30);
1 row created.
SQL> insert into emp values(4,"Jane","JM", "Designer", 9,date "1967-04-02", 2975, NULL, 20);
1 row created.
SQL> insert into emp values(5,"Mary","P", "Tester",6,date "1956-09-28", 1250, 1400, 30);
1 row created.
SQL> insert into emp values(6,"Black","R", "Designer", 9,date "1963-11-01", 2850, NULL, 30);
1 row created.
SQL> insert into emp values(7,"Chris","AB", "Designer", 9,date "1965-06-09", 2450, NULL, 10);
1 row created.
SQL> insert into emp values(8,"Smart","SCJ", "Coder", 4,date "1959-11-26", 3000, NULL, 20);
1 row created.
SQL> insert into emp values(9,"Peter","CC", "Designer",NULL,date "1952-11-17", 5000, NULL, 10);
1 row created.
SQL> insert into emp values(10,"Take","JJ", "Tester",6,date "1968-09-28", 1500, 0, 30);
1 row created.
SQL> insert into emp values(11,"Ana","AA", "Coder", 8,date "1966-12-30", 1100, NULL, 20);
1 row created.
SQL> insert into emp values(12,"Jane","R", "Manager", 6,date "1969-12-03", 800 , NULL, 30);
1 row created.
SQL> insert into emp values(13,"Fake","MG", "Coder", 4,date "1959-02-13", 3000, NULL, 20);
1 row created.
SQL> insert into emp values(14,"Mike","TJA","Manager", 7,date "1962-01-23", 1300, NULL, 10);
1 row created.
SQL>
SQL> select ename
2 , floor( (sysdate-bdate)/7) as weeks
3 , floor(mod(sysdate-bdate,7)) as days
4 from emp
5 where deptno = 10;
ENAME WEEKS DAYS
-------- ---------- ----------
Chris 2315 5
Peter 2971 0
Mike 2491 6
SQL>
SQL> drop table emp;
Table dropped.
Use mod() function to get all event employee id
SQL>
SQL> create table emp
2 ( empno NUMBER(4) constraint E_PK primary key
3 , ename VARCHAR2(8)
4 , init VARCHAR2(5)
5 , job VARCHAR2(8)
6 , mgr NUMBER(4)
7 , bdate DATE
8 , sal NUMBER(6,2)
9 , comm NUMBER(6,2)
10 , deptno NUMBER(2) default 10
11 ) ;
Table created.
SQL> insert into emp values(1,"Tom","N", "Coder", 13,date "1965-12-17", 800 , NULL, 20);
1 row created.
SQL> insert into emp values(2,"Jack","JAM", "Tester",6,date "1961-02-20", 1600, 300, 30);
1 row created.
SQL> insert into emp values(3,"Wil","TF" , "Tester",6,date "1962-02-22", 1250, 500, 30);
1 row created.
SQL> insert into emp values(4,"Jane","JM", "Designer", 9,date "1967-04-02", 2975, NULL, 20);
1 row created.
SQL> insert into emp values(5,"Mary","P", "Tester",6,date "1956-09-28", 1250, 1400, 30);
1 row created.
SQL> insert into emp values(6,"Black","R", "Designer", 9,date "1963-11-01", 2850, NULL, 30);
1 row created.
SQL> insert into emp values(7,"Chris","AB", "Designer", 9,date "1965-06-09", 2450, NULL, 10);
1 row created.
SQL> insert into emp values(8,"Smart","SCJ", "Coder", 4,date "1959-11-26", 3000, NULL, 20);
1 row created.
SQL> insert into emp values(9,"Peter","CC", "Designer",NULL,date "1952-11-17", 5000, NULL, 10);
1 row created.
SQL> insert into emp values(10,"Take","JJ", "Tester",6,date "1968-09-28", 1500, 0, 30);
1 row created.
SQL> insert into emp values(11,"Ana","AA", "Coder", 8,date "1966-12-30", 1100, NULL, 20);
1 row created.
SQL> insert into emp values(12,"Jane","R", "Manager", 6,date "1969-12-03", 800 , NULL, 30);
1 row created.
SQL> insert into emp values(13,"Fake","MG", "Coder", 4,date "1959-02-13", 3000, NULL, 20);
1 row created.
SQL> insert into emp values(14,"Mike","TJA","Manager", 7,date "1962-01-23", 1300, NULL, 10);
1 row created.
SQL>
SQL> select empno as odd_empno
2 , ename
3 from emp
4 where mod(empno,2) = 1;
ODD_EMPNO ENAME
---------- --------
1 Tom
3 Wil
5 Mary
7 Chris
9 Peter
11 Ana
13 Fake
7 rows selected.
SQL>
SQL> drop table emp;
Table dropped.