Oracle PL/SQL Tutorial/Numerical Math Functions/MOD
Содержание
- 1 Combine case statement with mod function
- 2 List all employee with odd employee number
- 3 MOD(8, 3)
- 4 MOD(8, 4)
- 5 MOD function in action
- 6 MOD(x, y) gets the remainder when x is divided by y.
- 7 select mod(8,3), mod(13,0)
- 8 Use floor(), mod() and date calculation to show how many weeks and days an employee has been working here
- 9 Use mod() function to get all event employee id
Combine case statement with mod function
<source lang="sql">
SQL> SQL> SQL> create table employees(
2 empno NUMBER(4) 3 , ename VARCHAR2(8) 4 , init VARCHAR2(5) 5 , job VARCHAR2(8) 6 , mgr NUMBER(4) 7 , bdate DATE 8 , msal NUMBER(6,2) 9 , comm NUMBER(6,2) 10 , deptno NUMBER(2) ) ;
Table created. SQL> SQL> SQL> insert into employees values(1,"Jason", "N", "TRAINER", 2, date "1965-12-18", 800 , NULL, 10); 1 row created. SQL> insert into employees values(2,"Jerry", "J", "SALESREP",3, date "1966-11-19", 1600, 300, 10); 1 row created. SQL> insert into employees values(3,"Jord", "T" , "SALESREP",4, date "1967-10-21", 1700, 500, 20); 1 row created. SQL> insert into employees values(4,"Mary", "J", "MANAGER", 5, date "1968-09-22", 1800, NULL, 20); 1 row created. SQL> insert into employees values(5,"Joe", "P", "SALESREP",6, date "1969-08-23", 1900, 1400, 30); 1 row created. SQL> insert into employees values(6,"Black", "R", "MANAGER", 7, date "1970-07-24", 2000, NULL, 30); 1 row created. SQL> insert into employees values(7,"Red", "A", "MANAGER", 8, date "1971-06-25", 2100, NULL, 40); 1 row created. SQL> insert into employees values(8,"White", "S", "TRAINER", 9, date "1972-05-26", 2200, NULL, 40); 1 row created. SQL> insert into employees values(9,"Yellow", "C", "DIRECTOR",10, date "1973-04-27", 2300, NULL, 20); 1 row created. SQL> insert into employees values(10,"Pink", "J", "SALESREP",null,date "1974-03-28", 2400, 0, 30); 1 row created. SQL> SQL> SQL> select case mod(empno,2)
2 when 0 then "EVEN " 3 else "ODD " 4 end as empno 5 , sum(msal) 6 from employees 7 group by mod(empno,2);
EMPNO SUM(MSAL)
----------
ODD 8800 EVEN 10000 SQL> SQL> SQL> drop table employees; Table dropped. SQL> SQL></source>
List all employee with odd employee number
<source lang="sql">
SQL> SQL> SQL> create table employees(
2 empno NUMBER(4) 3 , ename VARCHAR2(8) 4 , init VARCHAR2(5) 5 , job VARCHAR2(8) 6 , mgr NUMBER(4) 7 , bdate DATE 8 , msal NUMBER(6,2) 9 , comm NUMBER(6,2) 10 , deptno NUMBER(2) ) ;
Table created. SQL> SQL> SQL> insert into employees values(1,"Jason", "N", "TRAINER", 2, date "1965-12-18", 800 , NULL, 10); 1 row created. SQL> insert into employees values(2,"Jerry", "J", "SALESREP",3, date "1966-11-19", 1600, 300, 10); 1 row created. SQL> insert into employees values(3,"Jord", "T" , "SALESREP",4, date "1967-10-21", 1700, 500, 20); 1 row created. SQL> insert into employees values(4,"Mary", "J", "MANAGER", 5, date "1968-09-22", 1800, NULL, 20); 1 row created. SQL> insert into employees values(5,"Joe", "P", "SALESREP",6, date "1969-08-23", 1900, 1400, 30); 1 row created. SQL> insert into employees values(6,"Black", "R", "MANAGER", 7, date "1970-07-24", 2000, NULL, 30); 1 row created. SQL> insert into employees values(7,"Red", "A", "MANAGER", 8, date "1971-06-25", 2100, NULL, 40); 1 row created. SQL> insert into employees values(8,"White", "S", "TRAINER", 9, date "1972-05-26", 2200, NULL, 40); 1 row created. SQL> insert into employees values(9,"Yellow", "C", "DIRECTOR",10, date "1973-04-27", 2300, NULL, 20); 1 row created. SQL> insert into employees values(10,"Pink", "J", "SALESREP",null,date "1974-03-28", 2400, 0, 30); 1 row created. SQL> SQL> SQL> select empno as odd_empno
2 , ename 3 from employees 4 where mod(empno,2) = 1; ODD_EMPNO ENAME
--------
1 Jason 3 Jord 5 Joe 7 Red 9 Yellow
SQL> SQL> SQL> drop table employees; Table dropped. SQL> SQL></source>
MOD(8, 3)
<source lang="sql">
SQL> select MOD(8, 3) from dual;
MOD(8,3)
2</source>
MOD(8, 4)
<source lang="sql">
SQL> select MOD(8, 4) from dual;
MOD(8,4)
0</source>
MOD function in action
<source lang="sql">
SQL> SQL> SQL> SQL> -- create demo table SQL> create table myTable(
2 id NUMBER(2), 3 value NUMBER(6,2) 4 ) 5 /
Table created. SQL> SQL> -- prepare data SQL> insert into myTable(ID, value)values (1,9)
2 /
1 row created. SQL> insert into myTable(ID, value)values (2,2.11)
2 /
1 row created. SQL> insert into myTable(ID, value)values (3,3.44)
2 /
1 row created. SQL> insert into myTable(ID, value)values (4,-4.21)
2 /
1 row created. SQL> insert into myTable(ID, value)values (5,10)
2 /
1 row created. SQL> insert into myTable(ID, value)values (6,3)
2 /
1 row created. SQL> insert into myTable(ID, value)values (7,-5.88)
2 /
1 row created. SQL> insert into myTable(ID, value)values (8,123.45)
2 /
1 row created. SQL> insert into myTable(ID, value)values (9,98.23)
2 /
1 row created. SQL> SQL> select * from myTable
2 / ID VALUE
----------
1 9 2 2.11 3 3.44 4 -4.21 5 10 6 3 7 -5.88 8 123.45 9 98.23
9 rows selected. SQL> SQL> SELECT id, value, MOD(id,3)FROM myTable
2 / ID VALUE MOD(ID,3)
---------- ----------
1 9 1 2 2.11 2 3 3.44 0 4 -4.21 1 5 10 2 6 3 0 7 -5.88 1 8 123.45 2 9 98.23 0
9 rows selected. SQL> SQL> SQL> SQL> -- clean the table SQL> drop table myTable
2 /
Table dropped. SQL> SQL></source>
MOD(x, y) gets the remainder when x is divided by y.
The following example uses MOD() to display the remainder when 8 is divided by 3 and 4, respectively:
<source lang="sql">
SQL> SQL> SELECT MOD(8, 3), MOD(8, 4) FROM dual;
MOD(8,3) MOD(8,4)
----------
2 0
SQL></source>
select mod(8,3), mod(13,0)
<source lang="sql">
SQL> SQL> SQL> SQL> select mod(8,3), mod(13,0)
2 from dual; MOD(8,3) MOD(13,0)
----------
2 13
SQL></source>
Use floor(), mod() and date calculation to show how many weeks and days an employee has been working here
<source lang="sql">
SQL> create table emp
2 ( empno NUMBER(4) constraint E_PK primary key 3 , ename VARCHAR2(8) 4 , init VARCHAR2(5) 5 , job VARCHAR2(8) 6 , mgr NUMBER(4) 7 , bdate DATE 8 , sal NUMBER(6,2) 9 , comm NUMBER(6,2) 10 , deptno NUMBER(2) default 10 11 ) ;
Table created. SQL> insert into emp values(1,"Tom","N", "Coder", 13,date "1965-12-17", 800 , NULL, 20); 1 row created. SQL> insert into emp values(2,"Jack","JAM", "Tester",6,date "1961-02-20", 1600, 300, 30); 1 row created. SQL> insert into emp values(3,"Wil","TF" , "Tester",6,date "1962-02-22", 1250, 500, 30); 1 row created. SQL> insert into emp values(4,"Jane","JM", "Designer", 9,date "1967-04-02", 2975, NULL, 20); 1 row created. SQL> insert into emp values(5,"Mary","P", "Tester",6,date "1956-09-28", 1250, 1400, 30); 1 row created. SQL> insert into emp values(6,"Black","R", "Designer", 9,date "1963-11-01", 2850, NULL, 30); 1 row created. SQL> insert into emp values(7,"Chris","AB", "Designer", 9,date "1965-06-09", 2450, NULL, 10); 1 row created. SQL> insert into emp values(8,"Smart","SCJ", "Coder", 4,date "1959-11-26", 3000, NULL, 20); 1 row created. SQL> insert into emp values(9,"Peter","CC", "Designer",NULL,date "1952-11-17", 5000, NULL, 10); 1 row created. SQL> insert into emp values(10,"Take","JJ", "Tester",6,date "1968-09-28", 1500, 0, 30); 1 row created. SQL> insert into emp values(11,"Ana","AA", "Coder", 8,date "1966-12-30", 1100, NULL, 20); 1 row created. SQL> insert into emp values(12,"Jane","R", "Manager", 6,date "1969-12-03", 800 , NULL, 30); 1 row created. SQL> insert into emp values(13,"Fake","MG", "Coder", 4,date "1959-02-13", 3000, NULL, 20); 1 row created. SQL> insert into emp values(14,"Mike","TJA","Manager", 7,date "1962-01-23", 1300, NULL, 10); 1 row created. SQL> SQL> select ename
2 , floor( (sysdate-bdate)/7) as weeks 3 , floor(mod(sysdate-bdate,7)) as days 4 from emp 5 where deptno = 10;
ENAME WEEKS DAYS
---------- ----------
Chris 2315 5 Peter 2971 0 Mike 2491 6 SQL> SQL> drop table emp; Table dropped.</source>
Use mod() function to get all event employee id
<source lang="sql">
SQL> SQL> create table emp
2 ( empno NUMBER(4) constraint E_PK primary key 3 , ename VARCHAR2(8) 4 , init VARCHAR2(5) 5 , job VARCHAR2(8) 6 , mgr NUMBER(4) 7 , bdate DATE 8 , sal NUMBER(6,2) 9 , comm NUMBER(6,2) 10 , deptno NUMBER(2) default 10 11 ) ;
Table created. SQL> insert into emp values(1,"Tom","N", "Coder", 13,date "1965-12-17", 800 , NULL, 20); 1 row created. SQL> insert into emp values(2,"Jack","JAM", "Tester",6,date "1961-02-20", 1600, 300, 30); 1 row created. SQL> insert into emp values(3,"Wil","TF" , "Tester",6,date "1962-02-22", 1250, 500, 30); 1 row created. SQL> insert into emp values(4,"Jane","JM", "Designer", 9,date "1967-04-02", 2975, NULL, 20); 1 row created. SQL> insert into emp values(5,"Mary","P", "Tester",6,date "1956-09-28", 1250, 1400, 30); 1 row created. SQL> insert into emp values(6,"Black","R", "Designer", 9,date "1963-11-01", 2850, NULL, 30); 1 row created. SQL> insert into emp values(7,"Chris","AB", "Designer", 9,date "1965-06-09", 2450, NULL, 10); 1 row created. SQL> insert into emp values(8,"Smart","SCJ", "Coder", 4,date "1959-11-26", 3000, NULL, 20); 1 row created. SQL> insert into emp values(9,"Peter","CC", "Designer",NULL,date "1952-11-17", 5000, NULL, 10); 1 row created. SQL> insert into emp values(10,"Take","JJ", "Tester",6,date "1968-09-28", 1500, 0, 30); 1 row created. SQL> insert into emp values(11,"Ana","AA", "Coder", 8,date "1966-12-30", 1100, NULL, 20); 1 row created. SQL> insert into emp values(12,"Jane","R", "Manager", 6,date "1969-12-03", 800 , NULL, 30); 1 row created. SQL> insert into emp values(13,"Fake","MG", "Coder", 4,date "1959-02-13", 3000, NULL, 20); 1 row created. SQL> insert into emp values(14,"Mike","TJA","Manager", 7,date "1962-01-23", 1300, NULL, 10); 1 row created. SQL> SQL> select empno as odd_empno
2 , ename 3 from emp 4 where mod(empno,2) = 1; ODD_EMPNO ENAME
--------
1 Tom 3 Wil 5 Mary 7 Chris 9 Peter 11 Ana 13 Fake
7 rows selected. SQL> SQL> drop table emp; Table dropped.</source>