SQL Server/T-SQL Tutorial/Transact SQL/Variable Select

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An alternate syntax for setting a variable"s value in a select list

SELECT @variable_name = column_specification


Assignment with a Subquery

4>
5>
6> CREATE TABLE employee(
7>    id          INTEGER NOT NULL PRIMARY KEY,
8>    first_name  VARCHAR(10),
9>    last_name   VARCHAR(10),
10>    salary      DECIMAL(10,2),
11>    start_Date  DATETIME,
12>    region      VARCHAR(10),
13>    city        VARCHAR(20),
14>    managerid   INTEGER
15> );
16> GO
1> INSERT INTO employee VALUES (1, "Jason" ,  "Martin", 5890,"2005-03-22","North","Vancouver",3);
2> GO
(1 rows affected)
1> INSERT INTO employee VALUES (2, "Alison",  "Mathews",4789,"2003-07-21","South","Utown",4);
2> GO
(1 rows affected)
1> INSERT INTO employee VALUES (3, "James" ,  "Smith",  6678,"2001-12-01","North","Paris",5);
2> GO
(1 rows affected)
1> INSERT INTO employee VALUES (4, "Celia" ,  "Rice",   5567,"2006-03-03","South","London",6);
2> GO
(1 rows affected)
1> INSERT INTO employee VALUES (5, "Robert",  "Black",  4467,"2004-07-02","East","Newton",7);
2> GO
(1 rows affected)
1> INSERT INTO employee VALUES (6, "Linda" ,  "Green" , 6456,"2002-05-19","East","Calgary",8);
2> GO
(1 rows affected)
1> INSERT INTO employee VALUES (7, "David" ,  "Larry",  5345,"2008-03-18","West","New York",9);
2> GO
(1 rows affected)
1> INSERT INTO employee VALUES (8, "James" ,  "Cat",    4234,"2007-07-17","West","Regina",9);
2> GO
(1 rows affected)
1> INSERT INTO employee VALUES (9, "Joan"  ,  "Act",    6123,"2001-04-16","North","Toronto",10);
2> GO
(1 rows affected)
1>
2> select * from employee;
3> GO
id          first_name last_name  salary       start_Date              region     city                 managerid
----------- ---------- ---------- ------------ ----------------------- ---------- -------------------- -----------
          1 Jason      Martin          5890.00 2005-03-22 00:00:00.000 North      Vancouver                      3
          2 Alison     Mathews         4789.00 2003-07-21 00:00:00.000 South      Utown                          4
          3 James      Smith           6678.00 2001-12-01 00:00:00.000 North      Paris                          5
          4 Celia      Rice            5567.00 2006-03-03 00:00:00.000 South      London                         6
          5 Robert     Black           4467.00 2004-07-02 00:00:00.000 East       Newton                         7
          6 Linda      Green           6456.00 2002-05-19 00:00:00.000 East       Calgary                        8
          7 David      Larry           5345.00 2008-03-18 00:00:00.000 West       New York                       9
          8 James      Cat             4234.00 2007-07-17 00:00:00.000 West       Regina                         9
          9 Joan       Act             6123.00 2001-04-16 00:00:00.000 North      Toronto                       10
(9 rows affected)
1>
2> DECLARE
3>   @ID int
4> SELECT
5>   @ID = 0
6> SELECT
7>   @ID =
8>  (
9>    SELECT
10>      ID
11>    FROM
12>      Employee
13>    WHERE
14>      ID = 1
15> )
16> SELECT
17>   @ID
18>
19>
20>
21> drop table employee;
22> GO
-----------
          1
(1 rows affected)
1>


Creating a Comma Delimited List using SELECT

5> CREATE TABLE employee(
6>    id          INTEGER NOT NULL PRIMARY KEY,
7>    first_name  VARCHAR(10),
8>    last_name   VARCHAR(10),
9>    salary      DECIMAL(10,2),
10>    start_Date  DATETIME,
11>     region      VARCHAR(10),
12>     city        VARCHAR(20)
13>  );
14>  GO
1> INSERT INTO employee VALUES (1, "Jason" ,  "Martin", 5890,"2005-03-22","North","Vancouver");
2> GO
(1 rows affected)
1>
2>
3> INSERT INTO employee VALUES (2, "Alison",  "Mathews",4789,"2003-07-21","South","Utown");
4> GO
(1 rows affected)
1>
2>
3> INSERT INTO employee VALUES (3, "James" ,  "Smith",  6678,"2001-12-01","North","Paris");
4> GO
(1 rows affected)
1>
2>
3> INSERT INTO employee VALUES (4, "Celia" ,  "Rice",   5567,"2006-03-03","South","London");
4> GO
(1 rows affected)
1>
2>
3> INSERT INTO employee VALUES (5, "Robert",  "Black",  4467,"2004-07-02","East","Newton");
4> GO
(1 rows affected)
1>
2>
3> INSERT INTO employee VALUES (6, "Linda" ,  "Green" , 6456,"2002-05-19","East","Calgary");
4> GO
(1 rows affected)
1>
2>
3> INSERT INTO employee VALUES (7, "David" ,  "Larry",  5345,"2008-03-18","West","New York");
4> GO
(1 rows affected)
1>
2>
3> INSERT INTO employee VALUES (8, "James" ,  "Cat",    4234,"2007-07-17","West","Regina");
4> GO
(1 rows affected)
1>
2>
3> INSERT INTO employee VALUES (9, "Joan"  ,  "Act",    6123,"2001-04-16","North","Toronto");
4> GO
(1 rows affected)
1>
2>
3>
4> select * from employee;
5> GO
id          first_name last_name  salary       start_Date              region     city
----------- ---------- ---------- ------------ ----------------------- ---------- --------------------
          1 Jason      Martin          5890.00 2005-03-22 00:00:00.000 North      Vancouver
          2 Alison     Mathews         4789.00 2003-07-21 00:00:00.000 South      Utown
          3 James      Smith           6678.00 2001-12-01 00:00:00.000 North      Paris
          4 Celia      Rice            5567.00 2006-03-03 00:00:00.000 South      London
          5 Robert     Black           4467.00 2004-07-02 00:00:00.000 East       Newton
          6 Linda      Green           6456.00 2002-05-19 00:00:00.000 East       Calgary
          7 David      Larry           5345.00 2008-03-18 00:00:00.000 West       New York
          8 James      Cat             4234.00 2007-07-17 00:00:00.000 West       Regina
          9 Joan       Act             6123.00 2001-04-16 00:00:00.000 North      Toronto
(9 rows affected)
1>
2>
3>
4> DECLARE @Shifts varchar(20)
5> SET @Shifts = ""
6> SELECT @Shifts = @Shifts + s.first_Name + ","
7> FROM employee s
8> ORDER BY s.start_Date;
9>
10> SELECT @Shifts;
11> GO
--------------------
Joan,James,Linda,Ali
(1 rows affected)
1>
2>
3>
4> drop table employee;
5> GO


Example of a Variable Not Updated Due to No Rows Being Returned

9> CREATE TABLE employee(
10>    id          INTEGER NOT NULL PRIMARY KEY,
11>    first_name  VARCHAR(10),
12>    last_name   VARCHAR(10),
13>    salary      DECIMAL(10,2),
14>    start_Date  DATETIME,
15>    region      VARCHAR(10),
16>    city        VARCHAR(20),
17>    managerid   INTEGER
18> );
19> GO
1> INSERT INTO employee VALUES (1, "Jason" ,  "Martin", 5890,"2005-03-22","North","Vancouver",3);
2> GO
(1 rows affected)
1> INSERT INTO employee VALUES (2, "Alison",  "Mathews",4789,"2003-07-21","South","Utown",4);
2> GO
(1 rows affected)
1> INSERT INTO employee VALUES (3, "James" ,  "Smith",  6678,"2001-12-01","North","Paris",5);
2> GO
(1 rows affected)
1> INSERT INTO employee VALUES (4, "Celia" ,  "Rice",   5567,"2006-03-03","South","London",6);
2> GO
(1 rows affected)
1> INSERT INTO employee VALUES (5, "Robert",  "Black",  4467,"2004-07-02","East","Newton",7);
2> GO
(1 rows affected)
1> INSERT INTO employee VALUES (6, "Linda" ,  "Green" , 6456,"2002-05-19","East","Calgary",8);
2> GO
(1 rows affected)
1> INSERT INTO employee VALUES (7, "David" ,  "Larry",  5345,"2008-03-18","West","New York",9);
2> GO
(1 rows affected)
1> INSERT INTO employee VALUES (8, "James" ,  "Cat",    4234,"2007-07-17","West","Regina",9);
2> GO
(1 rows affected)
1> INSERT INTO employee VALUES (9, "Joan"  ,  "Act",    6123,"2001-04-16","North","Toronto",10);
2> GO
(1 rows affected)
1>
2> select * from employee;
3> GO
id          first_name last_name  salary       start_Date              region     city                 managerid
----------- ---------- ---------- ------------ ----------------------- ---------- -------------------- -----------
          1 Jason      Martin          5890.00 2005-03-22 00:00:00.000 North      Vancouver                      3
          2 Alison     Mathews         4789.00 2003-07-21 00:00:00.000 South      Utown                          4
          3 James      Smith           6678.00 2001-12-01 00:00:00.000 North      Paris                          5
          4 Celia      Rice            5567.00 2006-03-03 00:00:00.000 South      London                         6
          5 Robert     Black           4467.00 2004-07-02 00:00:00.000 East       Newton                         7
          6 Linda      Green           6456.00 2002-05-19 00:00:00.000 East       Calgary                        8
          7 David      Larry           5345.00 2008-03-18 00:00:00.000 West       New York                       9
          8 James      Cat             4234.00 2007-07-17 00:00:00.000 West       Regina                         9
          9 Joan       Act             6123.00 2001-04-16 00:00:00.000 North      Toronto                       10
(9 rows affected)
1>
2>
3>
4> DECLARE
5>   @ID int
6> SELECT
7>   @ID = 0
8> SELECT
9>   @ID = ID
10>    FROM
11>      Employee
12>    WHERE
13>      ID = 1
14> SELECT
15>   @ID
16>
17>
18> drop table employee;
19> GO
-----------
          1
(1 rows affected)
1>


multiple variables can be assigned values in a single operation.

6>
7> DECLARE @MyNumber1 Int, @MyNumber2 Int, @MyResult1 Int, @MyResult2 Int
8> SELECT @MyNumber1 = 144, @MyNumber2 = 121
9> -- Assign the function result to the variable:
10> SELECT @MyResult1 = SQRT(@MyNumber1), @MyResult2 = SQRT(@MyNumber2)
11> -- Return the variable value
12> SELECT @MyResult1, @MyResult2
13> GO
----------- -----------
         12          11
(1 rows affected)


Syntax for Variable Assignment with the SELECT Statement

SELECT {@local_variable = expression } [,...n]


Use select to output a variable

3> CREATE TABLE authors(
4>    au_id          varchar(11),
5>    au_lname       varchar(40)       NOT NULL,
6>    au_fname       varchar(20)       NOT NULL,
7>    phone          char(12)          NOT NULL DEFAULT ("UNKNOWN"),
8>    address        varchar(40)           NULL,
9>    city           varchar(20)           NULL,
10>    state          char(2)               NULL,
11>    zip            char(5)               NULL,
12>    contract       bit               NOT NULL
13> )
14> GO
1> insert authors values("1",  "Joe",   "Abra",   "111 111-1111", "6 St.", "Berkeley",  "CA", "11111", 1)
2> insert authors values("2",  "Jack",  "Majo",   "222 222-2222", "3 St.", "Oakland" ,  "CA", "22222", 1)
3> insert authors values("3",  "Pink",  "Cherry", "333 333-3333", "5 Ln.", "Vancouver", "BC", "33333", 1)
4> insert authors values("4",  "Blue",  "Albert", "444 444-4444", "7 Av.", "Vancouver", "BC", "44444", 1)
5> insert authors values("5",  "Red",   "Anne",   "555 555-5555", "6 Av.", "Regina",    "SK", "55555", 1)
6> insert authors values("6",  "Black", "Michel", "666 666-6666", "3 Pl.", "Regina",    "SK", "66666", 1)
7> insert authors values("7",  "White", "Sylvia", "777 777-7777", "1 Pl.", "Rockville", "MD", "77777", 1)
8> insert authors values("8",  "Yellow","Heather","888 888-8888", "3 Pu",  "Vacaville", "CA", "88888", 0)
9> insert authors values("9",  "Gold",  "Dep",    "999 999-9999", "5 Av.", "Oakland",   "CA", "99999", 0)
10> insert authors values("10", "Siler", "Dean",   "000 000-0000", "4 Av.", "Oakland",   "CA", "00000", 1)
11> GO
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
1>
2>
3> DECLARE @firstname varchar(20)
4> SELECT @firstname = au_fname
5> FROM authors
6> WHERE au_lname = "Greene"
7>
8> SELECT @firstname  
9> SELECT @firstname = au_fname
10> FROM authors
11> WHERE au_lname = "Ben-Gan"
12> SELECT @firstname
13> GO
--------------------
NULL
(1 rows affected)
--------------------
NULL
(1 rows affected)
1>
2> drop table authors;
3> GO


Using SELECT to Assign Variables

3> DECLARE @MyNumber1 Int, @MyNumber2 Int, @MyResult1 Int, @MyResult2 Int
4> SELECT @MyNumber1 = 144, @MyNumber2 = 121
5> 
6> SELECT @MyResult1 = SQRT(@MyNumber1), @MyResult2 = SQRT(@MyNumber2)
7> 
8> SELECT @MyResult1, @MyResult2
9> GO
----------- -----------
         12          11
(1 rows affected)