SQL Server/T-SQL Tutorial/String Functions/PATINDEX

Материал из SQL эксперт
Перейти к: навигация, поиск

Finding the Start Position of a String Within Another String Using Wildcards

   <source lang="sql">

4> 5> CREATE TABLE employee( 6> id INTEGER NOT NULL PRIMARY KEY, 7> first_name VARCHAR(10), 8> last_name VARCHAR(10), 9> salary DECIMAL(10,2), 10> start_Date DATETIME, 11> region VARCHAR(10), 12> city VARCHAR(20), 13> managerid INTEGER 14> ); 15> GO 1> INSERT INTO employee VALUES (1, "Jason" , "Martin", 5890,"2005-03-22","North","Vancouver",3); 2> GO (1 rows affected) 1> INSERT INTO employee VALUES (2, "Alison", "Mathews",4789,"2003-07-21","South","Utown",4); 2> GO (1 rows affected) 1> INSERT INTO employee VALUES (3, "James" , "Smith", 6678,"2001-12-01","North","Paris",5); 2> GO (1 rows affected) 1> INSERT INTO employee VALUES (4, "Celia" , "Rice", 5567,"2006-03-03","South","London",6); 2> GO (1 rows affected) 1> INSERT INTO employee VALUES (5, "Robert", "Black", 4467,"2004-07-02","East","Newton",7); 2> GO (1 rows affected) 1> INSERT INTO employee VALUES (6, "Linda" , "Green" , 6456,"2002-05-19","East","Calgary",8); 2> GO (1 rows affected) 1> INSERT INTO employee VALUES (7, "David" , "Larry", 5345,"2008-03-18","West","New York",9); 2> GO (1 rows affected) 1> INSERT INTO employee VALUES (8, "James" , "Cat", 4234,"2007-07-17","West","Regina",9); 2> GO (1 rows affected) 1> INSERT INTO employee VALUES (9, "Joan" , "Act", 6123,"2001-04-16","North","Toronto",10); 2> GO (1 rows affected) 1> 2> select * from employee; 3> GO id first_name last_name salary start_Date region city managerid

---------- ---------- ------------ ----------------------- ---------- -------------------- ----------- 
         1 Jason      Martin          5890.00 2005-03-22 00:00:00.000 North      Vancouver                      3
         2 Alison     Mathews         4789.00 2003-07-21 00:00:00.000 South      Utown                          4
         3 James      Smith           6678.00 2001-12-01 00:00:00.000 North      Paris                          5
         4 Celia      Rice            5567.00 2006-03-03 00:00:00.000 South      London                         6
         5 Robert     Black           4467.00 2004-07-02 00:00:00.000 East       Newton                         7
         6 Linda      Green           6456.00 2002-05-19 00:00:00.000 East       Calgary                        8
         7 David      Larry           5345.00 2008-03-18 00:00:00.000 West       New York                       9
         8 James      Cat             4234.00 2007-07-17 00:00:00.000 West       Regina                         9
         9 Joan       Act             6123.00 2001-04-16 00:00:00.000 North      Toronto                       10

(9 rows affected) 1> 2> 3> SELECT ID, first_name 4> FROM employee 5> WHERE PATINDEX("%J%", first_name) > 0 6> GO ID first_name

---------- 
         1 Jason
         3 James
         8 James
         9 Joan

(4 rows affected) 1> 2> 3> 4> 5> drop table employee; 6> GO</source>


PATINDEX searches for a pattern of characters within a string.

   <source lang="sql">

PATINDEX is not case sensitive. PATINDEX returns 0 if no match is found. PATINDEX allows the handling of wildcards, unlike CHARINDEX. 12> SELECT PATINDEX("%sqle%","This is www.sqle.ru") 13> 14> GO 

        13

(1 rows affected)</source>


SELECT PATINDEX("%M_rs%", "The stars near Mars are far from ours")

   <source lang="sql">

4> SELECT PATINDEX("%M_rs%", "The stars near Mars are far from ours") 5> GO 

        16

(1 rows affected) 1></source>


select PATINDEX("%v_r%", "SQL Server")

   <source lang="sql">

2> 3> select PATINDEX("%v_r%", "SQL Server") 4> GO 

         8

(1 rows affected)</source>


WHERE PATINDEX("%computer[^s]%", notes) > 0

   <source lang="sql">

4> CREATE TABLE titles( 5> title_id varchar(20), 6> title varchar(80) NOT NULL, 7> type char(12) NOT NULL, 8> pub_id char(4) NULL, 9> price money NULL, 10> advance money NULL, 11> royalty int NULL, 12> ytd_sales int NULL, 13> notes varchar(200) NULL, 14> pubdate datetime NOT NULL 15> ) 16> GO 1> 2> insert titles values ("1", "Secrets", "popular_comp", "1389", $20.00, $8000.00, 10, 4095,"Note 1","06/12/94") 3> insert titles values ("2", "The", "business", "1389", $19.99, $5000.00, 10, 4095,"Note 2","06/12/91") 4> insert titles values ("3", "Emotional", "psychology", "0736", $7.99, $4000.00, 10, 3336,"Note 3","06/12/91") 5> insert titles values ("4", "Prolonged", "psychology", "0736", $19.99, $2000.00, 10, 4072,"Note 4","06/12/91") 6> insert titles values ("5", "With", "business", "1389", $11.95, $5000.00, 10, 3876,"Note 5","06/09/91") 7> insert titles values ("6", "Valley", "mod_cook", "0877", $19.99, $0.00, 12, 2032,"Note 6","06/09/91") 8> insert titles values ("7", "Any?", "trad_cook", "0877", $14.99, $8000.00, 10, 4095,"Note 7","06/12/91") 9> insert titles values ("8", "Fifty", "trad_cook", "0877", $11.95, $4000.00, 14, 1509,"Note 8","06/12/91") 10> GO (1 rows affected) (1 rows affected) (1 rows affected) (1 rows affected) (1 rows affected) (1 rows affected) (1 rows affected) (1 rows affected)

1> UPDATE titles 2> SET notes=STUFF(notes, PATINDEX("%computer[^s]%", notes), 3> DATALENGTH("computer"), "Hi-Tech Computers") 4> WHERE PATINDEX("%computer[^s]%", notes) > 0 5> GO (0 rows affected) 1> 2> 3> drop table titles; 4> GO</source>

Источник — «http://sqle.ru/index.php?title=SQL_Server/T-SQL_Tutorial/String_Functions/PATINDEX&oldid=6247»