SQL Server/T-SQL Tutorial/Query/ALL
Содержание
- 1 A SELECT statement that returns all rows
- 2 Finding the First Order for Each Customer Using the ALL Predicate
- 3 Finding the Last Row in Employee Using ALL
- 4 Finding the Most Recently Shipped Employee Using ALL
- 5 Finding the Most Recently Shipped Employee Using ALL with NULL Handling
- 6 How the ALL keyword works
- 7 The ALL operator evaluates to true if the evaluation of the table column in the inner query returns all values of that column.
- 8 The ALL predicate is more restrictive, in that all of the values inside the subquery must satisfy the comparison condition.
A SELECT statement that returns all rows
<source lang="sql">
ALL keyword causes all rows matching the search condition to be included in the result set. To use the ALL keyword, code it immediately after the SELECT keyword. 7> 8> 9> create table Bankers( 10> BankerID Integer, 11> BankerName VARCHAR(20), 12> BankerContactLName VARCHAR(20), 13> BankerContactFName VARCHAR(20), 14> BankerCity VARCHAR(20), 15> BankerState VARCHAR(20), 16> BankerZipCode VARCHAR(20), 17> BankerPhone VARCHAR(20) 18> ) 19> GO 1> 2> insert into Bankers values (1, "ABC Inc.","Joe","Smith","Vancouver","BC","11111","111-111-1111"); 3> GO (1 rows affected) 1> insert into Bankers values (2, "DEF Inc.","Red","Rice", "New York", "DE","22222","222-222-2222"); 2> GO (1 rows affected) 1> insert into Bankers values (3, "HJI Inc.","Kit","Cat", "Paris", "CA","33333","333-333-3333"); 2> GO (1 rows affected) 1> insert into Bankers values (4, "QWE Inc.","Git","Black","Regina", "ER","44444","444-444-4444"); 2> GO (1 rows affected) 1> insert into Bankers values (5, "RTY Inc.","Wil","Lee", "Toronto", "YU","55555","555-555-5555"); 2> GO (1 rows affected) 1> insert into Bankers values (6, "YUI Inc.","Ted","Larry","Calgary", "TY","66666","666-666-6666"); 2> GO (1 rows affected) 1> insert into Bankers values (7, "OIP Inc.","Yam","Act", "San Franc","FG","77777","777-777-7777"); 2> GO (1 rows affected) 1> insert into Bankers values (8, "SAD Inc.","Hit","Eat", "Orland", "PO","88888","888-888-8888"); 2> GO (1 rows affected) 1> insert into Bankers values (9, "DFG Inc.","Sad","Lee", "Wisler", "PL","99999","999-999-9999"); 2> GO (1 rows affected) 1> insert into Bankers values (0, "GHJ Inc.","Bit","Lee", "Ticker", "MN","00000","000-000-0000"); 2> GO (1 rows affected) 1> 2> SELECT ALL BankerCity, BankerState 3> FROM Bankers 4> ORDER BY BankerCity 5> GO BankerCity BankerState
--------------------
Calgary TY New York DE Orland PO Paris CA Regina ER San Franc FG Ticker MN Toronto YU Vancouver BC Wisler PL (10 rows affected) 1> 2> 3> drop table Bankers; 4> GO 1> 2> 3> 4></source>
Finding the First Order for Each Customer Using the ALL Predicate
<source lang="sql">
4> 5> CREATE TABLE employee( 6> id INTEGER NOT NULL PRIMARY KEY, 7> first_name VARCHAR(10), 8> last_name VARCHAR(10), 9> salary DECIMAL(10,2), 10> start_Date DATETIME, 11> region VARCHAR(10), 12> city VARCHAR(20), 13> managerid INTEGER 14> ); 15> GO 1> INSERT INTO employee VALUES (1, "Jason" , "Martin", 5890,"2005-03-22","North","Vancouver",3); 2> GO (1 rows affected) 1> INSERT INTO employee VALUES (2, "Alison", "Mathews",4789,"2003-07-21","South","Utown",4); 2> GO (1 rows affected) 1> INSERT INTO employee VALUES (3, "James" , "Smith", 6678,"2001-12-01","North","Paris",5); 2> GO (1 rows affected) 1> INSERT INTO employee VALUES (4, "Celia" , "Rice", 5567,"2006-03-03","South","London",6); 2> GO (1 rows affected) 1> INSERT INTO employee VALUES (5, "Robert", "Black", 4467,"2004-07-02","East","Newton",7); 2> GO (1 rows affected) 1> INSERT INTO employee VALUES (6, "Linda" , "Green" , 6456,"2002-05-19","East","Calgary",8); 2> GO (1 rows affected) 1> INSERT INTO employee VALUES (7, "David" , "Larry", 5345,"2008-03-18","West","New York",9); 2> GO (1 rows affected) 1> INSERT INTO employee VALUES (8, "James" , "Cat", 4234,"2007-07-17","West","Regina",9); 2> GO (1 rows affected) 1> INSERT INTO employee VALUES (9, "Joan" , "Act", 6123,"2001-04-16","North","Toronto",10); 2> GO (1 rows affected) 1> 2> select * from employee; 3> GO id first_name last_name salary start_Date region city managerid
---------- ---------- ------------ ----------------------- ---------- -------------------- -----------
1 Jason Martin 5890.00 2005-03-22 00:00:00.000 North Vancouver 3
2 Alison Mathews 4789.00 2003-07-21 00:00:00.000 South Utown 4
3 James Smith 6678.00 2001-12-01 00:00:00.000 North Paris 5
4 Celia Rice 5567.00 2006-03-03 00:00:00.000 South London 6
5 Robert Black 4467.00 2004-07-02 00:00:00.000 East Newton 7
6 Linda Green 6456.00 2002-05-19 00:00:00.000 East Calgary 8
7 David Larry 5345.00 2008-03-18 00:00:00.000 West New York 9
8 James Cat 4234.00 2007-07-17 00:00:00.000 West Regina 9
9 Joan Act 6123.00 2001-04-16 00:00:00.000 North Toronto 10
(9 rows affected) 1> 2> 3> 4> SELECT 5> O1.* 6> FROM 7> Employee AS O1 8> WHERE 9> O1.ID <= ALL 10> ( 11> SELECT 12> O2.ID 13> FROM 14> Employee AS O2 15> WHERE 16> O2.ID = O1.ID 17> ) 18> 19> 20> drop table employee; 21> GO id first_name last_name salary start_Date region city managerid
---------- ---------- ------------ ----------------------- ---------- -------------------- -----------
1 Jason Martin 5890.00 2005-03-22 00:00:00.000 North Vancouver 3
2 Alison Mathews 4789.00 2003-07-21 00:00:00.000 South Utown 4
3 James Smith 6678.00 2001-12-01 00:00:00.000 North Paris 5
4 Celia Rice 5567.00 2006-03-03 00:00:00.000 South London 6
5 Robert Black 4467.00 2004-07-02 00:00:00.000 East Newton 7
6 Linda Green 6456.00 2002-05-19 00:00:00.000 East Calgary 8
7 David Larry 5345.00 2008-03-18 00:00:00.000 West New York 9
8 James Cat 4234.00 2007-07-17 00:00:00.000 West Regina 9
9 Joan Act 6123.00 2001-04-16 00:00:00.000 North Toronto 10
(9 rows affected)</source>
Finding the Last Row in Employee Using ALL
<source lang="sql">
3> 4> CREATE TABLE employee( 5> id INTEGER NOT NULL PRIMARY KEY, 6> first_name VARCHAR(10), 7> last_name VARCHAR(10), 8> salary DECIMAL(10,2), 9> start_Date DATETIME, 10> region VARCHAR(10), 11> city VARCHAR(20), 12> managerid INTEGER 13> ); 14> GO 1> INSERT INTO employee VALUES (1, "Jason" , "Martin", 5890,"2005-03-22","North","Vancouver",3); 2> GO (1 rows affected) 1> INSERT INTO employee VALUES (2, "Alison", "Mathews",4789,"2003-07-21","South","Utown",4); 2> GO (1 rows affected) 1> INSERT INTO employee VALUES (3, "James" , "Smith", 6678,"2001-12-01","North","Paris",5); 2> GO (1 rows affected) 1> INSERT INTO employee VALUES (4, "Celia" , "Rice", 5567,"2006-03-03","South","London",6); 2> GO (1 rows affected) 1> INSERT INTO employee VALUES (5, "Robert", "Black", 4467,"2004-07-02","East","Newton",7); 2> GO (1 rows affected) 1> INSERT INTO employee VALUES (6, "Linda" , "Green" , 6456,"2002-05-19","East","Calgary",8); 2> GO (1 rows affected) 1> INSERT INTO employee VALUES (7, "David" , "Larry", 5345,"2008-03-18","West","New York",9); 2> GO (1 rows affected) 1> INSERT INTO employee VALUES (8, "James" , "Cat", 4234,"2007-07-17","West","Regina",9); 2> GO (1 rows affected) 1> INSERT INTO employee VALUES (9, "Joan" , "Act", 6123,"2001-04-16","North","Toronto",10); 2> GO (1 rows affected) 1> 2> select * from employee; 3> GO id first_name last_name salary start_Date region city managerid
---------- ---------- ------------ ----------------------- ---------- -------------------- -----------
1 Jason Martin 5890.00 2005-03-22 00:00:00.000 North Vancouver 3
2 Alison Mathews 4789.00 2003-07-21 00:00:00.000 South Utown 4
3 James Smith 6678.00 2001-12-01 00:00:00.000 North Paris 5
4 Celia Rice 5567.00 2006-03-03 00:00:00.000 South London 6
5 Robert Black 4467.00 2004-07-02 00:00:00.000 East Newton 7
6 Linda Green 6456.00 2002-05-19 00:00:00.000 East Calgary 8
7 David Larry 5345.00 2008-03-18 00:00:00.000 West New York 9
8 James Cat 4234.00 2007-07-17 00:00:00.000 West Regina 9
9 Joan Act 6123.00 2001-04-16 00:00:00.000 North Toronto 10
(9 rows affected) 1> 2> 3> 4> SELECT 5> * 6> FROM 7> Employee 8> WHERE 9> ID >= ALL 10> ( 11> SELECT 12> ID 13> FROM 14> Employee 15> ) 16> 17> 18> drop table employee; 19> GO id first_name last_name salary start_Date region city managerid
---------- ---------- ------------ ----------------------- ---------- -------------------- -----------
9 Joan Act 6123.00 2001-04-16 00:00:00.000 North Toronto 10
(1 rows affected)</source>
Finding the Most Recently Shipped Employee Using ALL
<source lang="sql">
3> 4> CREATE TABLE employee( 5> id INTEGER NOT NULL PRIMARY KEY, 6> first_name VARCHAR(10), 7> last_name VARCHAR(10), 8> salary DECIMAL(10,2), 9> start_Date DATETIME, 10> region VARCHAR(10), 11> city VARCHAR(20), 12> managerid INTEGER 13> ); 14> GO 1> INSERT INTO employee VALUES (1, "Jason" , "Martin", 5890,"2005-03-22","North","Vancouver",3); 2> GO (1 rows affected) 1> INSERT INTO employee VALUES (2, "Alison", "Mathews",4789,"2003-07-21","South","Utown",4); 2> GO (1 rows affected) 1> INSERT INTO employee VALUES (3, "James" , "Smith", 6678,"2001-12-01","North","Paris",5); 2> GO (1 rows affected) 1> INSERT INTO employee VALUES (4, "Celia" , "Rice", 5567,"2006-03-03","South","London",6); 2> GO (1 rows affected) 1> INSERT INTO employee VALUES (5, "Robert", "Black", 4467,"2004-07-02","East","Newton",7); 2> GO (1 rows affected) 1> INSERT INTO employee VALUES (6, "Linda" , "Green" , 6456,"2002-05-19","East","Calgary",8); 2> GO (1 rows affected) 1> INSERT INTO employee VALUES (7, "David" , "Larry", 5345,"2008-03-18","West","New York",9); 2> GO (1 rows affected) 1> INSERT INTO employee VALUES (8, "James" , "Cat", 4234,"2007-07-17","West","Regina",9); 2> GO (1 rows affected) 1> INSERT INTO employee VALUES (9, "Joan" , "Act", 6123,"2001-04-16","North","Toronto",10); 2> GO (1 rows affected) 1> 2> select * from employee; 3> GO id first_name last_name salary start_Date region city managerid
---------- ---------- ------------ ----------------------- ---------- -------------------- -----------
1 Jason Martin 5890.00 2005-03-22 00:00:00.000 North Vancouver 3
2 Alison Mathews 4789.00 2003-07-21 00:00:00.000 South Utown 4
3 James Smith 6678.00 2001-12-01 00:00:00.000 North Paris 5
4 Celia Rice 5567.00 2006-03-03 00:00:00.000 South London 6
5 Robert Black 4467.00 2004-07-02 00:00:00.000 East Newton 7
6 Linda Green 6456.00 2002-05-19 00:00:00.000 East Calgary 8
7 David Larry 5345.00 2008-03-18 00:00:00.000 West New York 9
8 James Cat 4234.00 2007-07-17 00:00:00.000 West Regina 9
9 Joan Act 6123.00 2001-04-16 00:00:00.000 North Toronto 10
(9 rows affected) 1> 2> 3> 4> SELECT 5> * 6> FROM 7> Employee 8> WHERE 9> Start_Date >= ALL( 10> SELECT 11> Start_Date 12> FROM 13> Employee 14> ) 15> 16> 17> drop table employee; 18> GO id first_name last_name salary start_Date region city managerid
---------- ---------- ------------ ----------------------- ---------- -------------------- -----------
7 David Larry 5345.00 2008-03-18 00:00:00.000 West New York 9
(1 rows affected) 1></source>
Finding the Most Recently Shipped Employee Using ALL with NULL Handling
<source lang="sql">
5> CREATE TABLE employee( 6> id INTEGER NOT NULL PRIMARY KEY, 7> first_name VARCHAR(10), 8> last_name VARCHAR(10), 9> salary DECIMAL(10,2), 10> start_Date DATETIME, 11> region VARCHAR(10), 12> city VARCHAR(20), 13> managerid INTEGER 14> ); 15> GO 1> INSERT INTO employee VALUES (1, "Jason" , "Martin", 5890,"2005-03-22","North","Vancouver",3); 2> GO (1 rows affected) 1> INSERT INTO employee VALUES (2, "Alison", "Mathews",4789,"2003-07-21","South","Utown",4); 2> GO (1 rows affected) 1> INSERT INTO employee VALUES (3, "James" , "Smith", 6678,"2001-12-01","North","Paris",5); 2> GO (1 rows affected) 1> INSERT INTO employee VALUES (4, "Celia" , "Rice", 5567,"2006-03-03","South","London",6); 2> GO (1 rows affected) 1> INSERT INTO employee VALUES (5, "Robert", "Black", 4467,"2004-07-02","East","Newton",7); 2> GO (1 rows affected) 1> INSERT INTO employee VALUES (6, "Linda" , "Green" , 6456,"2002-05-19","East","Calgary",8); 2> GO (1 rows affected) 1> INSERT INTO employee VALUES (7, "David" , "Larry", 5345,"2008-03-18","West","New York",9); 2> GO (1 rows affected) 1> INSERT INTO employee VALUES (8, "James" , "Cat", 4234,"2007-07-17","West","Regina",9); 2> GO (1 rows affected) 1> INSERT INTO employee VALUES (9, "Joan" , "Act", 6123,"2001-04-16","North","Toronto",10); 2> GO (1 rows affected) 1> 2> select * from employee; 3> GO id first_name last_name salary start_Date region city managerid
---------- ---------- ------------ ----------------------- ---------- -------------------- -----------
1 Jason Martin 5890.00 2005-03-22 00:00:00.000 North Vancouver 3
2 Alison Mathews 4789.00 2003-07-21 00:00:00.000 South Utown 4
3 James Smith 6678.00 2001-12-01 00:00:00.000 North Paris 5
4 Celia Rice 5567.00 2006-03-03 00:00:00.000 South London 6
5 Robert Black 4467.00 2004-07-02 00:00:00.000 East Newton 7
6 Linda Green 6456.00 2002-05-19 00:00:00.000 East Calgary 8
7 David Larry 5345.00 2008-03-18 00:00:00.000 West New York 9
8 James Cat 4234.00 2007-07-17 00:00:00.000 West Regina 9
9 Joan Act 6123.00 2001-04-16 00:00:00.000 North Toronto 10
(9 rows affected) 1> 2> 3> SELECT 4> * 5> FROM 6> Employee 7> WHERE 8> Start_Date >= ALL 9> ( 10> SELECT 11> Start_Date 12> FROM 13> Employee 14> WHERE 15> Start_Date IS NOT NULL 16> ) 17> 18> 19> 20> drop table employee; 21> GO id first_name last_name salary start_Date region city managerid
---------- ---------- ------------ ----------------------- ---------- -------------------- -----------
7 David Larry 5345.00 2008-03-18 00:00:00.000 West New York 9
(1 rows affected)</source>
How the ALL keyword works
<source lang="sql">
Condition Equivalent expression x > ALL (1, 2) x > 2 x < ALL (1, 2) x < 1 x = ALL (1, 2) (x = 1) AND (x = 2) x <> ALL (1, 2) (x <> 1) AND (x <> 2)
14>
15>
16>
17> create table Billings (
18> BankerID INTEGER,
19> BillingNumber INTEGER,
20> BillingDate datetime,
21> BillingTotal INTEGER,
22> TermsID INTEGER,
23> BillingDueDate datetime ,
24> PaymentTotal INTEGER,
25> CreditTotal INTEGER
26>
27> );
28> GO
1>
2> INSERT INTO Billings VALUES (1, 1, "2005-01-22", 165, 1,"2005-04-22",123,321);
3> GO
(1 rows affected)
1> INSERT INTO Billings VALUES (2, 2, "2001-02-21", 165, 1,"2002-02-22",123,321);
2> GO
(1 rows affected)
1> INSERT INTO Billings VALUES (3, 3, "2003-05-02", 165, 1,"2005-04-12",123,321);
2> GO
(1 rows affected)
1> INSERT INTO Billings VALUES (4, 4, "1999-03-12", 165, 1,"2005-04-18",123,321);
2> GO
(1 rows affected)
1> INSERT INTO Billings VALUES (5, 5, "2000-04-23", 165, 1,"2005-04-17",123,321);
2> GO
(1 rows affected)
1> INSERT INTO Billings VALUES (6, 6, "2001-06-14", 165, 1,"2005-04-18",123,321);
2> GO
(1 rows affected)
1> INSERT INTO Billings VALUES (7, 7, "2002-07-15", 165, 1,"2005-04-19",123,321);
2> GO
(1 rows affected)
1> INSERT INTO Billings VALUES (8, 8, "2003-08-16", 165, 1,"2005-04-20",123,321);
2> GO
(1 rows affected)
1> INSERT INTO Billings VALUES (9, 9, "2004-09-17", 165, 1,"2005-04-21",123,321);
2> GO
(1 rows affected)
1> INSERT INTO Billings VALUES (0, 0, "2005-10-18", 165, 1,"2005-04-22",123,321);
2> GO
(1 rows affected)
1>
2>
3>
4> create table Bankers(
5> BankerID Integer,
6> BankerName VARCHAR(20),
7> BankerContactLName VARCHAR(20),
8> BankerContactFName VARCHAR(20),
9> BankerCity VARCHAR(20),
10> BankerState VARCHAR(20),
11> BankerZipCode VARCHAR(20),
12> BankerPhone VARCHAR(20)
13> )
14> GO
1>
2> insert into Bankers values (1, "ABC Inc.","Joe","Smith","Vancouver","BC","11111","111-111-1111");
3> GO
(1 rows affected)
1> insert into Bankers values (2, "DEF Inc.","Red","Rice", "New York", "DE","22222","222-222-2222");
2> GO
(1 rows affected)
1> insert into Bankers values (3, "HJI Inc.","Kit","Cat", "Paris", "CA","33333","333-333-3333");
2> GO
(1 rows affected)
1> insert into Bankers values (4, "QWE Inc.","Git","Black","Regina", "ER","44444","444-444-4444");
2> GO
(1 rows affected)
1> insert into Bankers values (5, "RTY Inc.","Wil","Lee", "Toronto", "YU","55555","555-555-5555");
2> GO
(1 rows affected)
1> insert into Bankers values (6, "YUI Inc.","Ted","Larry","Calgary", "TY","66666","666-666-6666");
2> GO
(1 rows affected)
1> insert into Bankers values (7, "OIP Inc.","Yam","Act", "San Franc","FG","77777","777-777-7777");
2> GO
(1 rows affected)
1> insert into Bankers values (8, "SAD Inc.","Hit","Eat", "Orland", "PO","88888","888-888-8888");
2> GO
(1 rows affected)
1> insert into Bankers values (9, "DFG Inc.","Sad","Lee", "Wisler", "PL","99999","999-999-9999");
2> GO
(1 rows affected)
1> insert into Bankers values (0, "GHJ Inc.","Bit","Lee", "Ticker", "MN","00000","000-000-0000");
2> GO
(1 rows affected)
1>
2>
3> SELECT BankerName, BillingNumber, BillingTotal
4> FROM Billings JOIN Bankers ON Billings.BankerID = Bankers.BankerID
5> WHERE BillingTotal > ALL
6> (SELECT BillingTotal
7> FROM Billings
8> WHERE BankerID = 34)
9> ORDER BY BankerName
10> GO
BankerName BillingNumber BillingTotal
------------- ------------
ABC Inc. 1 165 DEF Inc. 2 165 DFG Inc. 9 165 GHJ Inc. 0 165 HJI Inc. 3 165 OIP Inc. 7 165 QWE Inc. 4 165 RTY Inc. 5 165 SAD Inc. 8 165 YUI Inc. 6 165 (10 rows affected) 1> 2> drop table Billings; 3> drop table Bankers; 4> GO</source>
The ALL operator evaluates to true if the evaluation of the table column in the inner query returns all values of that column.
<source lang="sql">
Get jobs of the employee with the smallest employee number. 5> 6> 7> CREATE TABLE employee( 8> id INTEGER NOT NULL PRIMARY KEY, 9> first_name VARCHAR(10), 10> last_name VARCHAR(10), 11> salary DECIMAL(10,2), 12> start_Date DATETIME, 13> region VARCHAR(10), 14> city VARCHAR(20) 15> ); 16> GO 1> INSERT INTO employee VALUES (1, "Jason" , "Martin", 5890,"2005-03-22","North","Vancouver"); 2> INSERT INTO employee VALUES (2, "Alison", "Mathews",4789,"2003-07-21","South","Utown"); 3> INSERT INTO employee VALUES (3, "James" , "Smith", 6678,"2001-12-01","North","Paris"); 4> INSERT INTO employee VALUES (4, "Celia" , "Rice", 5567,"2006-03-03","South","London"); 5> INSERT INTO employee VALUES (5, "Robert", "Black", 4467,"2004-07-02","East","Newton"); 6> INSERT INTO employee VALUES (6, "Linda" , "Green" , 6456,"2002-05-19","East","Calgary"); 7> INSERT INTO employee VALUES (7, "David" , "Larry", 5345,"2008-03-18","West","New York"); 8> INSERT INTO employee VALUES (8, "James" , "Cat", 4234,"2007-07-17","West","Regina"); 9> INSERT INTO employee VALUES (9, "Joan" , "Act", 6123,"2001-04-16","North","Toronto"); 10> GO (1 rows affected) (1 rows affected) (1 rows affected) (1 rows affected) (1 rows affected) (1 rows affected) (1 rows affected) (1 rows affected) (1 rows affected) 1> select * from employee; 2> GO id first_name last_name salary start_Date region city
---------- ---------- ------------ ----------------------- ---------- --------------------
1 Jason Martin 5890.00 2005-03-22 00:00:00.000 North Vancouver
2 Alison Mathews 4789.00 2003-07-21 00:00:00.000 South Utown
3 James Smith 6678.00 2001-12-01 00:00:00.000 North Paris
4 Celia Rice 5567.00 2006-03-03 00:00:00.000 South London
5 Robert Black 4467.00 2004-07-02 00:00:00.000 East Newton
6 Linda Green 6456.00 2002-05-19 00:00:00.000 East Calgary
7 David Larry 5345.00 2008-03-18 00:00:00.000 West New York
8 James Cat 4234.00 2007-07-17 00:00:00.000 West Regina
9 Joan Act 6123.00 2001-04-16 00:00:00.000 North Toronto
(9 rows affected) 1> 2> CREATE TABLE title( 3> id INTEGER, 4> job_title VARCHAR(20) 5> ); 6> GO 1> 2> INSERT INTO title VALUES (6, "coder"); 3> INSERT INTO title VALUES (7, "tester"); 4> INSERT INTO title VALUES (8, "developer"); 5> INSERT INTO title VALUES (9, "manager"); 6> GO (1 rows affected) (1 rows affected) (1 rows affected) (1 rows affected) 1> 2> 3> SELECT * 4> FROM title 5> WHERE id <= ALL 6> (SELECT id 7> FROM employee) 8> GO id job_title
--------------------
(0 rows affected) 1> drop table employee; 2> drop table title; 3> GO</source>
The ALL predicate is more restrictive, in that all of the values inside the subquery must satisfy the comparison condition.
<source lang="sql">
4> 5> CREATE TABLE employee( 6> id INTEGER NOT NULL PRIMARY KEY, 7> first_name VARCHAR(10), 8> last_name VARCHAR(10), 9> salary DECIMAL(10,2), 10> start_Date DATETIME, 11> region VARCHAR(10), 12> city VARCHAR(20), 13> managerid INTEGER 14> ); 15> GO 1> INSERT INTO employee VALUES (1, "Jason" , "Martin", 5890,"2005-03-22","North","Vancouver",3); 2> GO (1 rows affected) 1> INSERT INTO employee VALUES (2, "Alison", "Mathews",4789,"2003-07-21","South","Utown",4); 2> GO (1 rows affected) 1> INSERT INTO employee VALUES (3, "James" , "Smith", 6678,"2001-12-01","North","Paris",5); 2> GO (1 rows affected) 1> INSERT INTO employee VALUES (4, "Celia" , "Rice", 5567,"2006-03-03","South","London",6); 2> GO (1 rows affected) 1> INSERT INTO employee VALUES (5, "Robert", "Black", 4467,"2004-07-02","East","Newton",7); 2> GO (1 rows affected) 1> INSERT INTO employee VALUES (6, "Linda" , "Green" , 6456,"2002-05-19","East","Calgary",8); 2> GO (1 rows affected) 1> INSERT INTO employee VALUES (7, "David" , "Larry", 5345,"2008-03-18","West","New York",9); 2> GO (1 rows affected) 1> INSERT INTO employee VALUES (8, "James" , "Cat", 4234,"2007-07-17","West","Regina",9); 2> GO (1 rows affected) 1> INSERT INTO employee VALUES (9, "Joan" , "Act", 6123,"2001-04-16","North","Toronto",10); 2> GO (1 rows affected) 1> 2> select * from employee; 3> GO id first_name last_name salary start_Date region city managerid
---------- ---------- ------------ ----------------------- ---------- -------------------- -----------
1 Jason Martin 5890.00 2005-03-22 00:00:00.000 North Vancouver 3
2 Alison Mathews 4789.00 2003-07-21 00:00:00.000 South Utown 4
3 James Smith 6678.00 2001-12-01 00:00:00.000 North Paris 5
4 Celia Rice 5567.00 2006-03-03 00:00:00.000 South London 6
5 Robert Black 4467.00 2004-07-02 00:00:00.000 East Newton 7
6 Linda Green 6456.00 2002-05-19 00:00:00.000 East Calgary 8
7 David Larry 5345.00 2008-03-18 00:00:00.000 West New York 9
8 James Cat 4234.00 2007-07-17 00:00:00.000 West Regina 9
9 Joan Act 6123.00 2001-04-16 00:00:00.000 North Toronto 10
(9 rows affected) 1> 2> 3> SELECT 4> * 5> FROM 6> employee AS T 7> WHERE 8> 1 < ALL 9> ( 10> SELECT 11> COUNT (*) 12> FROM 13> Employee 14> where id = 10 15> ) 16> 17> 18> 19> 20> drop table employee; 21> GO id first_name last_name salary start_Date region city managerid
---------- ---------- ------------ ----------------------- ---------- -------------------- -----------
(0 rows affected)</source>
