SQL Server/T-SQL/Insert Delete Update/Delete

Материал из SQL эксперт
Перейти к: навигация, поиск

Delete can also be performed using the where clause with joined tables

   <source lang="sql">

26> 27> CREATE TABLE employee (emp_no INTEGER NOT NULL, 28> emp_fname CHAR(20) NOT NULL, 29> emp_lname CHAR(20) NOT NULL, 30> dept_no CHAR(4) NULL) 31> 32> insert into employee values(1, "Matthew", "Smith", "d3") 33> insert into employee values(2, "Ann", "Jones", "d3") 34> insert into employee values(3, "John", "Barrimore","d1") 35> insert into employee values(4, "James", "James", "d2") 36> insert into employee values(5, "Elsa", "Bertoni", "d2") 37> insert into employee values(6, "Elke", "Hansel", "d2") 38> insert into employee values(7, "Sybill", "Moser", "d1") 39> 40> select * from employee 41> GO (1 rows affected) (1 rows affected) (1 rows affected) (1 rows affected) (1 rows affected) (1 rows affected) (1 rows affected) emp_no emp_fname emp_lname dept_no


-------------------- -------------------- -------
         1 Matthew              Smith                d3
         2 Ann                  Jones                d3
         3 John                 Barrimore            d1
         4 James                James                d2
         5 Elsa                 Bertoni              d2
         6 Elke                 Hansel               d2
         7 Sybill               Moser                d1

(7 rows affected) 1> 2> CREATE TABLE works_on (emp_no INTEGER NOT NULL, 3> project_no CHAR(4) NOT NULL, 4> job CHAR (15) NULL, 5> enter_date DATETIME NULL) 6> 7> insert into works_on values (1, "p1", "analyst", "1997.10.1") 8> insert into works_on values (1, "p3", "manager", "1999.1.1") 9> insert into works_on values (2, "p2", "clerk", "1998.2.15") 10> insert into works_on values (2, "p2", NULL, "1998.6.1") 11> insert into works_on values (3, "p2", NULL, "1997.12.15") 12> insert into works_on values (4, "p3", "analyst", "1998.10.15") 13> insert into works_on values (5, "p1", "manager", "1998.4.15") 14> insert into works_on values (6, "p1", NULL, "1998.8.1") 15> insert into works_on values (7, "p2", "clerk", "1999.2.1") 16> insert into works_on values (8, "p3", "clerk", "1997.11.15") 17> insert into works_on values (7, "p1", "clerk", "1998.1.4") 18> 19> select * from works_on 20> GO (1 rows affected) (1 rows affected) (1 rows affected) (1 rows affected) (1 rows affected) (1 rows affected) (1 rows affected) (1 rows affected) (1 rows affected) (1 rows affected) (1 rows affected) emp_no project_no job enter_date


---------- --------------- -----------------------
         1 p1         analyst         1997-10-01 00:00:00.000
         1 p3         manager         1999-01-01 00:00:00.000
         2 p2         clerk           1998-02-15 00:00:00.000
         2 p2         NULL            1998-06-01 00:00:00.000
         3 p2         NULL            1997-12-15 00:00:00.000
         4 p3         analyst         1998-10-15 00:00:00.000
         5 p1         manager         1998-04-15 00:00:00.000
         6 p1         NULL            1998-08-01 00:00:00.000
         7 p2         clerk           1999-02-01 00:00:00.000
         8 p3         clerk           1997-11-15 00:00:00.000
         7 p1         clerk           1998-01-04 00:00:00.000

(11 rows affected) 1> 2> 3> -- Delete can also be performed using the where clause 4> 5> DELETE works_on 6> FROM works_on, employee 7> WHERE works_on.emp_no = employee.emp_no 8> AND emp_lname = "Moser" 9> GO (2 rows affected) 1> select * from works_on 2> GO emp_no project_no job enter_date


---------- --------------- -----------------------
         1 p1         analyst         1997-10-01 00:00:00.000
         1 p3         manager         1999-01-01 00:00:00.000
         2 p2         clerk           1998-02-15 00:00:00.000
         2 p2         NULL            1998-06-01 00:00:00.000
         3 p2         NULL            1997-12-15 00:00:00.000
         4 p3         analyst         1998-10-15 00:00:00.000
         5 p1         manager         1998-04-15 00:00:00.000
         6 p1         NULL            1998-08-01 00:00:00.000
         8 p3         clerk           1997-11-15 00:00:00.000

(9 rows affected) 1> 2> drop table works_on 3> drop table employee 4> GO 1> 2>

      </source>
   
  


Delete command with conditions

   <source lang="sql">

1> create table employee( 2> ID int, 3> name nvarchar (10), 4> salary int, 5> start_date datetime, 6> city nvarchar (10), 7> region char (1)) 8> GO 1> 2> insert into employee (ID, name, salary, start_date, city, region) 3> values (1, "Jason", 40420, "02/01/94", "New York", "W") 4> GO (1 rows affected) 1> insert into employee (ID, name, salary, start_date, city, region) 2> values (2, "Robert",14420, "01/02/95", "Vancouver","N") 3> GO (1 rows affected) 1> insert into employee (ID, name, salary, start_date, city, region) 2> values (3, "Celia", 24020, "12/03/96", "Toronto", "W") 3> GO (1 rows affected) 1> insert into employee (ID, name, salary, start_date, city, region) 2> values (4, "Linda", 40620, "11/04/97", "New York", "N") 3> GO (1 rows affected) 1> insert into employee (ID, name, salary, start_date, city, region) 2> values (5, "David", 80026, "10/05/98", "Vancouver","W") 3> GO (1 rows affected) 1> insert into employee (ID, name, salary, start_date, city, region) 2> values (6, "James", 70060, "09/06/99", "Toronto", "N") 3> GO (1 rows affected) 1> insert into employee (ID, name, salary, start_date, city, region) 2> values (7, "Alison",90620, "08/07/00", "New York", "W") 3> GO (1 rows affected) 1> insert into employee (ID, name, salary, start_date, city, region) 2> values (8, "Chris", 26020, "07/08/01", "Vancouver","N") 3> GO (1 rows affected) 1> insert into employee (ID, name, salary, start_date, city, region) 2> values (9, "Mary", 60020, "06/09/02", "Toronto", "W") 3> GO (1 rows affected) 1> 2> select * from employee 3> GO ID name salary start_date city region


---------- ----------- ----------------------- ---------- ------
         1 Jason            40420 1994-02-01 00:00:00.000 New York   W
         2 Robert           14420 1995-01-02 00:00:00.000 Vancouver  N
         3 Celia            24020 1996-12-03 00:00:00.000 Toronto    W
         4 Linda            40620 1997-11-04 00:00:00.000 New York   N
         5 David            80026 1998-10-05 00:00:00.000 Vancouver  W
         6 James            70060 1999-09-06 00:00:00.000 Toronto    N
         7 Alison           90620 2000-08-07 00:00:00.000 New York   W
         8 Chris            26020 2001-07-08 00:00:00.000 Vancouver  N
         9 Mary             60020 2002-06-09 00:00:00.000 Toronto    W

(9 rows affected) 1> 2> DELETE Employee WHERE id = 1 3> GO (1 rows affected) 1> 2> select * from employee 3> GO ID name salary start_date city region


---------- ----------- ----------------------- ---------- ------
         2 Robert           14420 1995-01-02 00:00:00.000 Vancouver  N
         3 Celia            24020 1996-12-03 00:00:00.000 Toronto    W
         4 Linda            40620 1997-11-04 00:00:00.000 New York   N
         5 David            80026 1998-10-05 00:00:00.000 Vancouver  W
         6 James            70060 1999-09-06 00:00:00.000 Toronto    N
         7 Alison           90620 2000-08-07 00:00:00.000 New York   W
         8 Chris            26020 2001-07-08 00:00:00.000 Vancouver  N
         9 Mary             60020 2002-06-09 00:00:00.000 Toronto    W

(8 rows affected) 1> 2> drop table employee 3> GO 1>

      </source>
   
  


Delete rows using IN and subquery

   <source lang="sql">

1> 2> create table employee( 3> ID int, 4> name nvarchar (10), 5> salary int ) 6> GO 1> 2> create table job( 3> ID int, 4> title nvarchar (10), 5> averageSalary int) 6> GO 1> 2> 3> insert into employee (ID, name, salary) values (1, "Jason", 1234) 4> GO (1 rows affected) 1> insert into employee (ID, name, salary) values (2, "Robert", 4321) 2> GO (1 rows affected) 1> insert into employee (ID, name, salary) values (3, "Celia", 5432) 2> GO (1 rows affected) 1> insert into employee (ID, name, salary) values (4, "Linda", 3456) 2> GO (1 rows affected) 1> insert into employee (ID, name, salary) values (5, "David", 7654) 2> GO (1 rows affected) 1> insert into employee (ID, name, salary) values (6, "James", 4567) 2> GO (1 rows affected) 1> insert into employee (ID, name, salary) values (7, "Alison", 8744) 2> GO (1 rows affected) 1> insert into employee (ID, name, salary) values (8, "Chris", 9875) 2> GO (1 rows affected) 1> insert into employee (ID, name, salary) values (9, "Mary", 2345) 2> GO (1 rows affected) 1> 2> insert into job(ID, title, averageSalary) values(1,"Developer",3000) 3> GO (1 rows affected) 1> insert into job(ID, title, averageSalary) values(2,"Tester", 4000) 2> GO (1 rows affected) 1> insert into job(ID, title, averageSalary) values(3,"Designer", 5000) 2> GO (1 rows affected) 1> insert into job(ID, title, averageSalary) values(4,"Programmer", 6000) 2> GO (1 rows affected) 1> 2> 3> select * from employee; 4> GO ID name salary


---------- -----------
         1 Jason             1234
         2 Robert            4321
         3 Celia             5432
         4 Linda             3456
         5 David             7654
         6 James             4567
         7 Alison            8744
         8 Chris             9875
         9 Mary              2345

(9 rows affected) 1> select * from job; 2> GO ID title averageSalary


---------- -------------
         1 Developer           3000
         2 Tester              4000
         3 Designer            5000
         4 Programmer          6000

(4 rows affected) 1> 2> 3> -- Delete Employee: 4> 5> DELETE FROM Employee 6> WHERE ID NOT IN 7> (SELECT ID FROM Job) 8> GO (5 rows affected) 1> 2> select * from employee 3> GO ID name salary


---------- -----------
         1 Jason             1234
         2 Robert            4321
         3 Celia             5432
         4 Linda             3456

(4 rows affected) 1> 2> drop table employee; 3> drop table job; 4> GO 1> 2>

      </source>
   
  


Delete with IN operator and subquery

   <source lang="sql">

28> 29> CREATE TABLE works_on (emp_no INTEGER NOT NULL, 30> project_no CHAR(4) NOT NULL, 31> job CHAR (15) NULL, 32> enter_date DATETIME NULL) 33> 34> insert into works_on values (1, "p1", "analyst", "1997.10.1") 35> insert into works_on values (1, "p3", "manager", "1999.1.1") 36> insert into works_on values (2, "p2", "clerk", "1998.2.15") 37> insert into works_on values (2, "p2", NULL, "1998.6.1") 38> insert into works_on values (3, "p2", NULL, "1997.12.15") 39> insert into works_on values (4, "p3", "analyst", "1998.10.15") 40> insert into works_on values (5, "p1", "manager", "1998.4.15") 41> insert into works_on values (6, "p1", NULL, "1998.8.1") 42> insert into works_on values (7, "p2", "clerk", "1999.2.1") 43> insert into works_on values (8, "p3", "clerk", "1997.11.15") 44> insert into works_on values (7, "p1", "clerk", "1998.1.4") 45> 46> select * from works_on 47> GO (1 rows affected) (1 rows affected) (1 rows affected) (1 rows affected) (1 rows affected) (1 rows affected) (1 rows affected) (1 rows affected) (1 rows affected) (1 rows affected) (1 rows affected) emp_no project_no job enter_date


---------- --------------- -----------------------
         1 p1         analyst         1997-10-01 00:00:00.000
         1 p3         manager         1999-01-01 00:00:00.000
         2 p2         clerk           1998-02-15 00:00:00.000
         2 p2         NULL            1998-06-01 00:00:00.000
         3 p2         NULL            1997-12-15 00:00:00.000
         4 p3         analyst         1998-10-15 00:00:00.000
         5 p1         manager         1998-04-15 00:00:00.000
         6 p1         NULL            1998-08-01 00:00:00.000
         7 p2         clerk           1999-02-01 00:00:00.000
         8 p3         clerk           1997-11-15 00:00:00.000
         7 p1         clerk           1998-01-04 00:00:00.000

(11 rows affected) 1> 2> CREATE TABLE employee (emp_no INTEGER NOT NULL, 3> emp_fname CHAR(20) NOT NULL, 4> emp_lname CHAR(20) NOT NULL, 5> dept_no CHAR(4) NULL) 6> 7> insert into employee values(1, "Matthew", "Smith", "d3") 8> insert into employee values(2, "Ann", "Jones", "d3") 9> insert into employee values(3, "John", "Barrimore","d1") 10> insert into employee values(4, "James", "James", "d2") 11> insert into employee values(5, "Elsa", "Bertoni", "d2") 12> insert into employee values(6, "Elke", "Hansel", "d2") 13> insert into employee values(7, "Sybill", "Moser", "d1") 14> 15> select * from employee 16> GO (1 rows affected) (1 rows affected) (1 rows affected) (1 rows affected) (1 rows affected) (1 rows affected) (1 rows affected) emp_no emp_fname emp_lname dept_no


-------------------- -------------------- -------
         1 Matthew              Smith                d3
         2 Ann                  Jones                d3
         3 John                 Barrimore            d1
         4 James                James                d2
         5 Elsa                 Bertoni              d2
         6 Elke                 Hansel               d2
         7 Sybill               Moser                d1

(7 rows affected) 1> 2> DELETE FROM works_on WHERE emp_no IN 3> (SELECT emp_no FROM employee WHERE emp_lname = "Moser") 4> GO (2 rows affected) 1> select * from works_on 2> GO emp_no project_no job enter_date


---------- --------------- -----------------------
         1 p1         analyst         1997-10-01 00:00:00.000
         1 p3         manager         1999-01-01 00:00:00.000
         2 p2         clerk           1998-02-15 00:00:00.000
         2 p2         NULL            1998-06-01 00:00:00.000
         3 p2         NULL            1997-12-15 00:00:00.000
         4 p3         analyst         1998-10-15 00:00:00.000
         5 p1         manager         1998-04-15 00:00:00.000
         6 p1         NULL            1998-08-01 00:00:00.000
         8 p3         clerk           1997-11-15 00:00:00.000

(9 rows affected) 1> 2> drop table employee; 3> drop table works_on; 4> GO 1>

      </source>
   
  


Deleting a Row in a Table

   <source lang="sql">

1> create table employee( 2> ID int, 3> name nvarchar (10), 4> salary int, 5> start_date datetime, 6> city nvarchar (10), 7> region char (1)) 8> GO 1> 2> insert into employee (ID, name, salary, start_date, city, region) 3> values (1, "Jason", 40420, "02/01/94", "New York", "W") 4> GO (1 rows affected) 1> insert into employee (ID, name, salary, start_date, city, region) 2> values (2, "Robert",14420, "01/02/95", "Vancouver","N") 3> GO (1 rows affected) 1> insert into employee (ID, name, salary, start_date, city, region) 2> values (3, "Celia", 24020, "12/03/96", "Toronto", "W") 3> GO (1 rows affected) 1> insert into employee (ID, name, salary, start_date, city, region) 2> values (4, "Linda", 40620, "11/04/97", "New York", "N") 3> GO (1 rows affected) 1> insert into employee (ID, name, salary, start_date, city, region) 2> values (5, "David", 80026, "10/05/98", "Vancouver","W") 3> GO (1 rows affected) 1> insert into employee (ID, name, salary, start_date, city, region) 2> values (6, "James", 70060, "09/06/99", "Toronto", "N") 3> GO (1 rows affected) 1> insert into employee (ID, name, salary, start_date, city, region) 2> values (7, "Alison",90620, "08/07/00", "New York", "W") 3> GO (1 rows affected) 1> insert into employee (ID, name, salary, start_date, city, region) 2> values (8, "Chris", 26020, "07/08/01", "Vancouver","N") 3> GO (1 rows affected) 1> insert into employee (ID, name, salary, start_date, city, region) 2> values (9, "Mary", 60020, "06/09/02", "Toronto", "W") 3> GO (1 rows affected) 1> 2> select * from employee 3> GO ID name salary start_date city region


---------- ----------- ----------------------- ---------- ------
         1 Jason            40420 1994-02-01 00:00:00.000 New York   W
         2 Robert           14420 1995-01-02 00:00:00.000 Vancouver  N
         3 Celia            24020 1996-12-03 00:00:00.000 Toronto    W
         4 Linda            40620 1997-11-04 00:00:00.000 New York   N
         5 David            80026 1998-10-05 00:00:00.000 Vancouver  W
         6 James            70060 1999-09-06 00:00:00.000 Toronto    N
         7 Alison           90620 2000-08-07 00:00:00.000 New York   W
         8 Chris            26020 2001-07-08 00:00:00.000 Vancouver  N
         9 Mary             60020 2002-06-09 00:00:00.000 Toronto    W

(9 rows affected) 1> 2> --Deleting a Row in a Table 3> 4> 5> CREATE PROC usp_DeleteRecord 6> @ID int 7> AS 8> DELETE FROM Employee WHERE ID = @ID 9> GO 1> 2> EXEC usp_DeleteRecord 2 3> GO (1 rows affected) 1> 2> SELECT * FROM dbo.Employee 3> GO ID name salary start_date city region


---------- ----------- ----------------------- ---------- ------
         1 Jason            40420 1994-02-01 00:00:00.000 New York   W
         3 Celia            24020 1996-12-03 00:00:00.000 Toronto    W
         4 Linda            40620 1997-11-04 00:00:00.000 New York   N
         5 David            80026 1998-10-05 00:00:00.000 Vancouver  W
         6 James            70060 1999-09-06 00:00:00.000 Toronto    N
         7 Alison           90620 2000-08-07 00:00:00.000 New York   W
         8 Chris            26020 2001-07-08 00:00:00.000 Vancouver  N
         9 Mary             60020 2002-06-09 00:00:00.000 Toronto    W

(8 rows affected) 1> 2> drop table employee 3> GO 1>

      </source>
   
  


TOP Clause in DELETE Statements

   <source lang="sql">

1> create table employee( 2> ID int, 3> name nvarchar (10), 4> salary int, 5> start_date datetime, 6> city nvarchar (10), 7> region char (1)) 8> GO 1> 2> insert into employee (ID, name, salary, start_date, city, region) 3> values (1, "Jason", 40420, "02/01/94", "New York", "W") 4> GO (1 rows affected) 1> insert into employee (ID, name, salary, start_date, city, region) 2> values (2, "Robert",14420, "01/02/95", "Vancouver","N") 3> GO (1 rows affected) 1> insert into employee (ID, name, salary, start_date, city, region) 2> values (3, "Celia", 24020, "12/03/96", "Toronto", "W") 3> GO (1 rows affected) 1> insert into employee (ID, name, salary, start_date, city, region) 2> values (4, "Linda", 40620, "11/04/97", "New York", "N") 3> GO (1 rows affected) 1> insert into employee (ID, name, salary, start_date, city, region) 2> values (5, "David", 80026, "10/05/98", "Vancouver","W") 3> GO (1 rows affected) 1> insert into employee (ID, name, salary, start_date, city, region) 2> values (6, "James", 70060, "09/06/99", "Toronto", "N") 3> GO (1 rows affected) 1> insert into employee (ID, name, salary, start_date, city, region) 2> values (7, "Alison",90620, "08/07/00", "New York", "W") 3> GO (1 rows affected) 1> insert into employee (ID, name, salary, start_date, city, region) 2> values (8, "Chris", 26020, "07/08/01", "Vancouver","N") 3> GO (1 rows affected) 1> insert into employee (ID, name, salary, start_date, city, region) 2> values (9, "Mary", 60020, "06/09/02", "Toronto", "W") 3> GO (1 rows affected) 1> 2> select * from employee 3> GO ID name salary start_date city region


---------- ----------- ----------------------- ---------- ------
         1 Jason            40420 1994-02-01 00:00:00.000 New York   W
         2 Robert           14420 1995-01-02 00:00:00.000 Vancouver  N
         3 Celia            24020 1996-12-03 00:00:00.000 Toronto    W
         4 Linda            40620 1997-11-04 00:00:00.000 New York   N
         5 David            80026 1998-10-05 00:00:00.000 Vancouver  W
         6 James            70060 1999-09-06 00:00:00.000 Toronto    N
         7 Alison           90620 2000-08-07 00:00:00.000 New York   W
         8 Chris            26020 2001-07-08 00:00:00.000 Vancouver  N
         9 Mary             60020 2002-06-09 00:00:00.000 Toronto    W

(9 rows affected) 1> 2> 3> --TOP Clause in DELETE Statements 4> 5> DELETE Employee 6> FROM (SELECT TOP 3 * FROM Employee) AS Employee1 7> GO (9 rows affected) 1> 2> select * from employee 3> GO ID name salary start_date city region


---------- ----------- ----------------------- ---------- ------

(0 rows affected) 1> 2> drop table employee 3> GO 1>

      </source>