SQL/MySQL/Where Clause/OR

AND and OR may be intermixed

   <source lang="sql">

/* mysql> select * from Bird; +----------+-------+---------+------+------------+-------+ | name | owner | species | sex | birth | death | +----------+-------+---------+------+------------+-------+ | BlueBird | Joe | Car | f | 1999-03-30 | NULL | | RedBird | Yin | Bus | m | 1979-03-30 | NULL | +----------+-------+---------+------+------------+-------+ 2 rows in set (0.00 sec) mysql> /*although AND has higher precedence than OR*/ mysql> SELECT * FROM Bird WHERE (species = "Car" AND sex = "m")

   ->       OR (species = "Bus" AND sex = "f");

Empty set (0.00 sec)

• /

Drop table Bird; CREATE TABLE Bird (

   name VARCHAR(20), 
   owner VARCHAR(20),
   species VARCHAR(20), 
   sex CHAR(1), 
   birth DATE, 
   death DATE

);

INSERT INTO Bird VALUES ("BlueBird","Joe","Car","f","1999-03-30",NULL); INSERT INTO Bird VALUES ("RedBird","Yin","Bus","m","1979-03-30",NULL);

select * from Bird;

/*although AND has higher precedence than OR*/
 

SELECT * FROM Bird WHERE (species = "Car" AND sex = "m")

     OR (species = "Bus" AND sex = "f");
          
      </source>
   
  

An OR operator

   <source lang="sql">

/* mysql> select * from Bird; +----------+-------+---------+------+------------+-------+ | name | owner | species | sex | birth | death | +----------+-------+---------+------+------------+-------+ | BlueBird | Joe | Car | f | 1999-03-30 | NULL | | RedBird | Yin | Bus | m | 1979-03-30 | NULL | +----------+-------+---------+------+------------+-------+ 2 rows in set (0.01 sec) mysql> SELECT * FROM Bird WHERE species = "Bus" OR sex = "f"; +----------+-------+---------+------+------------+-------+ | name | owner | species | sex | birth | death | +----------+-------+---------+------+------------+-------+ | BlueBird | Joe | Car | f | 1999-03-30 | NULL | | RedBird | Yin | Bus | m | 1979-03-30 | NULL | +----------+-------+---------+------+------------+-------+ 2 rows in set (0.00 sec)

• /

Drop table Bird; CREATE TABLE Bird (

   name VARCHAR(20), 
   owner VARCHAR(20),
   species VARCHAR(20), 
   sex CHAR(1), 
   birth DATE, 
   death DATE

);

INSERT INTO Bird VALUES ("BlueBird","Joe","Car","f","1999-03-30",NULL); INSERT INTO Bird VALUES ("RedBird","Yin","Bus","m","1979-03-30",NULL);

select * from Bird;

SELECT * FROM Bird WHERE species = "Bus" OR sex = "f";

      </source>
   
  

Combine conditions in select clause

   <source lang="sql">

Drop table employee; CREATE TABLE employee (

   id int unsigned not null auto_increment primary key,
   firstname varchar(20),
   lastname varchar(20),
   title varchar(30),
   age int,
   yearofservice int,
   salary int,
   perks int,
   email varchar(60)

);

INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("John", "Chen", "Senior Programmer", 31, 3, 120000, 25000, "j@hotmail.ru"); INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Jan", "Pillai", "Senior Programmer", 32, 4, 110000, 20000, "g@yahoo.ru"); INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Ane", "Pandit", "Web Designer", 24, 3, 90000, 15000, "a@gmail.ru"); INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Mary", "Anchor", "Web Designer", 27, 2, 85000, 15000, "m@mail.ru"); INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Fred", "King", "Programmer", 32, 3, 75000, 15000, "f@net.ru"); INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("John", "Mac", "Programmer", 32, 4, 80000, 16000, "j@hotmail.ru"); INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Arthur", "Sam", "Programmer", 28, 2, 75000, 14000, "e@yahoo.ru"); INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Alok", "Nanda", "Programmer", 32, 3, 70000, 10000, "a@yahoo.ru"); INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Susan", "Ra", "Multimedia Programmer", 32, 4, 90000, 15000, "h@gmail.ru"); INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Paul", "Simon", "Multimedia Programmer", 23, 1, 85000, 12000, "ps@gmail.ru"); INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Edward", "Parhar", "Multimedia Programmer", 30, 2, 75000, 15000, "a@hotmail.ru"); INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Kim", "Hunter", "Senior Web Designer", 32, 4, 110000, 20000, "kim@coolmail.ru"); INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Roger", "Lewis", "System Administrator", 32, 3, 100000, 13000, "roger@mail.ru"); INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Danny", "Gibson", "System Administrator", 31, 2, 90000, 12000, "danny@hotmail.ru"); INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Mike", "Harper", "Senior Marketing Executive", 36, 1, 120000, 28000, "m@gmail.ru"); INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Mary", "Sunday", "Marketing Executive", 31, 5, 90000, 25000, "monica@bigmail.ru"); INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Jack", "Sim", "Marketing Executive", 27, 1, 70000, 18000, "hal@gmail.ru"); INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Joe", "Irvine", "Marketing Executive", 27, 1, 72000, 18000, "joseph@hotmail.ru"); INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Henry", "Ali", "Customer Service Manager", 32, 3, 70000, 9000, "shahida@hotmail.ru"); INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Peter", "Champion", "Finance Manager", 32, 2, 120000, 25000, "peter@yahoo.ru"); select * from employee; SELECT firstname, lastName , age from employee where (lastName like "S%" OR lastName like "A%") AND age < 30;

      </source>
   
  

Combine condition with OR

   <source lang="sql">

/* mysql> select * from Student; +-----------+------------+-----------+ | StudentID | first_name | last_name | +-----------+------------+-----------+ | 1 | John | Jones | | 2 | Gary | Burton | | 3 | Emily | Scarlett | | 4 | Bruce | Lee | | 5 | Anna | Wolff | | 6 | Vic | Andrews | | 7 | Steve | Alaska | +-----------+------------+-----------+ 7 rows in set (0.02 sec) mysql> select * from Student WHERE first_name="Bruce" OR last_name="Burton" OR

   ->                                  last_name="Wolff";

+-----------+------------+-----------+ | StudentID | first_name | last_name | +-----------+------------+-----------+ | 2 | Gary | Burton | | 4 | Bruce | Lee | | 5 | Anna | Wolff | +-----------+------------+-----------+ 3 rows in set (0.00 sec)

• /

Drop table Student; CREATE TABLE Student (

  StudentID INT NOT NULL PRIMARY KEY,
  first_name      VARCHAR(50) NOT NULL,
  last_name      VARCHAR(50) NOT NULL
  

)TYPE = InnoDB;

INSERT INTO Student (StudentID,first_name, last_name) VALUES (4,"Bruce", "Lee"); INSERT INTO Student (StudentID,first_name, last_name) VALUES (1,"John", "Jones"); INSERT INTO Student (StudentID,first_name, last_name) VALUES (2,"Gary", "Burton"); INSERT INTO Student (StudentID,first_name, last_name) VALUES (7,"Steve", "Alaska"); INSERT INTO Student (StudentID,first_name, last_name) VALUES (5,"Anna", "Wolff"); INSERT INTO Student (StudentID,first_name, last_name) VALUES (6,"Vic", "Andrews"); INSERT INTO Student (StudentID,first_name, last_name) VALUES (3,"Emily", "Scarlett"); select * from Student; select * from Student WHERE first_name="Bruce" OR last_name="Burton" OR

                                last_name="Wolff";
 
          
      </source>