Oracle PL/SQL/Hierarchical Query/Start With Connect

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Hierarchical Queries: START WITH and CONNECT BY PRIOR clauses

   <source lang="sql">

-- Hierarchical Queries SQL> SQL> CREATE TABLE employee (

 2    employee_id INTEGER,
 3    manager_id INTEGER,
 4    first_name VARCHAR2(10) NOT NULL,
 5    last_name VARCHAR2(10) NOT NULL,
 6    title VARCHAR2(20),
 7    salary NUMBER(6, 0)
 8  );

Table created. SQL> SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)

 2                 values( 1         ,0            , "James"  ,"Smith"  ,"CEO",800000);

1 row created. SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)

 2                 values( 2         , 1         ,"Ron"     ,"Johnson","Sales Manager",600000);

1 row created. SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)

 2                 values( 3         , 2         ,"Fred"    ,"Hobbs"  ,"Sales Person",200000);

1 row created. SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)

 2                 values( 4         , 1         ,"Susan"   ,"Jones"  ,"Support Manager",500000);

1 row created. SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)

 2                 values( 5         , 2         ,"Rob"     ,"Green"  ,"Sales Person", 40000);

1 row created. SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)

 2                 values( 6         , 4         ,"Jane"    ,"Brown"  ,"Support Person",45000);

1 row created. SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)

 2                 values( 7         , 4         ,"John"    ,"Grey"   ,"Support Manager",30000);

1 row created. SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)

 2                 values( 8         , 7         ,"Jean"    ,"Blue"   ,"Support Person",29000);

1 row created. SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)

 2                 values( 9         , 6         ,"Henry"   ,"Heyson" ,"Support Person",30000);

1 row created. SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)

 2                 values( 10        , 1         ,"Kevin"   ,"Black"  ,"Ops Manager",100000);

1 row created. SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)

 2                 values( 11        , 10        ,"Keith"   ,"Long"   ,"Ops Person",50000);

1 row created. SQL> SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)

 2                 values( 12        , 10        ,"Frank"   ,"Howard" ,"Ops Person",45000);

1 row created. SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)

 2                 values( 13        , 10        ,"Doreen"  ,"Penn"   ,"Ops Person",47000);

1 row created. SQL> SQL> SQL> SQL> SQL> select * from employee; EMPLOYEE_ID MANAGER_ID FIRST_NAME LAST_NAME TITLE SALARY


---------- ---------- ---------- -------------------- ----------
         1          0 James      Smith      CEO                      800000
         2          1 Ron        Johnson    Sales Manager            600000
         3          2 Fred       Hobbs      Sales Person             200000
         4          1 Susan      Jones      Support Manager          500000
         5          2 Rob        Green      Sales Person              40000
         6          4 Jane       Brown      Support Person            45000
         7          4 John       Grey       Support Manager           30000
         8          7 Jean       Blue       Support Person            29000
         9          6 Henry      Heyson     Support Person            30000
        10          1 Kevin      Black      Ops Manager              100000
        11         10 Keith      Long       Ops Person                50000
        12         10 Frank      Howard     Ops Person                45000
        13         10 Doreen     Penn       Ops Person                47000

13 rows selected. SQL> SQL> SQL> --START WITH and CONNECT BY PRIOR clauses. SQL> SQL> SELECT employee_id, manager_id, first_name, last_name

 2  FROM employee
 3  START WITH employee_id = 1
 4  CONNECT BY PRIOR employee_id = manager_id;

EMPLOYEE_ID MANAGER_ID FIRST_NAME LAST_NAME


---------- ---------- ----------
         1          0 James      Smith
         2          1 Ron        Johnson
         3          2 Fred       Hobbs
         5          2 Rob        Green
         4          1 Susan      Jones
         6          4 Jane       Brown
         9          6 Henry      Heyson
         7          4 John       Grey
         8          7 Jean       Blue
        10          1 Kevin      Black
        11         10 Keith      Long
        12         10 Frank      Howard
        13         10 Doreen     Penn

13 rows selected. SQL> SQL> SQL> SQL> drop table employee; Table dropped. SQL> SQL>

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Including Other Conditions in a Hierarchical Query

   <source lang="sql">

SQL> CREATE TABLE employee (

 2    employee_id INTEGER,
 3    manager_id INTEGER,
 4    first_name VARCHAR2(10) NOT NULL,
 5    last_name VARCHAR2(10) NOT NULL,
 6    title VARCHAR2(20),
 7    salary NUMBER(6, 0)
 8  );

Table created. SQL> SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)

 2                 values( 1         ,0            , "James"  ,"Smith"  ,"CEO",800000);

1 row created. SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)

 2                 values( 2         , 1         ,"Ron"     ,"Johnson","Sales Manager",600000);

1 row created. SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)

 2                 values( 3         , 2         ,"Fred"    ,"Hobbs"  ,"Sales Person",200000);

1 row created. SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)

 2                 values( 4         , 1         ,"Susan"   ,"Jones"  ,"Support Manager",500000);

1 row created. SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)

 2                 values( 5         , 2         ,"Rob"     ,"Green"  ,"Sales Person", 40000);

1 row created. SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)

 2                 values( 6         , 4         ,"Jane"    ,"Brown"  ,"Support Person",45000);

1 row created. SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)

 2                 values( 7         , 4         ,"John"    ,"Grey"   ,"Support Manager",30000);

1 row created. SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)

 2                 values( 8         , 7         ,"Jean"    ,"Blue"   ,"Support Person",29000);

1 row created. SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)

 2                 values( 9         , 6         ,"Henry"   ,"Heyson" ,"Support Person",30000);

1 row created. SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)

 2                 values( 10        , 1         ,"Kevin"   ,"Black"  ,"Ops Manager",100000);

1 row created. SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)

 2                 values( 11        , 10        ,"Keith"   ,"Long"   ,"Ops Person",50000);

1 row created. SQL> SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)

 2                 values( 12        , 10        ,"Frank"   ,"Howard" ,"Ops Person",45000);

1 row created. SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)

 2                 values( 13        , 10        ,"Doreen"  ,"Penn"   ,"Ops Person",47000);

1 row created. SQL> SQL> SQL> SQL> SQL> select * from employee; EMPLOYEE_ID MANAGER_ID FIRST_NAME LAST_NAME TITLE SALARY


---------- ---------- ---------- -------------------- ----------
         1          0 James      Smith      CEO                      800000
         2          1 Ron        Johnson    Sales Manager            600000
         3          2 Fred       Hobbs      Sales Person             200000
         4          1 Susan      Jones      Support Manager          500000
         5          2 Rob        Green      Sales Person              40000
         6          4 Jane       Brown      Support Person            45000
         7          4 John       Grey       Support Manager           30000
         8          7 Jean       Blue       Support Person            29000
         9          6 Henry      Heyson     Support Person            30000
        10          1 Kevin      Black      Ops Manager              100000
        11         10 Keith      Long       Ops Person                50000
        12         10 Frank      Howard     Ops Person                45000
        13         10 Doreen     Penn       Ops Person                47000

13 rows selected. SQL> SQL> SQL> -- Including Other Conditions in a Hierarchical Query SQL> SQL> SELECT LEVEL,

 2   LPAD(" ", 2 * LEVEL - 1) || first_name || " " ||
 3   last_name AS employee, salary
 4  FROM employee
 5  WHERE salary <= 50000
 6  START WITH employee_id = 1
 7  CONNECT BY PRIOR employee_id = manager_id;
    LEVEL EMPLOYEE                      SALARY

------------------------- ----------
        3      Rob Green                 40000
        3      Jane Brown                45000
        4        Henry Heyson            30000
        3      John Grey                 30000
        4        Jean Blue               29000
        3      Keith Long                50000
        3      Frank Howard              45000
        3      Doreen Penn               47000

8 rows selected. SQL> SQL> SQL> SQL> SQL> drop table employee; Table dropped. SQL> SQL>

      </source>
   
  


Using a Subquery in a START WITH Clause

   <source lang="sql">

SQL> CREATE TABLE employee (

 2    employee_id INTEGER,
 3    manager_id INTEGER,
 4    first_name VARCHAR2(10) NOT NULL,
 5    last_name VARCHAR2(10) NOT NULL,
 6    title VARCHAR2(20),
 7    salary NUMBER(6, 0)
 8  );

Table created. SQL> SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)

 2                 values( 1         ,0            , "James"  ,"Smith"  ,"CEO",800000);

1 row created. SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)

 2                 values( 2         , 1         ,"Ron"     ,"Johnson","Sales Manager",600000);

1 row created. SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)

 2                 values( 3         , 2         ,"Fred"    ,"Hobbs"  ,"Sales Person",200000);

1 row created. SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)

 2                 values( 4         , 1         ,"Susan"   ,"Jones"  ,"Support Manager",500000);

1 row created. SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)

 2                 values( 5         , 2         ,"Rob"     ,"Green"  ,"Sales Person", 40000);

1 row created. SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)

 2                 values( 6         , 4         ,"Jane"    ,"Brown"  ,"Support Person",45000);

1 row created. SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)

 2                 values( 7         , 4         ,"John"    ,"Grey"   ,"Support Manager",30000);

1 row created. SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)

 2                 values( 8         , 7         ,"Jean"    ,"Blue"   ,"Support Person",29000);

1 row created. SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)

 2                 values( 9         , 6         ,"Henry"   ,"Heyson" ,"Support Person",30000);

1 row created. SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)

 2                 values( 10        , 1         ,"Kevin"   ,"Black"  ,"Ops Manager",100000);

1 row created. SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)

 2                 values( 11        , 10        ,"Keith"   ,"Long"   ,"Ops Person",50000);

1 row created. SQL> SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)

 2                 values( 12        , 10        ,"Frank"   ,"Howard" ,"Ops Person",45000);

1 row created. SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)

 2                 values( 13        , 10        ,"Doreen"  ,"Penn"   ,"Ops Person",47000);

1 row created. SQL> SQL> SQL> SQL> SQL> select * from employee; EMPLOYEE_ID MANAGER_ID FIRST_NAME LAST_NAME TITLE SALARY


---------- ---------- ---------- -------------------- ----------
         1          0 James      Smith      CEO                      800000
         2          1 Ron        Johnson    Sales Manager            600000
         3          2 Fred       Hobbs      Sales Person             200000
         4          1 Susan      Jones      Support Manager          500000
         5          2 Rob        Green      Sales Person              40000
         6          4 Jane       Brown      Support Person            45000
         7          4 John       Grey       Support Manager           30000
         8          7 Jean       Blue       Support Person            29000
         9          6 Henry      Heyson     Support Person            30000
        10          1 Kevin      Black      Ops Manager              100000
        11         10 Keith      Long       Ops Person                50000
        12         10 Frank      Howard     Ops Person                45000
        13         10 Doreen     Penn       Ops Person                47000

13 rows selected. SQL> SQL> --Using a Subquery in a START WITH Clause SQL> SQL> SELECT LEVEL,

 2   LPAD(" ", 2 * LEVEL - 1) || first_name || " " ||
 3   last_name AS employee
 4  FROM employee
 5  START WITH employee_id = (
 6    SELECT employee_id
 7    FROM employee
 8    WHERE first_name = "Kevin"
 9    AND last_name = "Black"
10  )
11  CONNECT BY PRIOR employee_id = manager_id;
    LEVEL EMPLOYEE

-------------------------
        1  Kevin Black
        2    Keith Long
        2    Frank Howard
        2    Doreen Penn

SQL> SQL> SQL> SQL> drop table employee; Table dropped. SQL> SQL>

      </source>