Oracle PL/SQL/Hierarchical Query/Nodes Branches

Материал из SQL эксперт
Перейти к: навигация, поиск

Eliminate an entire branch of nodes from the results of a query, you add an AND clause to your CONNECT BY PRIOR clause

   <source lang="sql">

SQL> SQL> CREATE TABLE employee (

 2    employee_id INTEGER,
 3    manager_id INTEGER,
 4    first_name VARCHAR2(10) NOT NULL,
 5    last_name VARCHAR2(10) NOT NULL,
 6    title VARCHAR2(20),
 7    salary NUMBER(6, 0)
 8  );

Table created. SQL> SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)

 2                 values( 1         ,0            , "James"  ,"Smith"  ,"CEO",800000);

1 row created. SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)

 2                 values( 2         , 1         ,"Ron"     ,"Johnson","Sales Manager",600000);

1 row created. SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)

 2                 values( 3         , 2         ,"Fred"    ,"Hobbs"  ,"Sales Person",200000);

1 row created. SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)

 2                 values( 4         , 1         ,"Susan"   ,"Jones"  ,"Support Manager",500000);

1 row created. SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)

 2                 values( 5         , 2         ,"Rob"     ,"Green"  ,"Sales Person", 40000);

1 row created. SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)

 2                 values( 6         , 4         ,"Jane"    ,"Brown"  ,"Support Person",45000);

1 row created. SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)

 2                 values( 7         , 4         ,"John"    ,"Grey"   ,"Support Manager",30000);

1 row created. SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)

 2                 values( 8         , 7         ,"Jean"    ,"Blue"   ,"Support Person",29000);

1 row created. SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)

 2                 values( 9         , 6         ,"Henry"   ,"Heyson" ,"Support Person",30000);

1 row created. SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)

 2                 values( 10        , 1         ,"Kevin"   ,"Black"  ,"Ops Manager",100000);

1 row created. SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)

 2                 values( 11        , 10        ,"Keith"   ,"Long"   ,"Ops Person",50000);

1 row created. SQL> SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)

 2                 values( 12        , 10        ,"Frank"   ,"Howard" ,"Ops Person",45000);

1 row created. SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)

 2                 values( 13        , 10        ,"Doreen"  ,"Penn"   ,"Ops Person",47000);

1 row created. SQL> SQL> SQL> SQL> SQL> select * from employee; EMPLOYEE_ID MANAGER_ID FIRST_NAME LAST_NAME TITLE SALARY


---------- ---------- ---------- -------------------- ----------
         1          0 James      Smith      CEO                      800000
         2          1 Ron        Johnson    Sales Manager            600000
         3          2 Fred       Hobbs      Sales Person             200000
         4          1 Susan      Jones      Support Manager          500000
         5          2 Rob        Green      Sales Person              40000
         6          4 Jane       Brown      Support Person            45000
         7          4 John       Grey       Support Manager           30000
         8          7 Jean       Blue       Support Person            29000
         9          6 Henry      Heyson     Support Person            30000
        10          1 Kevin      Black      Ops Manager              100000
        11         10 Keith      Long       Ops Person                50000
        12         10 Frank      Howard     Ops Person                45000
        13         10 Doreen     Penn       Ops Person                47000

13 rows selected. SQL> SQL> SQL> --Eliminate an entire branch of nodes from the results of a query, you add an AND clause to your CONNECT BY PRIOR clause SQL> SQL> SELECT LEVEL,

 2   LPAD(" ", 2 * LEVEL - 1) || first_name || " " ||
 3   last_name AS employee
 4  FROM employee
 5  START WITH employee_id = 1
 6  CONNECT BY PRIOR employee_id = manager_id
 7  AND last_name != "Johnson";
    LEVEL EMPLOYEE

-------------------------
        1  James Smith
        2    Susan Jones
        3      Jane Brown
        4        Henry Heyson
        3      John Grey
        4        Jean Blue
        2    Kevin Black
        3      Keith Long
        3      Frank Howard
        3      Doreen Penn

10 rows selected. SQL> SQL> SQL> SQL> drop table employee; Table dropped. SQL> SQL>

      </source>
   
  


Eliminating Nodes and Branches from a Hierarchical Query

   <source lang="sql">

SQL> CREATE TABLE employee (

 2    employee_id INTEGER,
 3    manager_id INTEGER,
 4    first_name VARCHAR2(10) NOT NULL,
 5    last_name VARCHAR2(10) NOT NULL,
 6    title VARCHAR2(20),
 7    salary NUMBER(6, 0)
 8  );

Table created. SQL> SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)

 2                 values( 1         ,0            , "James"  ,"Smith"  ,"CEO",800000);

1 row created. SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)

 2                 values( 2         , 1         ,"Ron"     ,"Johnson","Sales Manager",600000);

1 row created. SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)

 2                 values( 3         , 2         ,"Fred"    ,"Hobbs"  ,"Sales Person",200000);

1 row created. SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)

 2                 values( 4         , 1         ,"Susan"   ,"Jones"  ,"Support Manager",500000);

1 row created. SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)

 2                 values( 5         , 2         ,"Rob"     ,"Green"  ,"Sales Person", 40000);

1 row created. SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)

 2                 values( 6         , 4         ,"Jane"    ,"Brown"  ,"Support Person",45000);

1 row created. SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)

 2                 values( 7         , 4         ,"John"    ,"Grey"   ,"Support Manager",30000);

1 row created. SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)

 2                 values( 8         , 7         ,"Jean"    ,"Blue"   ,"Support Person",29000);

1 row created. SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)

 2                 values( 9         , 6         ,"Henry"   ,"Heyson" ,"Support Person",30000);

1 row created. SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)

 2                 values( 10        , 1         ,"Kevin"   ,"Black"  ,"Ops Manager",100000);

1 row created. SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)

 2                 values( 11        , 10        ,"Keith"   ,"Long"   ,"Ops Person",50000);

1 row created. SQL> SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)

 2                 values( 12        , 10        ,"Frank"   ,"Howard" ,"Ops Person",45000);

1 row created. SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)

 2                 values( 13        , 10        ,"Doreen"  ,"Penn"   ,"Ops Person",47000);

1 row created. SQL> SQL> SQL> SQL> SQL> select * from employee; EMPLOYEE_ID MANAGER_ID FIRST_NAME LAST_NAME TITLE SALARY


---------- ---------- ---------- -------------------- ----------
         1          0 James      Smith      CEO                      800000
         2          1 Ron        Johnson    Sales Manager            600000
         3          2 Fred       Hobbs      Sales Person             200000
         4          1 Susan      Jones      Support Manager          500000
         5          2 Rob        Green      Sales Person              40000
         6          4 Jane       Brown      Support Person            45000
         7          4 John       Grey       Support Manager           30000
         8          7 Jean       Blue       Support Person            29000
         9          6 Henry      Heyson     Support Person            30000
        10          1 Kevin      Black      Ops Manager              100000
        11         10 Keith      Long       Ops Person                50000
        12         10 Frank      Howard     Ops Person                45000
        13         10 Doreen     Penn       Ops Person                47000

13 rows selected. SQL> SQL> -- Eliminating Nodes and Branches from a Hierarchical Query SQL> SQL> SELECT LEVEL,

 2   LPAD(" ", 2 * LEVEL - 1) || first_name || " " ||
 3   last_name AS employee
 4  FROM employee
 5  WHERE last_name != "Johnson"
 6  START WITH employee_id = 1
 7  CONNECT BY PRIOR employee_id = manager_id;
    LEVEL EMPLOYEE

-------------------------
        1  James Smith
        3      Fred Hobbs
        3      Rob Green
        2    Susan Jones
        3      Jane Brown
        4        Henry Heyson
        3      John Grey
        4        Jean Blue
        2    Kevin Black
        3      Keith Long
        3      Frank Howard
        3      Doreen Penn

12 rows selected. SQL> SQL> SQL> SQL> drop table employee; Table dropped. SQL> SQL>

      </source>