Oracle PL/SQL/Hierarchical Query/Nodes Branches

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Eliminate an entire branch of nodes from the results of a query, you add an AND clause to your CONNECT BY PRIOR clause

SQL>
SQL> CREATE TABLE employee (
  2    employee_id INTEGER,
  3    manager_id INTEGER,
  4    first_name VARCHAR2(10) NOT NULL,
  5    last_name VARCHAR2(10) NOT NULL,
  6    title VARCHAR2(20),
  7    salary NUMBER(6, 0)
  8  );
Table created.
SQL>
SQL>
SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)
  2                 values( 1         ,0            , "James"  ,"Smith"  ,"CEO",800000);
1 row created.
SQL>
SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)
  2                 values( 2         , 1         ,"Ron"     ,"Johnson","Sales Manager",600000);
1 row created.
SQL>
SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)
  2                 values( 3         , 2         ,"Fred"    ,"Hobbs"  ,"Sales Person",200000);
1 row created.
SQL>
SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)
  2                 values( 4         , 1         ,"Susan"   ,"Jones"  ,"Support Manager",500000);
1 row created.
SQL>
SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)
  2                 values( 5         , 2         ,"Rob"     ,"Green"  ,"Sales Person", 40000);
1 row created.
SQL>
SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)
  2                 values( 6         , 4         ,"Jane"    ,"Brown"  ,"Support Person",45000);
1 row created.
SQL>
SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)
  2                 values( 7         , 4         ,"John"    ,"Grey"   ,"Support Manager",30000);
1 row created.
SQL>
SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)
  2                 values( 8         , 7         ,"Jean"    ,"Blue"   ,"Support Person",29000);
1 row created.
SQL>
SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)
  2                 values( 9         , 6         ,"Henry"   ,"Heyson" ,"Support Person",30000);
1 row created.
SQL>
SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)
  2                 values( 10        , 1         ,"Kevin"   ,"Black"  ,"Ops Manager",100000);
1 row created.
SQL>
SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)
  2                 values( 11        , 10        ,"Keith"   ,"Long"   ,"Ops Person",50000);
1 row created.
SQL>
SQL>
SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)
  2                 values( 12        , 10        ,"Frank"   ,"Howard" ,"Ops Person",45000);
1 row created.
SQL>
SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)
  2                 values( 13        , 10        ,"Doreen"  ,"Penn"   ,"Ops Person",47000);
1 row created.
SQL>
SQL>
SQL>
SQL>
SQL> select * from employee;
EMPLOYEE_ID MANAGER_ID FIRST_NAME LAST_NAME  TITLE                    SALARY
----------- ---------- ---------- ---------- -------------------- ----------
          1          0 James      Smith      CEO                      800000
          2          1 Ron        Johnson    Sales Manager            600000
          3          2 Fred       Hobbs      Sales Person             200000
          4          1 Susan      Jones      Support Manager          500000
          5          2 Rob        Green      Sales Person              40000
          6          4 Jane       Brown      Support Person            45000
          7          4 John       Grey       Support Manager           30000
          8          7 Jean       Blue       Support Person            29000
          9          6 Henry      Heyson     Support Person            30000
         10          1 Kevin      Black      Ops Manager              100000
         11         10 Keith      Long       Ops Person                50000
         12         10 Frank      Howard     Ops Person                45000
         13         10 Doreen     Penn       Ops Person                47000
13 rows selected.
SQL>
SQL>
SQL> --Eliminate an entire branch of nodes from the results of a query, you add an AND 
clause to your CONNECT BY PRIOR clause
SQL>
SQL> SELECT LEVEL,
  2   LPAD(" ", 2 * LEVEL - 1) || first_name || " " ||
  3   last_name AS employee
  4  FROM employee
  5  START WITH employee_id = 1
  6  CONNECT BY PRIOR employee_id = manager_id
  7  AND last_name != "Johnson";
     LEVEL EMPLOYEE
---------- -------------------------
         1  James Smith
         2    Susan Jones
         3      Jane Brown
         4        Henry Heyson
         3      John Grey
         4        Jean Blue
         2    Kevin Black
         3      Keith Long
         3      Frank Howard
         3      Doreen Penn
10 rows selected.
SQL>
SQL>
SQL>
SQL> drop table employee;
Table dropped.
SQL>
SQL>



Eliminating Nodes and Branches from a Hierarchical Query

SQL> CREATE TABLE employee (
  2    employee_id INTEGER,
  3    manager_id INTEGER,
  4    first_name VARCHAR2(10) NOT NULL,
  5    last_name VARCHAR2(10) NOT NULL,
  6    title VARCHAR2(20),
  7    salary NUMBER(6, 0)
  8  );
Table created.
SQL>
SQL>
SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)
  2                 values( 1         ,0            , "James"  ,"Smith"  ,"CEO",800000);
1 row created.
SQL>
SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)
  2                 values( 2         , 1         ,"Ron"     ,"Johnson","Sales Manager",600000);
1 row created.
SQL>
SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)
  2                 values( 3         , 2         ,"Fred"    ,"Hobbs"  ,"Sales Person",200000);
1 row created.
SQL>
SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)
  2                 values( 4         , 1         ,"Susan"   ,"Jones"  ,"Support Manager",500000);
1 row created.
SQL>
SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)
  2                 values( 5         , 2         ,"Rob"     ,"Green"  ,"Sales Person", 40000);
1 row created.
SQL>
SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)
  2                 values( 6         , 4         ,"Jane"    ,"Brown"  ,"Support Person",45000);
1 row created.
SQL>
SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)
  2                 values( 7         , 4         ,"John"    ,"Grey"   ,"Support Manager",30000);
1 row created.
SQL>
SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)
  2                 values( 8         , 7         ,"Jean"    ,"Blue"   ,"Support Person",29000);
1 row created.
SQL>
SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)
  2                 values( 9         , 6         ,"Henry"   ,"Heyson" ,"Support Person",30000);
1 row created.
SQL>
SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)
  2                 values( 10        , 1         ,"Kevin"   ,"Black"  ,"Ops Manager",100000);
1 row created.
SQL>
SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)
  2                 values( 11        , 10        ,"Keith"   ,"Long"   ,"Ops Person",50000);
1 row created.
SQL>
SQL>
SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)
  2                 values( 12        , 10        ,"Frank"   ,"Howard" ,"Ops Person",45000);
1 row created.
SQL>
SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)
  2                 values( 13        , 10        ,"Doreen"  ,"Penn"   ,"Ops Person",47000);
1 row created.
SQL>
SQL>
SQL>
SQL>
SQL> select * from employee;
EMPLOYEE_ID MANAGER_ID FIRST_NAME LAST_NAME  TITLE                    SALARY
----------- ---------- ---------- ---------- -------------------- ----------
          1          0 James      Smith      CEO                      800000
          2          1 Ron        Johnson    Sales Manager            600000
          3          2 Fred       Hobbs      Sales Person             200000
          4          1 Susan      Jones      Support Manager          500000
          5          2 Rob        Green      Sales Person              40000
          6          4 Jane       Brown      Support Person            45000
          7          4 John       Grey       Support Manager           30000
          8          7 Jean       Blue       Support Person            29000
          9          6 Henry      Heyson     Support Person            30000
         10          1 Kevin      Black      Ops Manager              100000
         11         10 Keith      Long       Ops Person                50000
         12         10 Frank      Howard     Ops Person                45000
         13         10 Doreen     Penn       Ops Person                47000
13 rows selected.
SQL>
SQL> -- Eliminating Nodes and Branches from a Hierarchical Query
SQL>
SQL> SELECT LEVEL,
  2   LPAD(" ", 2 * LEVEL - 1) || first_name || " " ||
  3   last_name AS employee
  4  FROM employee
  5  WHERE last_name != "Johnson"
  6  START WITH employee_id = 1
  7  CONNECT BY PRIOR employee_id = manager_id;
     LEVEL EMPLOYEE
---------- -------------------------
         1  James Smith
         3      Fred Hobbs
         3      Rob Green
         2    Susan Jones
         3      Jane Brown
         4        Henry Heyson
         3      John Grey
         4        Jean Blue
         2    Kevin Black
         3      Keith Long
         3      Frank Howard
         3      Doreen Penn
12 rows selected.
SQL>
SQL>
SQL>
SQL> drop table employee;
Table dropped.
SQL>
SQL>