SQL Server/T-SQL Tutorial/System Functions/sp helpindex — различия между версиями

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Текущая версия на 13:24, 26 мая 2010

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   <source lang="sql">

3> 4> CREATE TABLE employee( 5> id INTEGER NOT NULL PRIMARY KEY, 6> first_name VARCHAR(10), 7> last_name VARCHAR(10), 8> salary DECIMAL(10,2), 9> start_Date DATETIME, 10> region VARCHAR(10), 11> city VARCHAR(20), 12> managerid INTEGER 13> ); 14> GO 1> INSERT INTO employee VALUES (1, "Jason" , "Martin", 5890,"2005-03-22","North","Vancouver",3); 2> GO (1 rows affected) 1> INSERT INTO employee VALUES (2, "Alison", "Mathews",4789,"2003-07-21","South","Utown",4); 2> GO (1 rows affected) 1> INSERT INTO employee VALUES (3, "James" , "Smith", 6678,"2001-12-01","North","Paris",5); 2> GO (1 rows affected) 1> INSERT INTO employee VALUES (4, "Celia" , "Rice", 5567,"2006-03-03","South","London",6); 2> GO (1 rows affected) 1> INSERT INTO employee VALUES (5, "Robert", "Black", 4467,"2004-07-02","East","Newton",7); 2> GO (1 rows affected) 1> INSERT INTO employee VALUES (6, "Linda" , "Green" , 6456,"2002-05-19","East","Calgary",8); 2> GO (1 rows affected) 1> INSERT INTO employee VALUES (7, "David" , "Larry", 5345,"2008-03-18","West","New York",9); 2> GO (1 rows affected) 1> INSERT INTO employee VALUES (8, "James" , "Cat", 4234,"2007-07-17","West","Regina",9); 2> GO (1 rows affected) 1> INSERT INTO employee VALUES (9, "Joan" , "Act", 6123,"2001-04-16","North","Toronto",10); 2> GO (1 rows affected) 1> 2> select * from employee; 3> GO id first_name last_name salary start_Date region city managerid


---------- ---------- ------------ ----------------------- ---------- -------------------- -----------
         1 Jason      Martin          5890.00 2005-03-22 00:00:00.000 North      Vancouver                      3
         2 Alison     Mathews         4789.00 2003-07-21 00:00:00.000 South      Utown                          4
         3 James      Smith           6678.00 2001-12-01 00:00:00.000 North      Paris                          5
         4 Celia      Rice            5567.00 2006-03-03 00:00:00.000 South      London                         6
         5 Robert     Black           4467.00 2004-07-02 00:00:00.000 East       Newton                         7
         6 Linda      Green           6456.00 2002-05-19 00:00:00.000 East       Calgary                        8
         7 David      Larry           5345.00 2008-03-18 00:00:00.000 West       New York                       9
         8 James      Cat             4234.00 2007-07-17 00:00:00.000 West       Regina                         9
         9 Joan       Act             6123.00 2001-04-16 00:00:00.000 North      Toronto                       10

(9 rows affected) 1> 2> 3> 4> CREATE NONCLUSTERED INDEX NI_Salary 5> ON Employee (Salary DESC) 6> GO 1> 2> EXEC sp_helpindex "Employee" 3> GO index_name

        index_description
                                                                                                   index_keys







---------------------------------------------------------------------------------------------------------------
--------------------

















NI_Salary

        nonclustered located on PRIMARY
                                                                                                   salary(-)





PK__employee__033C6B35

        clustered, unique, primary key located on PRIMARY
                                                                                                   id





1> SELECT SUBSTRING(name, 1,30) index_name, 2> allow_row_locks, 3> allow_page_locks, 4> is_disabled, 5> fill_factor 6> FROM sys.indexes 7> WHERE object_id = OBJECT_ID("Employee") 8> GO index_name allow_row_locks allow_page_locks is_disabled fill_factor


--------------- ---------------- ----------- -----------

PK__employee__033C6B35 1 1 0 0 NI_Salary 1 1 0 0 (2 rows affected) 1> 2> 3> 4> drop table employee; 5> GO</source>