Oracle PL/SQL Tutorial/Numerical Math Functions/FLOOR
Содержание
- 1 FLOOR(-5.2)
- 2 FLOOR(5.8)
- 3 FLOOR for negative value
- 4 FLOOR(x) gets the largest integer less than or equal to x.
- 5 select round(345.678), ceil(345.678), floor(345.678)
- 6 Use floor and mod to get the number of days
- 7 Use FLOOR function to get the flooring value
- 8 Use floor to get the number of weeks
FLOOR(-5.2)
<source lang="sql">
SQL> select FLOOR(-5.2) from dual; FLOOR(-5.2)
-6</source>
FLOOR(5.8)
<source lang="sql">
SQL> select FLOOR(5.8) from dual; FLOOR(5.8)
5</source>
FLOOR for negative value
<source lang="sql">
SQL> SQL> -- create demo table SQL> create table myTable(
2 id NUMBER(2), 3 value NUMBER(6,2) 4 ) 5 /
Table created. SQL> SQL> -- prepare data SQL> insert into myTable(ID, value)values (1,9)
2 /
1 row created. SQL> insert into myTable(ID, value)values (2,2.11)
2 /
1 row created. SQL> insert into myTable(ID, value)values (3,3.44)
2 /
1 row created. SQL> insert into myTable(ID, value)values (4,-4.21)
2 /
1 row created. SQL> insert into myTable(ID, value)values (5,10)
2 /
1 row created. SQL> insert into myTable(ID, value)values (6,3)
2 /
1 row created. SQL> insert into myTable(ID, value)values (7,-5.88)
2 /
1 row created. SQL> insert into myTable(ID, value)values (8,123.45)
2 /
1 row created. SQL> insert into myTable(ID, value)values (9,98.23)
2 /
1 row created. SQL> SQL> select * from myTable
2 /
ID VALUE
----------
1 9
2 2.11
3 3.44
4 -4.21
5 10
6 3
7 -5.88
8 123.45
9 98.23
9 rows selected. SQL> SQL> SQL> SELECT id, value,FLOOR(value) FROM myTable
2 /
ID VALUE FLOOR(VALUE)
---------- ------------
1 9 9
2 2.11 2
3 3.44 3
4 -4.21 -5
5 10 10
6 3 3
7 -5.88 -6
8 123.45 123
9 98.23 98
9 rows selected. SQL> SQL> SQL> SQL> -- clean the table SQL> drop table myTable
2 /
Table dropped. SQL> SQL></source>
FLOOR(x) gets the largest integer less than or equal to x.
The following example uses FLOOR() to display the absolute value of 5.8 and -5.2, respectively:
<source lang="sql">
SQL> SELECT FLOOR(5.8), FLOOR(-5.2) FROM dual; FLOOR(5.8) FLOOR(-5.2)
-----------
5 -6
SQL></source>
select round(345.678), ceil(345.678), floor(345.678)
<source lang="sql">
SQL> SQL> SQL> select round(345.678), ceil(345.678), floor(345.678)
2 from dual;
ROUND(345.678) CEIL(345.678) FLOOR(345.678)
------------- --------------
346 346 345
SQL> SQL> SQL></source>
Use floor and mod to get the number of days
<source lang="sql">
SQL> SQL> create table employees(
2 empno NUMBER(4) 3 , ename VARCHAR2(8) 4 , init VARCHAR2(5) 5 , job VARCHAR2(8) 6 , mgr NUMBER(4) 7 , bdate DATE 8 , msal NUMBER(6,2) 9 , comm NUMBER(6,2) 10 , deptno NUMBER(2) ) ;
Table created. SQL> SQL> SQL> insert into employees values(1,"Jason", "N", "TRAINER", 2, date "1965-12-18", 800 , NULL, 10); 1 row created. SQL> insert into employees values(2,"Jerry", "J", "SALESREP",3, date "1966-11-19", 1600, 300, 10); 1 row created. SQL> insert into employees values(3,"Jord", "T" , "SALESREP",4, date "1967-10-21", 1700, 500, 20); 1 row created. SQL> insert into employees values(4,"Mary", "J", "MANAGER", 5, date "1968-09-22", 1800, NULL, 20); 1 row created. SQL> insert into employees values(5,"Joe", "P", "SALESREP",6, date "1969-08-23", 1900, 1400, 30); 1 row created. SQL> insert into employees values(6,"Black", "R", "MANAGER", 7, date "1970-07-24", 2000, NULL, 30); 1 row created. SQL> insert into employees values(7,"Red", "A", "MANAGER", 8, date "1971-06-25", 2100, NULL, 40); 1 row created. SQL> insert into employees values(8,"White", "S", "TRAINER", 9, date "1972-05-26", 2200, NULL, 40); 1 row created. SQL> insert into employees values(9,"Yellow", "C", "DIRECTOR",10, date "1973-04-27", 2300, NULL, 20); 1 row created. SQL> insert into employees values(10,"Pink", "J", "SALESREP",null,date "1974-03-28", 2400, 0, 30); 1 row created. SQL> SQL> SQL> select ename
2 , floor(mod(sysdate-bdate,7)) as days 3 from employees;
ENAME DAYS
----------
Jason 5 Jerry 5 Jord 5 Mary 4 Joe 5 Black 6 Red 6 White 6 Yellow 6 Pink 0 10 rows selected. SQL> SQL> SQL> drop table employees; Table dropped. SQL> SQL></source>
Use FLOOR function to get the flooring value
<source lang="sql">
SQL> SQL> SQL> -- create demo table SQL> create table myTable(
2 id NUMBER(2), 3 value NUMBER(6,2) 4 ) 5 /
Table created. SQL> SQL> -- prepare data SQL> insert into myTable(ID, value)values (1,9)
2 /
1 row created. SQL> insert into myTable(ID, value)values (2,2.11)
2 /
1 row created. SQL> insert into myTable(ID, value)values (3,3.44)
2 /
1 row created. SQL> insert into myTable(ID, value)values (4,-4.21)
2 /
1 row created. SQL> insert into myTable(ID, value)values (5,10)
2 /
1 row created. SQL> insert into myTable(ID, value)values (6,3)
2 /
1 row created. SQL> insert into myTable(ID, value)values (7,-5.88)
2 /
1 row created. SQL> insert into myTable(ID, value)values (8,123.45)
2 /
1 row created. SQL> insert into myTable(ID, value)values (9,98.23)
2 /
1 row created. SQL> SQL> select * from myTable
2 /
ID VALUE
----------
1 9
2 2.11
3 3.44
4 -4.21
5 10
6 3
7 -5.88
8 123.45
9 98.23
9 rows selected. SQL> SQL> SELECT id, value,FLOOR(value) FROM myTable
2 /
ID VALUE FLOOR(VALUE)
---------- ------------
1 9 9
2 2.11 2
3 3.44 3
4 -4.21 -5
5 10 10
6 3 3
7 -5.88 -6
8 123.45 123
9 98.23 98
9 rows selected. SQL> SQL> SQL> -- clean the table SQL> drop table myTable
2 /
Table dropped. SQL> SQL></source>
Use floor to get the number of weeks
<source lang="sql">
SQL> SQL> SQL> create table employees(
2 empno NUMBER(4) 3 , ename VARCHAR2(8) 4 , init VARCHAR2(5) 5 , job VARCHAR2(8) 6 , mgr NUMBER(4) 7 , bdate DATE 8 , msal NUMBER(6,2) 9 , comm NUMBER(6,2) 10 , deptno NUMBER(2) ) ;
Table created. SQL> SQL> SQL> insert into employees values(1,"Jason", "N", "TRAINER", 2, date "1965-12-18", 800 , NULL, 10); 1 row created. SQL> insert into employees values(2,"Jerry", "J", "SALESREP",3, date "1966-11-19", 1600, 300, 10); 1 row created. SQL> insert into employees values(3,"Jord", "T" , "SALESREP",4, date "1967-10-21", 1700, 500, 20); 1 row created. SQL> insert into employees values(4,"Mary", "J", "MANAGER", 5, date "1968-09-22", 1800, NULL, 20); 1 row created. SQL> insert into employees values(5,"Joe", "P", "SALESREP",6, date "1969-08-23", 1900, 1400, 30); 1 row created. SQL> insert into employees values(6,"Black", "R", "MANAGER", 7, date "1970-07-24", 2000, NULL, 30); 1 row created. SQL> insert into employees values(7,"Red", "A", "MANAGER", 8, date "1971-06-25", 2100, NULL, 40); 1 row created. SQL> insert into employees values(8,"White", "S", "TRAINER", 9, date "1972-05-26", 2200, NULL, 40); 1 row created. SQL> insert into employees values(9,"Yellow", "C", "DIRECTOR",10, date "1973-04-27", 2300, NULL, 20); 1 row created. SQL> insert into employees values(10,"Pink", "J", "SALESREP",null,date "1974-03-28", 2400, 0, 30); 1 row created. SQL> SQL> SQL> select ename ,floor((sysdate-bdate)/7) as weeks
2 from employees;
ENAME WEEKS
----------
Jason 2222 Jerry 2174 Jord 2126 Mary 2078 Joe 2030 Black 1982 Red 1934 White 1886 Yellow 1838 Pink 1791 10 rows selected. SQL> SQL> SQL> drop table employees; Table dropped.</source>
