SQL Server/T-SQL/String Functions/Regular Expressions — различия между версиями

Материал из SQL эксперт
Перейти к: навигация, поиск
м (1 версия)
 
(нет различий)

Текущая версия на 10:19, 26 мая 2010

Any of the wildcard characters (%, _ [, ], or ?) enclosed in square brackets stand for themselves

1> CREATE TABLE project   (project_no   CHAR(4) NOT NULL,
2>                         project_name CHAR(15) NOT NULL,
3>                         budget FLOAT NULL)
4> GO
1> insert into project values ("p1", "Search Engine",        120000.00)
2> insert into project values ("p2", "Programming",          95000.00)
3> insert into project values ("p3", "SQL",                  186500.00)
4> GO
(1 rows affected)
(1 rows affected)
(1 rows affected)
1>
2> -- Any of the wildcard characters (%, _ [, ], or ?) enclosed in 
square brackets stand for themselves.
3>
4> SELECT project_no, project_name
5>        FROM project
6>        WHERE project_name LIKE "%[_]%"
7> GO
project_no project_name
---------- ---------------
(0 rows affected)
1> drop table project
2> GO
1>



Begin with a character in the range C through F

1> CREATE TABLE department(dept_no   CHAR(4) NOT NULL,
2>                         dept_name CHAR(25) NOT NULL,
3>                         location  CHAR(30) NULL)
4> GO
1> insert into department values ("d1", "developer",   "Dallas")
2> insert into department values ("d2", "tester",      "Seattle")
3> insert into department values ("d3", "marketing",  "Dallas")
4> GO
(1 rows affected)
(1 rows affected)
(1 rows affected)
1> -- Begin with a character in the range C through F.
2>
3> SELECT * FROM department WHERE location LIKE "[C-F]%"
4> GO
dept_no dept_name                 location
------- ------------------------- ------------------------------
d1      developer                 Dallas
d3      marketing                 Dallas
(2 rows affected)
1> drop table department
2> GO
1>



"%" is for any length of letters

1> CREATE TABLE employee  (emp_no    INTEGER NOT NULL,
2>                         emp_fname CHAR(20) NOT NULL,
3>                         emp_lname CHAR(20) NOT NULL,
4>                         dept_no   CHAR(4) NULL)
5> GO
1>
2> insert into employee values(1,  "Matthew", "Smith",    "d3")
3> insert into employee values(2,  "Ann",     "Jones",    "d3")
4> insert into employee values(3,  "John",    "Barrimore","d1")
5> insert into employee values(4,  "James",   "James",    "d2")
6> insert into employee values(5,  "Elsa",    "Bertoni",  "d2")
7> insert into employee values(6,  "Elke",    "Hansel",   "d2")
8> insert into employee values(7,  "Sybill",  "Moser",    "d1")
9> GO
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
1>
2> select * from employee
3> GO
emp_no      emp_fname            emp_lname            dept_no
----------- -------------------- -------------------- -------
          1 Matthew              Smith                d3
          2 Ann                  Jones                d3
          3 John                 Barrimore            d1
          4 James                James                d2
          5 Elsa                 Bertoni              d2
          6 Elke                 Hansel               d2
          7 Sybill               Moser                d1
(7 rows affected)
1>
2>
3> -- LIKE Operator
4>
5> SELECT emp_fname, emp_lname, emp_no FROM employee WHERE emp_lname LIKE "J%"
6> GO
emp_fname            emp_lname            emp_no
-------------------- -------------------- -----------
Ann                  Jones                          2
James                James                          4
(2 rows affected)
1> drop table employee
2> GO
1>



"_" is for one letter

1> CREATE TABLE employee  (emp_no    INTEGER NOT NULL,
2>                         emp_fname CHAR(20) NOT NULL,
3>                         emp_lname CHAR(20) NOT NULL,
4>                         dept_no   CHAR(4) NULL)
5> GO
1> insert into employee values(1,  "Matthew", "Smith",    "d3")
2> insert into employee values(2,  "Ann",     "Jones",    "d3")
3> insert into employee values(3,  "John",    "Barrimore","d1")
4> insert into employee values(4,  "James",   "James",    "d2")
5> insert into employee values(5,  "Elsa",    "Bertoni",  "d2")
6> insert into employee values(6,  "Elke",    "Hansel",   "d2")
7> insert into employee values(7,  "Sybill",  "Moser",    "d1")
8> GO
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
1> select * from employee
2> GO
emp_no      emp_fname            emp_lname            dept_no
----------- -------------------- -------------------- -------
          1 Matthew              Smith                d3
          2 Ann                  Jones                d3
          3 John                 Barrimore            d1
          4 James                James                d2
          5 Elsa                 Bertoni              d2
          6 Elke                 Hansel               d2
          7 Sybill               Moser                d1
(7 rows affected)
1>
2> SELECT emp_fname, emp_lname, emp_no FROM employee WHERE emp_fname LIKE "_a%"
3> GO
emp_fname            emp_lname            emp_no
-------------------- -------------------- -----------
Matthew              Smith                          1
James                James                          4
(2 rows affected)
1> drop table employee
2> GO
1>



^ specifies the negation of a range or a list of characters

1> CREATE TABLE employee  (emp_no    INTEGER NOT NULL,
2>                         emp_fname CHAR(20) NOT NULL,
3>                         emp_lname CHAR(20) NOT NULL,
4>                         dept_no   CHAR(4) NULL)
5> GO
1> insert into employee values(1,  "Matthew", "Smith",    "d3")
2> insert into employee values(2,  "Ann",     "Jones",    "d3")
3> insert into employee values(3,  "John",    "Barrimore","d1")
4> insert into employee values(4,  "James",   "James",    "d2")
5> insert into employee values(5,  "Elsa",    "Bertoni",  "d2")
6> insert into employee values(6,  "Elke",    "Hansel",   "d2")
7> insert into employee values(7,  "Sybill",  "Moser",    "d1")
8> GO
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
1> select * from employee
2> GO
emp_no      emp_fname            emp_lname            dept_no
----------- -------------------- -------------------- -------
          1 Matthew              Smith                d3
          2 Ann                  Jones                d3
          3 John                 Barrimore            d1
          4 James                James                d2
          5 Elsa                 Bertoni              d2
          6 Elke                 Hansel               d2
          7 Sybill               Moser                d1
(7 rows affected)
1> -- ^ specifies the negation of a range or a list of characters
2>
3> SELECT emp_no, emp_fname, emp_lname FROM employee
4>        WHERE emp_lname LIKE "[^J-O]%"
5>        AND emp_fname LIKE "[^EZ]%"
6> GO
emp_no      emp_fname            emp_lname
----------- -------------------- --------------------
          1 Matthew              Smith
          3 John                 Barrimore
(2 rows affected)
1> drop table employee
2> GO
1>
2>