SQL/MySQL/Select Clause/Group — различия между версиями
Admin (обсуждение | вклад) м (1 версия) |
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Версия 13:46, 26 мая 2010
Содержание
- 1 Another GROUP BY
- 2 Get GROUP BY for COUNT
- 3 GROUP and HAVING with sub query
- 4 GROUP and sort the records
- 5 GROUP BY with order and HAVING
- 6 Grouping Data: 03 Using the HAVING Clause 1
- 7 Grouping Data: Filtering Group Data
- 8 Grouping Data: Using the HAVING Clause 1
- 9 GROUP value and count
- 10 Simple GROUP BY
- 11 Use GROUP BY
- 12 Use GROUP BY 2
- 13 Use GROUP BY and ORDER BY together
- 14 Use GROUP BY clause to list only the unique data
- 15 Using math function in HAVING
Another GROUP BY
/*
mysql> select * from sales;
+-----+------------+--------+--------+--------+------+------------+
| num | name | winter | spring | summer | fall | category |
+-----+------------+--------+--------+--------+------+------------+
| 1 | Java | 1067 | 200 | 150 | 267 | Holiday |
| 2 | C | 970 | 770 | 531 | 486 | Profession |
| 3 | JavaScript | 53 | 13 | 21 | 856 | Literary |
| 4 | SQL | 782 | 357 | 168 | 250 | Profession |
| 5 | Oracle | 589 | 795 | 367 | 284 | Holiday |
| 6 | MySQL | 953 | 582 | 336 | 489 | Literary |
| 7 | Cplus | 752 | 657 | 259 | 478 | Literary |
| 8 | Python | 67 | 23 | 83 | 543 | Holiday |
| 9 | PHP | 673 | 48 | 625 | 52 | Profession |
+-----+------------+--------+--------+--------+------+------------+
9 rows in set (0.00 sec)
mysql> /*Use the following GROUP BY clause to list only the unique cities and st
ates in the cust_city and cust_state columns of the duck_cust table.
mysql> */
mysql> SELECT name, category FROM sales
-> GROUP BY name;
+------------+------------+
| name | category |
+------------+------------+
| C | Profession |
| Cplus | Literary |
| Java | Holiday |
| JavaScript | Literary |
| MySQL | Literary |
| Oracle | Holiday |
| PHP | Profession |
| Python | Holiday |
| SQL | Profession |
+------------+------------+
9 rows in set (0.00 sec)
*/
Drop table sales;
CREATE TABLE sales(
num MEDIUMINT NOT NULL AUTO_INCREMENT,
name CHAR(20),
winter INT,
spring INT,
summer INT,
fall INT,
category CHAR(13),
primary key(num)
)type=MyISAM;
insert into sales value(1, "Java", 1067 , 200, 150, 267,"Holiday");
insert into sales value(2, "C",970,770,531,486,"Profession");
insert into sales value(3, "JavaScript",53,13,21,856,"Literary");
insert into sales value(4, "SQL",782,357,168,250,"Profession");
insert into sales value(5, "Oracle",589,795,367,284,"Holiday");
insert into sales value(6, "MySQL",953,582,336,489,"Literary");
insert into sales value(7, "Cplus",752,657,259,478,"Literary");
insert into sales value(8, "Python",67,23,83,543,"Holiday");
insert into sales value(9, "PHP",673,48,625,52,"Profession");
select * from sales;
/*Use the following GROUP BY clause to list only the unique cities and states in the cust_city and cust_state columns of the duck_cust table.
*/
SELECT name FROM sales
GROUP BY name;
Get GROUP BY for COUNT
/*
mysql> select * from employee;
+----+-----------+----------+----------------------------+------+---------------+--------+-------+---------------------+
| id | firstname | lastname | title | age | yearofservice| salary | perks | email |
+----+-----------+----------+----------------------------+------+---------------+--------+-------+---------------------+
| 1 | John | Chen | Senior Programmer | 31 | 3| 120000 | 25000 | j@hotmail.ru |
| 2 | Jan | Pillai | Senior Programmer | 32 | 4| 110000 | 20000 | g@yahoo.ru |
| 3 | Ane | Pandit | Web Designer | 24 | 3| 90000 | 15000 | a@gmail.ru |
| 4 | Mary | Anchor | Web Designer | 27 | 2| 85000 | 15000 | m@mail.ru |
| 5 | Fred | King | Programmer | 32 | 3| 75000 | 15000 | f@net.ru |
| 6 | John | Mac | Programmer | 32 | 4| 80000 | 16000 | j@hotmail.ru |
| 7 | Arthur | Sam | Programmer | 28 | 2| 75000 | 14000 | e@yahoo.ru |
| 8 | Alok | Nanda | Programmer | 32 | 3| 70000 | 10000 | a@yahoo.ru |
| 9 | Susan | Ra | Multimedia Programmer | 32 | 4| 90000 | 15000 | h@gmail.ru |
| 10 | Paul | Simon | Multimedia Programmer | 23 | 1| 85000 | 12000 | ps@gmail.ru |
| 11 | Edward | Parhar | Multimedia Programmer | 30 | 2| 75000 | 15000 | a@hotmail.ru |
| 12 | Kim | Hunter | Senior Web Designer | 32 | 4| 110000 | 20000 | kim@coolmail.ru |
| 13 | Roger | Lewis | System Administrator | 32 | 3| 100000 | 13000 | roger@mail.ru |
| 14 | Danny | Gibson | System Administrator | 31 | 2| 90000 | 12000 | danny@hotmail.ru |
| 15 | Mike | Harper | Senior Marketing Executive | 36 | 1| 120000 | 28000 | m@gmail.ru |
| 16 | Mary | Sunday | Marketing Executive | 31 | 5| 90000 | 25000 | monica@bigmail.ru |
| 17 | Jack | Sim | Marketing Executive | 27 | 1| 70000 | 18000 | hal@gmail.ru |
| 18 | Joe | Irvine | Marketing Executive | 27 | 1| 72000 | 18000 | joseph@hotmail.ru |
| 19 | Henry | Ali | Customer Service Manager | 32 | 3| 70000 | 9000 | shahida@hotmail.ru |
| 20 | Peter | Champion | Finance Manager | 32 | 2| 120000 | 25000 | peter@yahoo.ru |
+----+-----------+----------+----------------------------+------+---------------+--------+-------+---------------------+
20 rows in set (0.00 sec)
mysql> select title, count(*)
-> from employee GROUP BY title;
+----------------------------+----------+
| title | count(*) |
+----------------------------+----------+
| Customer Service Manager | 1 |
| Finance Manager | 1 |
| Marketing Executive | 3 |
| Multimedia Programmer | 3 |
| Programmer | 4 |
| Senior Marketing Executive | 1 |
| Senior Programmer | 2 |
| Senior Web Designer | 1 |
| System Administrator | 2 |
| Web Designer | 2 |
+----------------------------+----------+
10 rows in set (0.00 sec)
*/
Drop table employee;
CREATE TABLE employee (
id int unsigned not null auto_increment primary key,
firstname varchar(20),
lastname varchar(20),
title varchar(30),
age int,
yearofservice int,
salary int,
perks int,
email varchar(60)
);
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("John", "Chen", "Senior Programmer", 31, 3, 120000, 25000, "j@hotmail.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Jan", "Pillai", "Senior Programmer", 32, 4, 110000, 20000, "g@yahoo.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Ane", "Pandit", "Web Designer", 24, 3, 90000, 15000, "a@gmail.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Mary", "Anchor", "Web Designer", 27, 2, 85000, 15000, "m@mail.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Fred", "King", "Programmer", 32, 3, 75000, 15000, "f@net.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("John", "Mac", "Programmer", 32, 4, 80000, 16000, "j@hotmail.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Arthur", "Sam", "Programmer", 28, 2, 75000, 14000, "e@yahoo.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Alok", "Nanda", "Programmer", 32, 3, 70000, 10000, "a@yahoo.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Susan", "Ra", "Multimedia Programmer", 32, 4, 90000, 15000, "h@gmail.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Paul", "Simon", "Multimedia Programmer", 23, 1, 85000, 12000, "ps@gmail.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Edward", "Parhar", "Multimedia Programmer", 30, 2, 75000, 15000, "a@hotmail.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Kim", "Hunter", "Senior Web Designer", 32, 4, 110000, 20000, "kim@coolmail.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Roger", "Lewis", "System Administrator", 32, 3, 100000, 13000, "roger@mail.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Danny", "Gibson", "System Administrator", 31, 2, 90000, 12000, "danny@hotmail.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Mike", "Harper", "Senior Marketing Executive", 36, 1, 120000, 28000, "m@gmail.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Mary", "Sunday", "Marketing Executive", 31, 5, 90000, 25000, "monica@bigmail.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Jack", "Sim", "Marketing Executive", 27, 1, 70000, 18000, "hal@gmail.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Joe", "Irvine", "Marketing Executive", 27, 1, 72000, 18000, "joseph@hotmail.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Henry", "Ali", "Customer Service Manager", 32, 3, 70000, 9000, "shahida@hotmail.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Peter", "Champion", "Finance Manager", 32, 2, 120000, 25000, "peter@yahoo.ru");
select * from employee;
select title, count(*)
from employee GROUP BY title;
GROUP and HAVING with sub query
/*
mysql> SELECT ArticleID, SUM(Quantity) AS Total
-> FROM ArticleOrders
-> GROUP BY ArticleID
-> HAVING ArticleID IN
-> (SELECT ArticleID FROM AuthorArticle WHERE AuthID IN
-> (
-> SELECT AuthID FROM AuthorArticle
-> GROUP BY AuthID
-> HAVING COUNT(*)>1
-> )
-> );
+-----------+-------+
| ArticleID | Total |
+-----------+-------+
| 19264 | 1 |
| 19354 | 3 |
+-----------+-------+
2 rows in set (0.01 sec)
*/
Drop table Articles;
Drop table Authors;
Drop table AuthorArticle;
Drop table ArticleOrders;
CREATE TABLE Articles (
ArticleID SMALLINT NOT NULL PRIMARY KEY,
ArticleTitle VARCHAR(60) NOT NULL,
Copyright YEAR NOT NULL
)
ENGINE=INNODB;
INSERT INTO Articles VALUES (12786, "How write a paper", 1934),
(13331, "Publish a paper", 1919),
(14356, "Sell a paper", 1966),
(15729, "Buy a paper", 1932),
(16284, "Conferences", 1996),
(17695, "Journal", 1980),
(19264, "Information", 1992),
(19354, "AI", 1993);
CREATE TABLE Authors (
AuthID SMALLINT NOT NULL PRIMARY KEY,
AuthorFirstName VARCHAR(20),
AuthorMiddleName VARCHAR(20),
AuthorLastName VARCHAR(20)
)
ENGINE=INNODB;
INSERT INTO Authors VALUES (1006, "Henry", "S.", "Thompson"),
(1007, "Jason", "Carol", "Oak"),
(1008, "James", NULL, "Elk"),
(1009, "Tom", "M", "Ride"),
(1010, "Jack", "K", "Ken"),
(1011, "Mary", "G.", "Lee"),
(1012, "Annie", NULL, "Peng"),
(1013, "Alan", NULL, "Wang"),
(1014, "Nelson", NULL, "Yin");
CREATE TABLE AuthorArticle (
AuthID SMALLINT NOT NULL,
ArticleID SMALLINT NOT NULL,
PRIMARY KEY (AuthID, ArticleID),
FOREIGN KEY (AuthID) REFERENCES Authors (AuthID),
FOREIGN KEY (ArticleID) REFERENCES Articles (ArticleID)
)
ENGINE=INNODB;
INSERT INTO AuthorArticle VALUES (1006, 14356),
(1008, 15729),
(1009, 12786),
(1010, 17695),
(1011, 15729),
(1012, 19264),
(1012, 19354),
(1014, 16284);
CREATE TABLE ArticleOrders
(
OrderID SMALLINT NOT NULL,
ArticleID SMALLINT NOT NULL,
Quantity SMALLINT NOT NULL,
PRIMARY KEY (OrderID, ArticleID),
FOREIGN KEY (ArticleID) REFERENCES Articles (ArticleID)
)
ENGINE=INNODB;
INSERT INTO ArticleOrders VALUES (101, 13331, 1),
(101, 12786, 1),
(101, 16284, 2),
(102, 19354, 1),
(102, 15729, 3),
(103, 12786, 2),
(103, 19264, 1),
(103, 13331, 1),
(103, 14356, 2),
(104, 19354, 1),
(105, 15729, 1),
(105, 14356, 2),
(106, 16284, 2),
(106, 13331, 1),
(107, 12786, 3),
(108, 19354, 1),
(108, 16284, 4),
(109, 15729, 1),
(110, 13331, 2),
(110, 12786, 2),
(110, 14356, 2),
(111, 14356, 2);
SELECT ArticleID, SUM(Quantity) AS Total
FROM ArticleOrders
GROUP BY ArticleID
HAVING ArticleID IN
(SELECT ArticleID FROM AuthorArticle WHERE AuthID IN
(
SELECT AuthID FROM AuthorArticle
GROUP BY AuthID
HAVING COUNT(*)>1
)
);
GROUP and sort the records
/*
mysql> select * from employee_person;
+----+-------------------------------------+---------+---------------------------+------------+------+----------+-----------------+----------+
| id | address | phone | email | birthday | sex | m_status | s_name | children |
+----+-------------------------------------+---------+---------------------------+------------+------+----------+-----------------+----------+
| 1 | 200, Regina Street | 7176666 | net@hotmail.ru | 1971-04-26 | M | Y | Ane Regina | NULL |
| 2 | 1232 Alberta Road | 5553312 | jo@hotmail.ru | 1968-03-02 | M | Y | Jane Van | 3 |
| 3 | 90 Potter A | 3331211 | gp@ymail.ru | 1967-09-22 | M | N | Sandhya Pil | 2 |
| 4 | 202, Donna Street | 7176167 | twink@hotmail.ru | 1976-08-09 | F | Y | Manish Sha | NULL |
| 5 | Apartment #8, UBC, Van Street | 8973242 | holy@ymail.ru | 1974-10-14 | F | N | NULL | NULL |
| 6 | 46 SFU Street | 6451234 | kill@el.ru | 1978-12-31 | M | N | NULL | NULL |
| 7 | 432 Mercury Ave | 7932232 | mac@hotmail.ru | 1966-08-21 | M | Y | Mary Shelly | 3 |
| 8 | 8 Little YaleTown | 5442994 | edd@gmail.ru | 1975-01-14 | M | N | NULL | NULL |
| 9 | 64 Temp Road | 4327652 | nan@pmail.ru | 1969-05-19 | M | Y | Man Nanda | 1 |
| 10 | 132 Metro House, Henry Street | 5552376 | ra@hotmail.ru | 1968-07-06 | M | N | NULL | NULL |
| 11 | 1 Grace Town, Van Avenue | 5433879 | soundofsilence@boxer.net | 1957-11-04 | M | Y | Muriel Lovelace | 4 |
| 12 | 97 Oakland Road | 5423311 | kingarthur@roundtable.org | 1968-02-15 | M | Y | Rina Brighton | 3 |
| 13 | 543 Applegate Lane | 3434343 | levy@cmail.ru | 1968-09-03 | F | Y | Matt Shi | 2 |
| 14 | 76 Fish Street | 7432433 | tink@email.ru | 1965-04-28 | M | N | NULL | NULL |
| 15 | 98 Gun Street | 6500787 | danny@fhardy.ru | 1966-06-23 | M | Y | Betty Cudly | 3 |
| 16 | #5 Winnepag Homes | 5433243 | mike@cmail.ru | 1964-03-06 | M | Y | Stella Stevens | 2 |
| 17 | 652 Devon Building, 6th Jade Avenue | 5537885 | mona@darling.ru | 1970-04-18 | F | Y | Edgar Alan | 1 |
| 18 | Apartment #9, Together Towers | 5476565 | odessey@hotmail.ru | 1973-10-09 | M | N | NULL | NULL |
| 19 | Apartment #9, West Towers | 5476565 | jire@hotmail.ru | 1973-01-20 | M | N | NULL | NULL |
| 20 | 90 Yale Town | 7528326 | help@more.org | 1968-01-25 | F | N | NULL | NULL |
| 21 | 4329 Eucalyptus Avenue | 4254863 | money@cold.ru | 1964-06-13 | M | Y | Ruby Richer | 2 |
+----+-------------------------------------+---------+---------------------------+------------+------+----------+-----------------+----------+
21 rows in set (0.06 sec)
mysql> select children, count(*) AS
-> number from employee_person
-> GROUP BY children
-> ORDER BY number DESC;
+----------+--------+
| children | number |
+----------+--------+
| NULL | 10 |
| 3 | 4 |
| 2 | 4 |
| 1 | 2 |
| 4 | 1 |
+----------+--------+
5 rows in set (0.00 sec)
*/
Drop table employee_person;
CREATE TABLE employee_person (
id int unsigned not null primary key,
address varchar(60),
phone int,
email varchar(60),
birthday DATE,
sex ENUM("M", "F"),
m_status ENUM("Y","N"),
s_name varchar(40),
children int
);
INSERT INTO employee_person (id, address, phone, email, birthday, sex, m_status, s_name) values (1, "200, Regina Street", 7176666, "net@hotmail.ru", "1971-04-26", "M", "Y", "Ane Regina");
INSERT INTO employee_person (id, address, phone, email, birthday, sex, m_status, s_name, children) values (2, "1232 Alberta Road", 5553312, "jo@hotmail.ru", "1968-03-02", "M", "Y", "Jane Van", 3);
INSERT INTO employee_person (id, address, phone, email, birthday, sex, m_status, s_name, children) values (3, "90 Potter A", 3331211, "gp@ymail.ru", "1967-09-22", "M", "N", "Sandhya Pil", 2);
INSERT INTO employee_person (id, address, phone, email, birthday, sex, m_status, s_name) values (4, "202, Donna Street", 7176167, "twink@hotmail.ru", "1976-08-09", "F", "Y", "Manish Sha");
INSERT INTO employee_person (id, address, phone, email, birthday, sex, m_status) values (5, "Apartment #8, UBC, Van Street", 8973242, "holy@ymail.ru", "1974-10-14", "F", "N");
INSERT INTO employee_person (id, address, phone, email, birthday, sex, m_status) values (6, "46 SFU Street", "6451234", "kill@el.ru", "1978-12-31", "M", "N");
INSERT INTO employee_person (id, address, phone, email, birthday, sex, m_status, s_name, children) values (7, "432 Mercury Ave", 7932232, "mac@hotmail.ru", "1966-8-21", "M", "Y", "Mary Shelly", "3");
INSERT INTO employee_person (id, address, phone, email, birthday, sex, m_status) values (8, "8 Little YaleTown", 5442994, "edd@gmail.ru", "1975-01-14", "M", "N");
INSERT INTO employee_person (id, address, phone, email, birthday, sex, m_status, s_name, children) values (9, "64 Temp Road", 4327652, "nan@pmail.ru", "1969-05-19", "M", "Y", "Man Nanda", "1");
INSERT INTO employee_person (id, address, phone, email, birthday, sex, m_status) values (10, "132 Metro House, Henry Street", 5552376, "ra@hotmail.ru", "1968-07-06", "M", "N");
INSERT INTO employee_person (id, address, phone, email, birthday, sex, m_status, s_name, children) values (11, "1 Grace Town, Van Avenue", 5433879, "soundofsilence@boxer.net", "1957-11-04", "M", "Y", "Muriel Lovelace", "4");
INSERT INTO employee_person (id, address, phone, email, birthday, sex, m_status, s_name, children) values (12, "97 Oakland Road", 5423311, "kingarthur@roundtable.org", "1968-02-15", "M", "Y", "Rina Brighton", 3);
INSERT INTO employee_person (id, address, phone, email, birthday, sex, m_status, s_name, children) values (13, "543 Applegate Lane", 3434343, "levy@cmail.ru", "1968-09-03", "F", "Y", "Matt Shi", "2");
INSERT INTO employee_person (id, address, phone, email, birthday, sex, m_status) values (14, "76 Fish Street", 7432433, "tink@email.ru", "1965-04-28", "M", "N");
INSERT INTO employee_person (id, address, phone, email, birthday, sex, m_status, s_name, children) values (15, "98 Gun Street", 6500787, "danny@fhardy.ru", "1966-06-23", "M", "Y", "Betty Cudly", 3);
INSERT INTO employee_person (id, address, phone, email, birthday, sex, m_status, s_name, children) values (16, "#5 Winnepag Homes", 5433243, "mike@cmail.ru", "1964-03-06", "M", "Y", "Stella Stevens", 2);
INSERT INTO employee_person (id, address, phone, email, birthday, sex, m_status, s_name, children) values (17, "652 Devon Building, 6th Jade Avenue", 5537885, "mona@darling.ru", "1970-04-18", "F", "Y", "Edgar Alan", 1);
INSERT INTO employee_person (id, address, phone, email, birthday, sex, m_status) values (18, "Apartment #9, Together Towers", 5476565, "odessey@hotmail.ru", "1973-10-09", "M", "N");
INSERT INTO employee_person (id, address, phone, email, birthday, sex, m_status) values (19, "Apartment #9, West Towers", 5476565, "jire@hotmail.ru", "1973-1-20", "M", "N");
INSERT INTO employee_person (id, address, phone, email, birthday, sex, m_status) values (20, "90 Yale Town", 7528326, "help@more.org", "1968-01-25", "F", "N");
INSERT INTO employee_person (id, address, phone, email, birthday, sex, m_status, s_name, children) values (21, "4329 Eucalyptus Avenue", 4254863, "money@cold.ru", "1964-06-13", "M", "Y", "Ruby Richer", 2);
select * from employee_person;
select children, count(*) AS
number from employee_person
GROUP BY children
ORDER BY number DESC;
GROUP BY with order and HAVING
/*
mysql> select * from sales;
+-----+------------+--------+--------+--------+------+------------+
| num | name | winter | spring | summer | fall | category |
+-----+------------+--------+--------+--------+------+------------+
| 1 | Java | 1067 | 200 | 150 | 267 | Holiday |
| 2 | C | 970 | 770 | 531 | 486 | Profession |
| 3 | JavaScript | 53 | 13 | 21 | 856 | Literary |
| 4 | SQL | 782 | 357 | 168 | 250 | Profession |
| 5 | Oracle | 589 | 795 | 367 | 284 | Holiday |
| 6 | MySQL | 953 | 582 | 336 | 489 | Literary |
| 7 | Cplus | 752 | 657 | 259 | 478 | Literary |
| 8 | Python | 67 | 23 | 83 | 543 | Holiday |
| 9 | PHP | 673 | 48 | 625 | 52 | Profession |
+-----+------------+--------+--------+--------+------+------------+
9 rows in set (0.00 sec)
mysql> /* Using the following SELECT command with WHERE, GROUP BY and HAVING cla
uses, list the design_name or names in the Literary design_category that have wi
nter_sales over 700, in order of most sales to least sales.
mysql> */
mysql> SELECT name, category, winter
-> FROM sales
-> WHERE category="Literary"
-> GROUP BY winter DESC HAVING winter > 700;
+-------+----------+--------+
| name | category | winter |
+-------+----------+--------+
| MySQL | Literary | 953 |
| Cplus | Literary | 752 |
+-------+----------+--------+
2 rows in set (0.00 sec)
*/
Drop table sales;
CREATE TABLE sales(
num MEDIUMINT NOT NULL AUTO_INCREMENT,
name CHAR(20),
winter INT,
spring INT,
summer INT,
fall INT,
category CHAR(13),
primary key(num)
)type=MyISAM;
insert into sales value(1, "Java", 1067 , 200, 150, 267,"Holiday");
insert into sales value(2, "C",970,770,531,486,"Profession");
insert into sales value(3, "JavaScript",53,13,21,856,"Literary");
insert into sales value(4, "SQL",782,357,168,250,"Profession");
insert into sales value(5, "Oracle",589,795,367,284,"Holiday");
insert into sales value(6, "MySQL",953,582,336,489,"Literary");
insert into sales value(7, "Cplus",752,657,259,478,"Literary");
insert into sales value(8, "Python",67,23,83,543,"Holiday");
insert into sales value(9, "PHP",673,48,625,52,"Profession");
select * from sales;
/* Using the following SELECT command with WHERE, GROUP BY and HAVING clauses, list the design_name or names in the Literary design_category that have winter_sales over 700, in order of most sales to least sales.
*/
SELECT name, category, winter
FROM sales
WHERE category="Literary"
GROUP BY winter DESC HAVING winter > 700;
Grouping Data: 03 Using the HAVING Clause 1
/*
mysql> Select * from StudentExam;
+-----------+------+------------+
| StudentID | Mark | Comments |
+-----------+------+------------+
| 10 | 76 | Java |
| 10 | 65 | C# |
| 10 | 79 | JavaScript |
| 11 | 66 | Java |
| 11 | 85 | C# |
| 11 | 69 | JavaScript |
+-----------+------+------------+
6 rows in set (0.00 sec)
mysql> /* Real command */
mysql> SELECT StudentID, AVG(Mark) AS AverageMark
-> FROM StudentExam
-> GROUP BY StudentID
-> HAVING AVG(Mark) < 50 OR AVG(Mark) > 70;
+-----------+-------------+
| StudentID | AverageMark |
+-----------+-------------+
| 10 | 73.3333 |
| 11 | 73.3333 |
+-----------+-------------+
2 rows in set (0.01 sec)
*/
/* Create table */
Drop TABLE StudentExam;
CREATE TABLE StudentExam (
StudentID INT NOT NULL,
Mark INT,
Comments VARCHAR(255)
)TYPE = InnoDB;
/* Insert data */
INSERT INTO StudentExam (StudentID,Mark,Comments) VALUES (10,76,"Java");
INSERT INTO StudentExam (StudentID,Mark,Comments) VALUES (10,65,"C#");
INSERT INTO StudentExam (StudentID,Mark,Comments) VALUES (10,79,"JavaScript");
INSERT INTO StudentExam (StudentID,Mark,Comments) VALUES (11,66,"Java");
INSERT INTO StudentExam (StudentID,Mark,Comments) VALUES (11,85,"C#");
INSERT INTO StudentExam (StudentID,Mark,Comments) VALUES (11,69,"JavaScript");
Select * from StudentExam;
/* Real command */
SELECT StudentID, AVG(Mark) AS AverageMark
FROM StudentExam
GROUP BY StudentID
HAVING AVG(Mark) < 50 OR AVG(Mark) > 70;
Grouping Data: Filtering Group Data
/*
mysql> Select * from StudentExam;
+-----------+------+------------+
| StudentID | Mark | Comments |
+-----------+------+------------+
| 10 | 76 | Java |
| 10 | 65 | C# |
| 10 | 79 | JavaScript |
| 11 | 66 | Java |
| 11 | 85 | C# |
| 11 | 69 | JavaScript |
+-----------+------+------------+
6 rows in set (0.00 sec)
mysql> /* Real command */
mysql> SELECT StudentID, COUNT(*) AS HighPasses
-> FROM StudentExam
-> WHERE Mark > 70
-> GROUP BY StudentID;
+-----------+------------+
| StudentID | HighPasses |
+-----------+------------+
| 10 | 2 |
| 11 | 1 |
+-----------+------------+
2 rows in set (0.04 sec)
*/
/* Create table */
Drop TABLE StudentExam;
CREATE TABLE StudentExam (
StudentID INT NOT NULL,
Mark INT,
Comments VARCHAR(255)
)TYPE = InnoDB;
/* Insert data */
INSERT INTO StudentExam (StudentID,Mark,Comments) VALUES (10,76,"Java");
INSERT INTO StudentExam (StudentID,Mark,Comments) VALUES (10,65,"C#");
INSERT INTO StudentExam (StudentID,Mark,Comments) VALUES (10,79,"JavaScript");
INSERT INTO StudentExam (StudentID,Mark,Comments) VALUES (11,66,"Java");
INSERT INTO StudentExam (StudentID,Mark,Comments) VALUES (11,85,"C#");
INSERT INTO StudentExam (StudentID,Mark,Comments) VALUES (11,69,"JavaScript");
Select * from StudentExam;
/* Real command */
SELECT StudentID, COUNT(*) AS HighPasses
FROM StudentExam
WHERE Mark > 70
GROUP BY StudentID;
Grouping Data: Using the HAVING Clause 1
/* Create table */
Drop TABLE StudentExam;
CREATE TABLE StudentExam (
StudentID INT NOT NULL,
Mark INT,
Comments VARCHAR(255)
)TYPE = InnoDB;
/* Insert data */
INSERT INTO StudentExam (StudentID,Mark,Comments) VALUES (10,76,"Java");
INSERT INTO StudentExam (StudentID,Mark,Comments) VALUES (10,65,"C#");
INSERT INTO StudentExam (StudentID,Mark,Comments) VALUES (10,79,"JavaScript");
INSERT INTO StudentExam (StudentID,Mark,Comments) VALUES (11,66,"Java");
INSERT INTO StudentExam (StudentID,Mark,Comments) VALUES (11,85,"C#");
INSERT INTO StudentExam (StudentID,Mark,Comments) VALUES (11,69,"JavaScript");
Select * from StudentExam;
/* Real command */
SELECT StudentID, AVG(Mark) AS AverageMark
FROM StudentExam
WHERE ExamID IN ( 5, 8, 11 )
GROUP BY StudentID
HAVING AVG(Mark) < 50 OR AVG(Mark) > 70;
GROUP value and count
/*
mysql> select * from employee_person;
+----+-------------------------------------+---------+---------------------------+------------+------+----------+-----------------+----------+
| id | address | phone | email | birthday | sex | m_status | s_name | children |
+----+-------------------------------------+---------+---------------------------+------------+------+----------+-----------------+----------+
| 1 | 200, Regina Street | 7176666 | net@hotmail.ru | 1971-04-26 | M | Y | Ane Regina | NULL |
| 2 | 1232 Alberta Road | 5553312 | jo@hotmail.ru | 1968-03-02 | M | Y | Jane Van | 3 |
| 3 | 90 Potter A | 3331211 | gp@ymail.ru | 1967-09-22 | M | N | Sandhya Pil | 2 |
| 4 | 202, Donna Street | 7176167 | twink@hotmail.ru | 1976-08-09 | F | Y | Manish Sha | NULL |
| 5 | Apartment #8, UBC, Van Street | 8973242 | holy@ymail.ru | 1974-10-14 | F | N | NULL | NULL |
| 6 | 46 SFU Street | 6451234 | kill@el.ru | 1978-12-31 | M | N | NULL | NULL |
| 7 | 432 Mercury Ave | 7932232 | mac@hotmail.ru | 1966-08-21 | M | Y | Mary Shelly | 3 |
| 8 | 8 Little YaleTown | 5442994 | edd@gmail.ru | 1975-01-14 | M | N | NULL | NULL |
| 9 | 64 Temp Road | 4327652 | nan@pmail.ru | 1969-05-19 | M | Y | Man Nanda | 1 |
| 10 | 132 Metro House, Henry Street | 5552376 | ra@hotmail.ru | 1968-07-06 | M | N | NULL | NULL |
| 11 | 1 Grace Town, Van Avenue | 5433879 | soundofsilence@boxer.net | 1957-11-04 | M | Y | Muriel Lovelace | 4 |
| 12 | 97 Oakland Road | 5423311 | kingarthur@roundtable.org | 1968-02-15 | M | Y | Rina Brighton | 3 |
| 13 | 543 Applegate Lane | 3434343 | levy@cmail.ru | 1968-09-03 | F | Y | Matt Shi | 2 |
| 14 | 76 Fish Street | 7432433 | tink@email.ru | 1965-04-28 | M | N | NULL | NULL |
| 15 | 98 Gun Street | 6500787 | danny@fhardy.ru | 1966-06-23 | M | Y | Betty Cudly | 3 |
| 16 | #5 Winnepag Homes | 5433243 | mike@cmail.ru | 1964-03-06 | M | Y | Stella Stevens | 2 |
| 17 | 652 Devon Building, 6th Jade Avenue | 5537885 | mona@darling.ru | 1970-04-18 | F | Y | Edgar Alan | 1 |
| 18 | Apartment #9, Together Towers | 5476565 | odessey@hotmail.ru | 1973-10-09 | M | N | NULL | NULL |
| 19 | Apartment #9, West Towers | 5476565 | jire@hotmail.ru | 1973-01-20 | M | N | NULL | NULL |
| 20 | 90 Yale Town | 7528326 | help@more.org | 1968-01-25 | F | N | NULL | NULL |
| 21 | 4329 Eucalyptus Avenue | 4254863 | money@cold.ru | 1964-06-13 | M | Y | Ruby Richer | 2 |
+----+-------------------------------------+---------+---------------------------+------------+------+----------+-----------------+----------+
21 rows in set (0.01 sec)
mysql> select sex, count(*)
-> from employee_person
-> GROUP BY sex;
+------+----------+
| sex | count(*) |
+------+----------+
| M | 16 |
| F | 5 |
+------+----------+
2 rows in set (0.00 sec)
*/
Drop table employee_person;
CREATE TABLE employee_person (
id int unsigned not null primary key,
address varchar(60),
phone int,
email varchar(60),
birthday DATE,
sex ENUM("M", "F"),
m_status ENUM("Y","N"),
s_name varchar(40),
children int
);
INSERT INTO employee_person (id, address, phone, email, birthday, sex, m_status, s_name) values (1, "200, Regina Street", 7176666, "net@hotmail.ru", "1971-04-26", "M", "Y", "Ane Regina");
INSERT INTO employee_person (id, address, phone, email, birthday, sex, m_status, s_name, children) values (2, "1232 Alberta Road", 5553312, "jo@hotmail.ru", "1968-03-02", "M", "Y", "Jane Van", 3);
INSERT INTO employee_person (id, address, phone, email, birthday, sex, m_status, s_name, children) values (3, "90 Potter A", 3331211, "gp@ymail.ru", "1967-09-22", "M", "N", "Sandhya Pil", 2);
INSERT INTO employee_person (id, address, phone, email, birthday, sex, m_status, s_name) values (4, "202, Donna Street", 7176167, "twink@hotmail.ru", "1976-08-09", "F", "Y", "Manish Sha");
INSERT INTO employee_person (id, address, phone, email, birthday, sex, m_status) values (5, "Apartment #8, UBC, Van Street", 8973242, "holy@ymail.ru", "1974-10-14", "F", "N");
INSERT INTO employee_person (id, address, phone, email, birthday, sex, m_status) values (6, "46 SFU Street", "6451234", "kill@el.ru", "1978-12-31", "M", "N");
INSERT INTO employee_person (id, address, phone, email, birthday, sex, m_status, s_name, children) values (7, "432 Mercury Ave", 7932232, "mac@hotmail.ru", "1966-8-21", "M", "Y", "Mary Shelly", "3");
INSERT INTO employee_person (id, address, phone, email, birthday, sex, m_status) values (8, "8 Little YaleTown", 5442994, "edd@gmail.ru", "1975-01-14", "M", "N");
INSERT INTO employee_person (id, address, phone, email, birthday, sex, m_status, s_name, children) values (9, "64 Temp Road", 4327652, "nan@pmail.ru", "1969-05-19", "M", "Y", "Man Nanda", "1");
INSERT INTO employee_person (id, address, phone, email, birthday, sex, m_status) values (10, "132 Metro House, Henry Street", 5552376, "ra@hotmail.ru", "1968-07-06", "M", "N");
INSERT INTO employee_person (id, address, phone, email, birthday, sex, m_status, s_name, children) values (11, "1 Grace Town, Van Avenue", 5433879, "soundofsilence@boxer.net", "1957-11-04", "M", "Y", "Muriel Lovelace", "4");
INSERT INTO employee_person (id, address, phone, email, birthday, sex, m_status, s_name, children) values (12, "97 Oakland Road", 5423311, "kingarthur@roundtable.org", "1968-02-15", "M", "Y", "Rina Brighton", 3);
INSERT INTO employee_person (id, address, phone, email, birthday, sex, m_status, s_name, children) values (13, "543 Applegate Lane", 3434343, "levy@cmail.ru", "1968-09-03", "F", "Y", "Matt Shi", "2");
INSERT INTO employee_person (id, address, phone, email, birthday, sex, m_status) values (14, "76 Fish Street", 7432433, "tink@email.ru", "1965-04-28", "M", "N");
INSERT INTO employee_person (id, address, phone, email, birthday, sex, m_status, s_name, children) values (15, "98 Gun Street", 6500787, "danny@fhardy.ru", "1966-06-23", "M", "Y", "Betty Cudly", 3);
INSERT INTO employee_person (id, address, phone, email, birthday, sex, m_status, s_name, children) values (16, "#5 Winnepag Homes", 5433243, "mike@cmail.ru", "1964-03-06", "M", "Y", "Stella Stevens", 2);
INSERT INTO employee_person (id, address, phone, email, birthday, sex, m_status, s_name, children) values (17, "652 Devon Building, 6th Jade Avenue", 5537885, "mona@darling.ru", "1970-04-18", "F", "Y", "Edgar Alan", 1);
INSERT INTO employee_person (id, address, phone, email, birthday, sex, m_status) values (18, "Apartment #9, Together Towers", 5476565, "odessey@hotmail.ru", "1973-10-09", "M", "N");
INSERT INTO employee_person (id, address, phone, email, birthday, sex, m_status) values (19, "Apartment #9, West Towers", 5476565, "jire@hotmail.ru", "1973-1-20", "M", "N");
INSERT INTO employee_person (id, address, phone, email, birthday, sex, m_status) values (20, "90 Yale Town", 7528326, "help@more.org", "1968-01-25", "F", "N");
INSERT INTO employee_person (id, address, phone, email, birthday, sex, m_status, s_name, children) values (21, "4329 Eucalyptus Avenue", 4254863, "money@cold.ru", "1964-06-13", "M", "Y", "Ruby Richer", 2);
select * from employee_person;
select sex, count(*)
from employee_person
GROUP BY sex;
Simple GROUP BY
/*
mysql> select * from employee;
+----+-----------+----------+----------------------------+------+---------------+--------+-------+---------------------+
| id | firstname | lastname | title | age | yearofservice| salary | perks | email |
+----+-----------+----------+----------------------------+------+---------------+--------+-------+---------------------+
| 1 | John | Chen | Senior Programmer | 31 | 3| 120000 | 25000 | j@hotmail.ru |
| 2 | Jan | Pillai | Senior Programmer | 32 | 4| 110000 | 20000 | g@yahoo.ru |
| 3 | Ane | Pandit | Web Designer | 24 | 3| 90000 | 15000 | a@gmail.ru |
| 4 | Mary | Anchor | Web Designer | 27 | 2| 85000 | 15000 | m@mail.ru |
| 5 | Fred | King | Programmer | 32 | 3| 75000 | 15000 | f@net.ru |
| 6 | John | Mac | Programmer | 32 | 4| 80000 | 16000 | j@hotmail.ru |
| 7 | Arthur | Sam | Programmer | 28 | 2| 75000 | 14000 | e@yahoo.ru |
| 8 | Alok | Nanda | Programmer | 32 | 3| 70000 | 10000 | a@yahoo.ru |
| 9 | Susan | Ra | Multimedia Programmer | 32 | 4| 90000 | 15000 | h@gmail.ru |
| 10 | Paul | Simon | Multimedia Programmer | 23 | 1| 85000 | 12000 | ps@gmail.ru |
| 11 | Edward | Parhar | Multimedia Programmer | 30 | 2| 75000 | 15000 | a@hotmail.ru |
| 12 | Kim | Hunter | Senior Web Designer | 32 | 4| 110000 | 20000 | kim@coolmail.ru |
| 13 | Roger | Lewis | System Administrator | 32 | 3| 100000 | 13000 | roger@mail.ru |
| 14 | Danny | Gibson | System Administrator | 31 | 2| 90000 | 12000 | danny@hotmail.ru |
| 15 | Mike | Harper | Senior Marketing Executive | 36 | 1| 120000 | 28000 | m@gmail.ru |
| 16 | Mary | Sunday | Marketing Executive | 31 | 5| 90000 | 25000 | monica@bigmail.ru |
| 17 | Jack | Sim | Marketing Executive | 27 | 1| 70000 | 18000 | hal@gmail.ru |
| 18 | Joe | Irvine | Marketing Executive | 27 | 1| 72000 | 18000 | joseph@hotmail.ru |
| 19 | Henry | Ali | Customer Service Manager | 32 | 3| 70000 | 9000 | shahida@hotmail.ru |
| 20 | Peter | Champion | Finance Manager | 32 | 2| 120000 | 25000 | peter@yahoo.ru |
+----+-----------+----------+----------------------------+------+---------------+--------+-------+---------------------+
20 rows in set (0.02 sec)
mysql> select title from employee
-> GROUP BY title;
+----------------------------+
| title |
+----------------------------+
| Customer Service Manager |
| Finance Manager |
| Marketing Executive |
| Multimedia Programmer |
| Programmer |
| Senior Marketing Executive |
| Senior Programmer |
| Senior Web Designer |
| System Administrator |
| Web Designer |
+----------------------------+
10 rows in set (0.00 sec)
*/
Drop table employee;
CREATE TABLE employee (
id int unsigned not null auto_increment primary key,
firstname varchar(20),
lastname varchar(20),
title varchar(30),
age int,
yearofservice int,
salary int,
perks int,
email varchar(60)
);
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("John", "Chen", "Senior Programmer", 31, 3, 120000, 25000, "j@hotmail.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Jan", "Pillai", "Senior Programmer", 32, 4, 110000, 20000, "g@yahoo.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Ane", "Pandit", "Web Designer", 24, 3, 90000, 15000, "a@gmail.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Mary", "Anchor", "Web Designer", 27, 2, 85000, 15000, "m@mail.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Fred", "King", "Programmer", 32, 3, 75000, 15000, "f@net.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("John", "Mac", "Programmer", 32, 4, 80000, 16000, "j@hotmail.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Arthur", "Sam", "Programmer", 28, 2, 75000, 14000, "e@yahoo.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Alok", "Nanda", "Programmer", 32, 3, 70000, 10000, "a@yahoo.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Susan", "Ra", "Multimedia Programmer", 32, 4, 90000, 15000, "h@gmail.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Paul", "Simon", "Multimedia Programmer", 23, 1, 85000, 12000, "ps@gmail.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Edward", "Parhar", "Multimedia Programmer", 30, 2, 75000, 15000, "a@hotmail.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Kim", "Hunter", "Senior Web Designer", 32, 4, 110000, 20000, "kim@coolmail.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Roger", "Lewis", "System Administrator", 32, 3, 100000, 13000, "roger@mail.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Danny", "Gibson", "System Administrator", 31, 2, 90000, 12000, "danny@hotmail.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Mike", "Harper", "Senior Marketing Executive", 36, 1, 120000, 28000, "m@gmail.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Mary", "Sunday", "Marketing Executive", 31, 5, 90000, 25000, "monica@bigmail.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Jack", "Sim", "Marketing Executive", 27, 1, 70000, 18000, "hal@gmail.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Joe", "Irvine", "Marketing Executive", 27, 1, 72000, 18000, "joseph@hotmail.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Henry", "Ali", "Customer Service Manager", 32, 3, 70000, 9000, "shahida@hotmail.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Peter", "Champion", "Finance Manager", 32, 2, 120000, 25000, "peter@yahoo.ru");
select * from employee;
select title from employee
GROUP BY title;
Use GROUP BY
Drop table sales;
CREATE TABLE sales(
num MEDIUMINT NOT NULL AUTO_INCREMENT,
name CHAR(20),
winter INT,
spring INT,
summer INT,
fall INT,
category CHAR(13),
primary key(num)
)type=MyISAM;
insert into sales value(1, "Java", 1067 , 200, 150, 267,"Holiday");
insert into sales value(2, "C",970,770,531,486,"Profession");
insert into sales value(3, "JavaScript",53,13,21,856,"Literary");
insert into sales value(4, "SQL",782,357,168,250,"Profession");
insert into sales value(5, "Oracle",589,795,367,284,"Holiday");
insert into sales value(6, "MySQL",953,582,336,489,"Literary");
insert into sales value(7, "Cplus",752,657,259,478,"Literary");
insert into sales value(8, "Python",67,23,83,543,"Holiday");
insert into sales value(9, "PHP",673,48,625,52,"Profession");
select * from sales;
/*Change the GROUP BY field to cust_city, to list all the unique cities and their states, including both cities from CA.
*/
SELECT * FROM sales
GROUP BY catagory;
Use GROUP BY 2
/*
mysql> select * from employee;
+----+-----------+----------+----------------------------+------+---------------+--------+-------+---------------------+
| id | firstname | lastname | title | age | yearofservice| salary | perks | email |
+----+-----------+----------+----------------------------+------+---------------+--------+-------+---------------------+
| 1 | John | Chen | Senior Programmer | 31 | 3| 120000 | 25000 | j@hotmail.ru |
| 2 | Jan | Pillai | Senior Programmer | 32 | 4| 110000 | 20000 | g@yahoo.ru |
| 3 | Ane | Pandit | Web Designer | 24 | 3| 90000 | 15000 | a@gmail.ru |
| 4 | Mary | Anchor | Web Designer | 27 | 2| 85000 | 15000 | m@mail.ru |
| 5 | Fred | King | Programmer | 32 | 3| 75000 | 15000 | f@net.ru |
| 6 | John | Mac | Programmer | 32 | 4| 80000 | 16000 | j@hotmail.ru |
| 7 | Arthur | Sam | Programmer | 28 | 2| 75000 | 14000 | e@yahoo.ru |
| 8 | Alok | Nanda | Programmer | 32 | 3| 70000 | 10000 | a@yahoo.ru |
| 9 | Susan | Ra | Multimedia Programmer | 32 | 4| 90000 | 15000 | h@gmail.ru |
| 10 | Paul | Simon | Multimedia Programmer | 23 | 1| 85000 | 12000 | ps@gmail.ru |
| 11 | Edward | Parhar | Multimedia Programmer | 30 | 2| 75000 | 15000 | a@hotmail.ru |
| 12 | Kim | Hunter | Senior Web Designer | 32 | 4| 110000 | 20000 | kim@coolmail.ru |
| 13 | Roger | Lewis | System Administrator | 32 | 3| 100000 | 13000 | roger@mail.ru |
| 14 | Danny | Gibson | System Administrator | 31 | 2| 90000 | 12000 | danny@hotmail.ru |
| 15 | Mike | Harper | Senior Marketing Executive | 36 | 1| 120000 | 28000 | m@gmail.ru |
| 16 | Mary | Sunday | Marketing Executive | 31 | 5| 90000 | 25000 | monica@bigmail.ru |
| 17 | Jack | Sim | Marketing Executive | 27 | 1| 70000 | 18000 | hal@gmail.ru |
| 18 | Joe | Irvine | Marketing Executive | 27 | 1| 72000 | 18000 | joseph@hotmail.ru |
| 19 | Henry | Ali | Customer Service Manager | 32 | 3| 70000 | 9000 | shahida@hotmail.ru |
| 20 | Peter | Champion | Finance Manager | 32 | 2| 120000 | 25000 | peter@yahoo.ru |
+----+-----------+----------+----------------------------+------+---------------+--------+-------+---------------------+
20 rows in set (0.01 sec)
mysql> select title, AVG(salary)
-> from employee
-> GROUP BY title;
+----------------------------+-------------+
| title | AVG(salary) |
+----------------------------+-------------+
| Customer Service Manager | 70000.0000 |
| Finance Manager | 120000.0000 |
| Marketing Executive | 77333.3333 |
| Multimedia Programmer | 83333.3333 |
| Programmer | 75000.0000 |
| Senior Marketing Executive | 120000.0000 |
| Senior Programmer | 115000.0000 |
| Senior Web Designer | 110000.0000 |
| System Administrator | 95000.0000 |
| Web Designer | 87500.0000 |
+----------------------------+-------------+
10 rows in set (0.00 sec)
*/
Drop table employee;
CREATE TABLE employee (
id int unsigned not null auto_increment primary key,
firstname varchar(20),
lastname varchar(20),
title varchar(30),
age int,
yearofservice int,
salary int,
perks int,
email varchar(60)
);
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("John", "Chen", "Senior Programmer", 31, 3, 120000, 25000, "j@hotmail.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Jan", "Pillai", "Senior Programmer", 32, 4, 110000, 20000, "g@yahoo.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Ane", "Pandit", "Web Designer", 24, 3, 90000, 15000, "a@gmail.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Mary", "Anchor", "Web Designer", 27, 2, 85000, 15000, "m@mail.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Fred", "King", "Programmer", 32, 3, 75000, 15000, "f@net.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("John", "Mac", "Programmer", 32, 4, 80000, 16000, "j@hotmail.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Arthur", "Sam", "Programmer", 28, 2, 75000, 14000, "e@yahoo.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Alok", "Nanda", "Programmer", 32, 3, 70000, 10000, "a@yahoo.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Susan", "Ra", "Multimedia Programmer", 32, 4, 90000, 15000, "h@gmail.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Paul", "Simon", "Multimedia Programmer", 23, 1, 85000, 12000, "ps@gmail.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Edward", "Parhar", "Multimedia Programmer", 30, 2, 75000, 15000, "a@hotmail.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Kim", "Hunter", "Senior Web Designer", 32, 4, 110000, 20000, "kim@coolmail.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Roger", "Lewis", "System Administrator", 32, 3, 100000, 13000, "roger@mail.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Danny", "Gibson", "System Administrator", 31, 2, 90000, 12000, "danny@hotmail.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Mike", "Harper", "Senior Marketing Executive", 36, 1, 120000, 28000, "m@gmail.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Mary", "Sunday", "Marketing Executive", 31, 5, 90000, 25000, "monica@bigmail.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Jack", "Sim", "Marketing Executive", 27, 1, 70000, 18000, "hal@gmail.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Joe", "Irvine", "Marketing Executive", 27, 1, 72000, 18000, "joseph@hotmail.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Henry", "Ali", "Customer Service Manager", 32, 3, 70000, 9000, "shahida@hotmail.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Peter", "Champion", "Finance Manager", 32, 2, 120000, 25000, "peter@yahoo.ru");
select * from employee;
select title, AVG(salary)
from employee
GROUP BY title;
Use GROUP BY and ORDER BY together
/*mysql> select * from employee;
+----+-----------+----------+----------------------------+------+---------------+--------+-------+---------------------+
| id | firstname | lastname | title | age | yearofservice| salary | perks | email |
+----+-----------+----------+----------------------------+------+---------------+--------+-------+---------------------+
| 1 | John | Chen | Senior Programmer | 31 | 3| 120000 | 25000 | j@hotmail.ru |
| 2 | Jan | Pillai | Senior Programmer | 32 | 4| 110000 | 20000 | g@yahoo.ru |
| 3 | Ane | Pandit | Web Designer | 24 | 3| 90000 | 15000 | a@gmail.ru |
| 4 | Mary | Anchor | Web Designer | 27 | 2| 85000 | 15000 | m@mail.ru |
| 5 | Fred | King | Programmer | 32 | 3| 75000 | 15000 | f@net.ru |
| 6 | John | Mac | Programmer | 32 | 4| 80000 | 16000 | j@hotmail.ru |
| 7 | Arthur | Sam | Programmer | 28 | 2| 75000 | 14000 | e@yahoo.ru |
| 8 | Alok | Nanda | Programmer | 32 | 3| 70000 | 10000 | a@yahoo.ru |
| 9 | Susan | Ra | Multimedia Programmer | 32 | 4| 90000 | 15000 | h@gmail.ru |
| 10 | Paul | Simon | Multimedia Programmer | 23 | 1| 85000 | 12000 | ps@gmail.ru |
| 11 | Edward | Parhar | Multimedia Programmer | 30 | 2| 75000 | 15000 | a@hotmail.ru |
| 12 | Kim | Hunter | Senior Web Designer | 32 | 4| 110000 | 20000 | kim@coolmail.ru |
| 13 | Roger | Lewis | System Administrator | 32 | 3| 100000 | 13000 | roger@mail.ru |
| 14 | Danny | Gibson | System Administrator | 31 | 2| 90000 | 12000 | danny@hotmail.ru |
| 15 | Mike | Harper | Senior Marketing Executive | 36 | 1| 120000 | 28000 | m@gmail.ru |
| 16 | Mary | Sunday | Marketing Executive | 31 | 5| 90000 | 25000 | monica@bigmail.ru |
| 17 | Jack | Sim | Marketing Executive | 27 | 1| 70000 | 18000 | hal@gmail.ru |
| 18 | Joe | Irvine | Marketing Executive | 27 | 1| 72000 | 18000 | joseph@hotmail.ru |
| 19 | Henry | Ali | Customer Service Manager | 32 | 3| 70000 | 9000 | shahida@hotmail.ru |
| 20 | Peter | Champion | Finance Manager | 32 | 2| 120000 | 25000 | peter@yahoo.ru |
+----+-----------+----------+----------------------------+------+---------------+--------+-------+---------------------+
20 rows in set (0.00 sec)
mysql> select title, count(*) AS Number
-> from employee
-> GROUP BY title
-> ORDER BY Number;
+----------------------------+--------+
| title | Number |
+----------------------------+--------+
| Customer Service Manager | 1 |
| Finance Manager | 1 |
| Senior Web Designer | 1 |
| Senior Marketing Executive | 1 |
| System Administrator | 2 |
| Senior Programmer | 2 |
| Web Designer | 2 |
| Marketing Executive | 3 |
| Multimedia Programmer | 3 |
| Programmer | 4 |
+----------------------------+--------+
10 rows in set (0.00 sec)
*/
Drop table employee;
CREATE TABLE employee (
id int unsigned not null auto_increment primary key,
firstname varchar(20),
lastname varchar(20),
title varchar(30),
age int,
yearofservice int,
salary int,
perks int,
email varchar(60)
);
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("John", "Chen", "Senior Programmer", 31, 3, 120000, 25000, "j@hotmail.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Jan", "Pillai", "Senior Programmer", 32, 4, 110000, 20000, "g@yahoo.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Ane", "Pandit", "Web Designer", 24, 3, 90000, 15000, "a@gmail.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Mary", "Anchor", "Web Designer", 27, 2, 85000, 15000, "m@mail.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Fred", "King", "Programmer", 32, 3, 75000, 15000, "f@net.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("John", "Mac", "Programmer", 32, 4, 80000, 16000, "j@hotmail.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Arthur", "Sam", "Programmer", 28, 2, 75000, 14000, "e@yahoo.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Alok", "Nanda", "Programmer", 32, 3, 70000, 10000, "a@yahoo.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Susan", "Ra", "Multimedia Programmer", 32, 4, 90000, 15000, "h@gmail.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Paul", "Simon", "Multimedia Programmer", 23, 1, 85000, 12000, "ps@gmail.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Edward", "Parhar", "Multimedia Programmer", 30, 2, 75000, 15000, "a@hotmail.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Kim", "Hunter", "Senior Web Designer", 32, 4, 110000, 20000, "kim@coolmail.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Roger", "Lewis", "System Administrator", 32, 3, 100000, 13000, "roger@mail.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Danny", "Gibson", "System Administrator", 31, 2, 90000, 12000, "danny@hotmail.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Mike", "Harper", "Senior Marketing Executive", 36, 1, 120000, 28000, "m@gmail.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Mary", "Sunday", "Marketing Executive", 31, 5, 90000, 25000, "monica@bigmail.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Jack", "Sim", "Marketing Executive", 27, 1, 70000, 18000, "hal@gmail.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Joe", "Irvine", "Marketing Executive", 27, 1, 72000, 18000, "joseph@hotmail.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Henry", "Ali", "Customer Service Manager", 32, 3, 70000, 9000, "shahida@hotmail.ru");
INSERT INTO employee (firstname, lastName, title, age, yearofservice, salary, perks, email) values ("Peter", "Champion", "Finance Manager", 32, 2, 120000, 25000, "peter@yahoo.ru");
select * from employee;
select title, count(*) AS Number
from employee
GROUP BY title
ORDER BY Number;
Use GROUP BY clause to list only the unique data
/*
mysql> select * from sales;
+-----+------------+--------+--------+--------+------+------------+
| num | name | winter | spring | summer | fall | category |
+-----+------------+--------+--------+--------+------+------------+
| 1 | Java | 1067 | 200 | 150 | 267 | Holiday |
| 2 | C | 970 | 770 | 531 | 486 | Profession |
| 3 | JavaScript | 53 | 13 | 21 | 856 | Literary |
| 4 | SQL | 782 | 357 | 168 | 250 | Profession |
| 5 | Oracle | 589 | 795 | 367 | 284 | Holiday |
| 6 | MySQL | 953 | 582 | 336 | 489 | Literary |
| 7 | Cplus | 752 | 657 | 259 | 478 | Literary |
| 8 | Python | 67 | 23 | 83 | 543 | Holiday |
| 9 | PHP | 673 | 48 | 625 | 52 | Profession |
+-----+------------+--------+--------+--------+------+------------+
9 rows in set (0.01 sec)
mysql> /* Use the following GROUP BY clause to list only the unique states in th
e cust_state column of the duck_cust table.
mysql> */
mysql> SELECT * FROM sales
-> GROUP BY category;
+-----+------------+--------+--------+--------+------+------------+
| num | name | winter | spring | summer | fall | category |
+-----+------------+--------+--------+--------+------+------------+
| 1 | Java | 1067 | 200 | 150 | 267 | Holiday |
| 3 | JavaScript | 53 | 13 | 21 | 856 | Literary |
| 2 | C | 970 | 770 | 531 | 486 | Profession |
+-----+------------+--------+--------+--------+------+------------+
3 rows in set (0.00 sec)
*/
Drop table sales;
CREATE TABLE sales(
num MEDIUMINT NOT NULL AUTO_INCREMENT,
name CHAR(20),
winter INT,
spring INT,
summer INT,
fall INT,
category CHAR(13),
primary key(num)
)type=MyISAM;
insert into sales value(1, "Java", 1067 , 200, 150, 267,"Holiday");
insert into sales value(2, "C",970,770,531,486,"Profession");
insert into sales value(3, "JavaScript",53,13,21,856,"Literary");
insert into sales value(4, "SQL",782,357,168,250,"Profession");
insert into sales value(5, "Oracle",589,795,367,284,"Holiday");
insert into sales value(6, "MySQL",953,582,336,489,"Literary");
insert into sales value(7, "Cplus",752,657,259,478,"Literary");
insert into sales value(8, "Python",67,23,83,543,"Holiday");
insert into sales value(9, "PHP",673,48,625,52,"Profession");
select * from sales;
/* Use the following GROUP BY clause to list only the unique states in the cust_state column of the duck_cust table.
*/
SELECT * FROM sales
GROUP BY category;
Using math function in HAVING
/*
mysql> SELECT OrderID, SUM(Quantity) AS Total
-> FROM ArticleOrders
-> GROUP BY OrderID
-> HAVING Total>(SELECT AVG(Quantity) FROM ArticleOrders);
+---------+-------+
| OrderID | Total |
+---------+-------+
| 101 | 4 |
| 102 | 4 |
| 103 | 6 |
| 105 | 3 |
| 106 | 3 |
| 107 | 3 |
| 108 | 5 |
| 110 | 6 |
| 111 | 2 |
+---------+-------+
9 rows in set (0.05 sec)
*/
Drop table Articles;
Drop table Authors;
Drop table AuthorArticle;
Drop table ArticleOrders;
CREATE TABLE Articles (
ArticleID SMALLINT NOT NULL PRIMARY KEY,
ArticleTitle VARCHAR(60) NOT NULL,
Copyright YEAR NOT NULL
)
ENGINE=INNODB;
INSERT INTO Articles VALUES (12786, "How write a paper", 1934),
(13331, "Publish a paper", 1919),
(14356, "Sell a paper", 1966),
(15729, "Buy a paper", 1932),
(16284, "Conferences", 1996),
(17695, "Journal", 1980),
(19264, "Information", 1992),
(19354, "AI", 1993);
CREATE TABLE Authors (
AuthID SMALLINT NOT NULL PRIMARY KEY,
AuthorFirstName VARCHAR(20),
AuthorMiddleName VARCHAR(20),
AuthorLastName VARCHAR(20)
)
ENGINE=INNODB;
INSERT INTO Authors VALUES (1006, "Henry", "S.", "Thompson"),
(1007, "Jason", "Carol", "Oak"),
(1008, "James", NULL, "Elk"),
(1009, "Tom", "M", "Ride"),
(1010, "Jack", "K", "Ken"),
(1011, "Mary", "G.", "Lee"),
(1012, "Annie", NULL, "Peng"),
(1013, "Alan", NULL, "Wang"),
(1014, "Nelson", NULL, "Yin");
CREATE TABLE AuthorArticle (
AuthID SMALLINT NOT NULL,
ArticleID SMALLINT NOT NULL,
PRIMARY KEY (AuthID, ArticleID),
FOREIGN KEY (AuthID) REFERENCES Authors (AuthID),
FOREIGN KEY (ArticleID) REFERENCES Articles (ArticleID)
)
ENGINE=INNODB;
INSERT INTO AuthorArticle VALUES (1006, 14356),
(1008, 15729),
(1009, 12786),
(1010, 17695),
(1011, 15729),
(1012, 19264),
(1012, 19354),
(1014, 16284);
CREATE TABLE ArticleOrders
(
OrderID SMALLINT NOT NULL,
ArticleID SMALLINT NOT NULL,
Quantity SMALLINT NOT NULL,
PRIMARY KEY (OrderID, ArticleID),
FOREIGN KEY (ArticleID) REFERENCES Articles (ArticleID)
)
ENGINE=INNODB;
INSERT INTO ArticleOrders VALUES (101, 13331, 1),
(101, 12786, 1),
(101, 16284, 2),
(102, 19354, 1),
(102, 15729, 3),
(103, 12786, 2),
(103, 19264, 1),
(103, 13331, 1),
(103, 14356, 2),
(104, 19354, 1),
(105, 15729, 1),
(105, 14356, 2),
(106, 16284, 2),
(106, 13331, 1),
(107, 12786, 3),
(108, 19354, 1),
(108, 16284, 4),
(109, 15729, 1),
(110, 13331, 2),
(110, 12786, 2),
(110, 14356, 2),
(111, 14356, 2);
SELECT OrderID, SUM(Quantity) AS Total
FROM ArticleOrders
GROUP BY OrderID
HAVING Total>(SELECT AVG(Quantity) FROM ArticleOrders);