Oracle PL/SQL Tutorial/Character String Functions/RTRIM — различия между версиями
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Текущая версия на 10:11, 26 мая 2010
Rtrim removes a set of characters from the right of a string
RTRIM stands for "right trim."
The general format for this function is:
RTRIM(string, characters_to_remove)
SQL> SELECT RTRIM("Computers", "s") FROM dual;
RTRIM("C
--------
Computer
SQL>
RTRIM(x [, trim_string]) trim characters from the right of x.
You can supply an optional trim_string that specifies the characters to trim.
If no trim_string is supplied, spaces are trimmed by default.
SQL> SELECT RTRIM("Hi abcabc", "abc") FROM dual;
RTR
---
Hi
SQL>
Trim letter S from both sides
SQL>
SQL> create table emp
2 ( empno NUMBER(4) constraint E_PK primary key
3 , ename VARCHAR2(8)
4 , init VARCHAR2(5)
5 , job VARCHAR2(8)
6 , mgr NUMBER(4)
7 , bdate DATE
8 , sal NUMBER(6,2)
9 , comm NUMBER(6,2)
10 , deptno NUMBER(2) default 10
11 ) ;
Table created.
SQL> insert into emp values(1,"Tom","N", "Coder", 13,date "1965-12-17", 800 , NULL, 20);
1 row created.
SQL> insert into emp values(2,"Jack","JAM", "Tester",6,date "1961-02-20", 1600, 300, 30);
1 row created.
SQL> insert into emp values(3,"Wil","TF" , "Tester",6,date "1962-02-22", 1250, 500, 30);
1 row created.
SQL> insert into emp values(4,"Jane","JM", "Designer", 9,date "1967-04-02", 2975, NULL, 20);
1 row created.
SQL> insert into emp values(5,"Mary","P", "Tester",6,date "1956-09-28", 1250, 1400, 30);
1 row created.
SQL> insert into emp values(6,"Black","R", "Designer", 9,date "1963-11-01", 2850, NULL, 30);
1 row created.
SQL> insert into emp values(7,"Chris","AB", "Designer", 9,date "1965-06-09", 2450, NULL, 10);
1 row created.
SQL> insert into emp values(8,"Smart","SCJ", "Coder", 4,date "1959-11-26", 3000, NULL, 20);
1 row created.
SQL> insert into emp values(9,"Peter","CC", "Designer",NULL,date "1952-11-17", 5000, NULL, 10);
1 row created.
SQL> insert into emp values(10,"Take","JJ", "Tester",6,date "1968-09-28", 1500, 0, 30);
1 row created.
SQL> insert into emp values(11,"Ana","AA", "Coder", 8,date "1966-12-30", 1100, NULL, 20);
1 row created.
SQL> insert into emp values(12,"Jane","R", "Manager", 6,date "1969-12-03", 800 , NULL, 30);
1 row created.
SQL> insert into emp values(13,"Fake","MG", "Coder", 4,date "1959-02-13", 3000, NULL, 20);
1 row created.
SQL> insert into emp values(14,"Mike","TJA","Manager", 7,date "1962-01-23", 1300, NULL, 10);
1 row created.
SQL>
SQL>
SQL> select ename
2 , ltrim(ename,"S") as ltrim_s
3 , rtrim(ename,"S") as rtrim_s
4 from emp
5 where deptno = 20;
ENAME LTRIM_S RTRIM_S
-------- -------- --------
Tom Tom Tom
Jane Jane Jane
Smart mart Smart
Ana Ana Ana
Fake Fake Fake
SQL>
SQL>
SQL> drop table emp;
Table dropped.