Oracle PL/SQL Tutorial/Query Select/Multiple Row Subquery — различия между версиями
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Текущая версия на 10:11, 26 мая 2010
Содержание
- 1 First three rows from subquery
- 2 Multi-row subqueries: Show products that aren"t selling
- 3 Select from another select statement
- 4 Subqueries That Return Multiple Results
- 5 Update price of products that aren"t selling
- 6 Uses NOT IN to check if an id is not in the list of id values in the employee table
- 7 Using ALL with a Multiple Row Subquery
- 8 Using ANY with a Multiple Row Subquery
- 9 Using IN with a Multiple Row Subquery
- 10 Writing Multiple Column Subqueries
- 11 Writing Multiple Row Subqueries
First three rows from subquery
SQL>
SQL> create table history
2 ( empno NUMBER(4)
3 , beginyear NUMBER(4)
4 , begindate DATE
5 , enddate DATE
6 , deptno NUMBER(2)
7 , sal NUMBER(6,2)
8 , comments VARCHAR2(60)
9 , constraint H_PK primary key (empno,begindate)
10 , constraint H_BEG_END check (begindate < enddate)
11 ) ;
Table created.
SQL>
SQL>
SQL> alter session set NLS_DATE_FORMAT="DD-MM-YYYY";
Session altered.
SQL>
SQL> insert into history values (1,2000,"01-02-2000", NULL ,20, 800,"restarted");
1 row created.
SQL> insert into history values (2,1995,"01-10-1995","01-11-2009",30,1700,"");
1 row created.
SQL> insert into history values (2,2009,"01-11-2009", NULL ,30,1600,"just hired");
1 row created.
SQL> insert into history values (3,1986,"01-10-1986","01-08-1987",20,1000,"");
1 row created.
SQL> insert into history values (3,1987,"01-08-1987","01-01-1989",30,1000,"On training");
1 row created.
SQL> insert into history values (3,2000,"01-02-2000", NULL ,30,1250,"");
1 row created.
SQL>
SQL> select *
2 from (select empno, sal
3 from history
4 order by sal desc)
5 where rownum <= 3;
EMPNO SAL
---------- ----------
2 1700
2 1600
3 1250
SQL>
SQL> drop table history;
Table dropped.
SQL>
Multi-row subqueries: Show products that aren"t selling
SQL>
SQL> CREATE TABLE product (
2 product_name VARCHAR2(25) PRIMARY KEY,
3 product_price NUMBER(4,2),
4 quantity_on_hand NUMBER(5,0),
5 last_stock_date DATE
6 );
Table created.
SQL>
SQL> CREATE TABLE product_order (
2 product_name VARCHAR2(25),
3 salesperson VARCHAR2(3),
4 order_date DATE,
5 quantity NUMBER(4,2)
6 );
Table created.
SQL>
SQL>
SQL> INSERT INTO product_order VALUES ("Product 1", "CA", "14-JUL-03", 1);
1 row created.
SQL> INSERT INTO product_order VALUES ("Product 2", "BB", "14-JUL-03", 75);
1 row created.
SQL> INSERT INTO product_order VALUES ("Product 3", "GA", "14-JUL-03", 2);
1 row created.
SQL> INSERT INTO product_order VALUES ("Product 4", "GA", "15-JUL-03", 8);
1 row created.
SQL> INSERT INTO product_order VALUES ("Product 5", "LB", "15-JUL-03", 20);
1 row created.
SQL> INSERT INTO product_order VALUES ("Product 6", "CA", "16-JUL-03", 5);
1 row created.
SQL> INSERT INTO product_order VALUES ("Product 7", "CA", "17-JUL-03", 1);
1 row created.
SQL>
SQL>
SQL> INSERT INTO product VALUES ("Product 1", 99, 1, "15-JAN-03");
1 row created.
SQL> INSERT INTO product VALUES ("Product 2", 75, 1000, "15-JAN-02");
1 row created.
SQL> INSERT INTO product VALUES ("Product 3", 50, 100, "15-JAN-03");
1 row created.
SQL> INSERT INTO product VALUES ("Product 4", 25, 10000, null);
1 row created.
SQL> INSERT INTO product VALUES ("Product 5", 9.95,1234, "15-JAN-04");
1 row created.
SQL> INSERT INTO product VALUES ("Product 6", 45, 1, TO_DATE("December 31, 2008, 11:30 P.M.","Month dd, YYYY, HH:MI P.M."));
1 row created.
SQL>
SQL> SELECT * FROM product_order ORDER BY product_name;
PRODUCT_NAME SAL ORDER_DAT QUANTITY
------------------------- --- --------- ----------
Product 1 CA 14-JUL-03 1
Product 2 BB 14-JUL-03 75
Product 3 GA 14-JUL-03 2
Product 4 GA 15-JUL-03 8
Product 5 LB 15-JUL-03 20
Product 6 CA 16-JUL-03 5
Product 7 CA 17-JUL-03 1
7 rows selected.
SQL>
SQL> SELECT * FROM product
2 WHERE product_name NOT IN (SELECT DISTINCT product_name FROM product_order)
3 ORDER BY product_name;
no rows selected
SQL>
SQL>
SQL> drop table product;
Table dropped.
SQL> drop table product_order;
Table dropped.
SQL>
Select from another select statement
SQL> create table t
2 (item number,
3 bin number,
4 primary key (bin , item) );
Table created.
SQL>
SQL> insert into t values(2, 34353);
1 row created.
SQL> insert into t values(45,34353);
1 row created.
SQL> insert into t values(76,34353);
1 row created.
SQL> insert into t values(76,35667);
1 row created.
SQL> insert into t values(89,35667);
1 row created.
SQL> insert into t values(45,35667);
1 row created.
SQL> insert into t values(45,36767);
1 row created.
SQL>
SQL> insert into t values(46,36767);
1 row created.
SQL> insert into t values(66,36767);
1 row created.
SQL> insert into t values(86,36767);
1 row created.
SQL> insert into t values(96,36767);
1 row created.
SQL>
SQL> select * from t
2 order by 1,2;
ITEM BIN
---------- ----------
2 34353
45 34353
45 35667
45 36767
46 36767
66 36767
76 34353
76 35667
86 36767
89 35667
96 36767
11 rows selected.
SQL>
SQL> select bin, count(*), count(*)/cnt
2 from (
3 select bin, count(distinct item) over () AS cnt
4 from t
5 where item in (2,45,76,89) )
6 group by bin, cnt
7 /
BIN COUNT(*) COUNT(*)/CNT
---------- ---------- ------------
35667 3 .75
36767 1 .25
34353 3 .75
SQL>
SQL> drop table t;
Table dropped.
SQL>
SQL>
Subqueries That Return Multiple Results
SQL>
SQL> CREATE TABLE Course (
2 CourseID INT NOT NULL PRIMARY KEY,
3 Name VARCHAR(50),
4 Credits INT);
SQL>
SQL>
SQL> CREATE TABLE Exam (
2 ExamID INT NOT NULL PRIMARY KEY,
3 CourseID INT NOT NULL,
4 InstructorID INT NOT NULL,
5 SustainedOn DATE,
6 Comments VARCHAR(255));
SQL>
SQL> SELECT Name FROM Course
2 WHERE CourseID IN(
3 SELECT CourseID from EXAM
4 WHERE SustainedOn="26-MAR-03"
5 );
no rows selected
SQL>
SQL> drop table course;
Table dropped.
SQL> drop table exam;
Table dropped.
Update price of products that aren"t selling
SQL>
SQL> CREATE TABLE product (
2 product_name VARCHAR2(25) PRIMARY KEY,
3 product_price NUMBER(4,2),
4 quantity_on_hand NUMBER(5,0),
5 last_stock_date DATE
6 );
Table created.
SQL>
SQL> CREATE TABLE product_order (
2 product_name VARCHAR2(25),
3 salesperson VARCHAR2(3),
4 order_date DATE,
5 quantity NUMBER(4,2)
6 );
Table created.
SQL>
SQL>
SQL> INSERT INTO product_order VALUES ("Product 1", "CA", "14-JUL-03", 1);
1 row created.
SQL> INSERT INTO product_order VALUES ("Product 2", "BB", "14-JUL-03", 75);
1 row created.
SQL> INSERT INTO product_order VALUES ("Product 3", "GA", "14-JUL-03", 2);
1 row created.
SQL> INSERT INTO product_order VALUES ("Product 4", "GA", "15-JUL-03", 8);
1 row created.
SQL> INSERT INTO product_order VALUES ("Product 5", "LB", "15-JUL-03", 20);
1 row created.
SQL> INSERT INTO product_order VALUES ("Product 6", "CA", "16-JUL-03", 5);
1 row created.
SQL> INSERT INTO product_order VALUES ("Product 7", "CA", "17-JUL-03", 1);
1 row created.
SQL>
SQL>
SQL> INSERT INTO product VALUES ("Product 1", 99, 1, "15-JAN-03");
1 row created.
SQL> INSERT INTO product VALUES ("Product 2", 75, 1000, "15-JAN-02");
1 row created.
SQL> INSERT INTO product VALUES ("Product 3", 50, 100, "15-JAN-03");
1 row created.
SQL> INSERT INTO product VALUES ("Product 4", 25, 10000, null);
1 row created.
SQL> INSERT INTO product VALUES ("Product 5", 9.95,1234, "15-JAN-04");
1 row created.
SQL> INSERT INTO product VALUES ("Product 6", 45, 1, TO_DATE("December 31, 2008, 11:30 P.M.","Month dd, YYYY, HH:MI P.M."));
1 row created.
SQL>
SQL> SELECT * FROM product;
PRODUCT_NAME PRODUCT_PRICE QUANTITY_ON_HAND LAST_STOC
------------------------- ------------- ---------------- ---------
Product 1 99 1 15-JAN-03
Product 2 75 1000 15-JAN-02
Product 3 50 100 15-JAN-03
Product 4 25 10000
Product 5 9.95 1234 15-JAN-04
Product 6 45 1 31-DEC-08
6 rows selected.
SQL>
SQL> UPDATE product
2 SET product_price = product_price * .9
3 WHERE product_name NOT IN (SELECT DISTINCT product_name FROM product_order);
0 rows updated.
SQL>
SQL> SELECT * FROM product;
PRODUCT_NAME PRODUCT_PRICE QUANTITY_ON_HAND LAST_STOC
------------------------- ------------- ---------------- ---------
Product 1 99 1 15-JAN-03
Product 2 75 1000 15-JAN-02
Product 3 50 100 15-JAN-03
Product 4 25 10000
Product 5 9.95 1234 15-JAN-04
Product 6 45 1 31-DEC-08
6 rows selected.
SQL>
SQL> drop table product;
Table dropped.
SQL> drop table product_order;
Table dropped.
Uses NOT IN to check if an id is not in the list of id values in the employee table
SQL>
SQL>
SQL>
SQL>
SQL> -- create demo table
SQL> create table Employee(
2 EMPNO NUMBER(3),
3 ENAME VARCHAR2(15 BYTE),
4 HIREDATE DATE,
5 ORIG_SALARY NUMBER(6),
6 CURR_SALARY NUMBER(6),
7 REGION VARCHAR2(1 BYTE),
8 MANAGER_ID NUMBER(3)
9 )
10 /
Table created.
SQL>
SQL> create table job (
2 EMPNO NUMBER(3),
3 jobtitle VARCHAR2(20 BYTE)
4 )
5 /
Table created.
SQL>
SQL> insert into job (EMPNO, Jobtitle) values (1,"Tester");
1 row created.
SQL> insert into job (EMPNO, Jobtitle) values (2,"Accountant");
1 row created.
SQL> insert into job (EMPNO, Jobtitle) values (3,"Developer");
1 row created.
SQL> insert into job (EMPNO, Jobtitle) values (4,"COder");
1 row created.
SQL> insert into job (EMPNO, Jobtitle) values (5,"Director");
1 row created.
SQL> insert into job (EMPNO, Jobtitle) values (6,"Mediator");
1 row created.
SQL> insert into job (EMPNO, Jobtitle) values (7,"Proffessor");
1 row created.
SQL> insert into job (EMPNO, Jobtitle) values (8,"Programmer");
1 row created.
SQL> insert into job (EMPNO, Jobtitle) values (9,"Developer");
1 row created.
SQL>
SQL>
SQL> -- prepare data
SQL> insert into Employee(EMPNO, EName, HIREDATE, ORIG_SALARY, CURR_SALARY, REGION, MANAGER_ID)
2 values (1, "Jason", to_date("19960725","YYYYMMDD"), 1234, 8767, "E", 2)
3 /
1 row created.
SQL> insert into Employee(EMPNO, EName, HIREDATE, ORIG_SALARY, CURR_SALARY, REGION, MANAGER_ID)
2 values (2, "John", to_date("19970715","YYYYMMDD"), 2341, 3456, "W", 3)
3 /
1 row created.
SQL> insert into Employee(EMPNO, EName, HIREDATE, ORIG_SALARY, CURR_SALARY, REGION, MANAGER_ID)
2 values (3, "Joe", to_date("19860125","YYYYMMDD"), 4321, 5654, "E", 3)
3 /
1 row created.
SQL> insert into Employee(EMPNO, EName, HIREDATE, ORIG_SALARY, CURR_SALARY, REGION, MANAGER_ID)
2 values (4, "Tom", to_date("20060913","YYYYMMDD"), 2413, 6787, "W", 4)
3 /
1 row created.
SQL> insert into Employee(EMPNO, EName, HIREDATE, ORIG_SALARY, CURR_SALARY, REGION, MANAGER_ID)
2 values (5, "Jane", to_date("20050417","YYYYMMDD"), 7654, 4345, "E", 4)
3 /
1 row created.
SQL> insert into Employee(EMPNO, EName, HIREDATE, ORIG_SALARY, CURR_SALARY, REGION, MANAGER_ID)
2 values (6, "James", to_date("20040718","YYYYMMDD"), 5679, 6546, "W", 5)
3 /
1 row created.
SQL> insert into Employee(EMPNO, EName, HIREDATE, ORIG_SALARY, CURR_SALARY, REGION, MANAGER_ID)
2 values (7, "Jodd", to_date("20030720","YYYYMMDD"), 5438, 7658, "E", 6)
3 /
1 row created.
SQL> insert into Employee(EMPNO, EName, HIREDATE, ORIG_SALARY, CURR_SALARY, REGION)
2 values (8, "Joke", to_date("20020101","YYYYMMDD"), 8765, 4543, "W")
3 /
1 row created.
SQL> insert into Employee(EMPNO, EName, HIREDATE, ORIG_SALARY, CURR_SALARY, REGION)
2 values (9, "Jack", to_date("20010829","YYYYMMDD"), 7896, 1232, "E")
3 /
1 row created.
SQL>
SQL>
SQL>
SQL> -- display data in the table
SQL> select * from Employee
2 /
EMPNO ENAME HIREDATE ORIG_SALARY CURR_SALARY R MANAGER_ID
---------- --------------- --------- ----------- ----------- - ----------
1 Jason 25-JUL-96 1234 8767 E 2
2 John 15-JUL-97 2341 3456 W 3
3 Joe 25-JAN-86 4321 5654 E 3
4 Tom 13-SEP-06 2413 6787 W 4
5 Jane 17-APR-05 7654 4345 E 4
6 James 18-JUL-04 5679 6546 W 5
7 Jodd 20-JUL-03 5438 7658 E 6
8 Joke 01-JAN-02 8765 4543 W
9 Jack 29-AUG-01 7896 1232 E
9 rows selected.
SQL> select * from job
2 /
EMPNO JOBTITLE
---------- --------------------
1 Tester
2 Accountant
3 Developer
4 COder
5 Director
6 Mediator
7 Proffessor
8 Programmer
9 Developer
9 rows selected.
SQL>
SQL>
SQL> SELECT empno, ename
2 FROM employee
3 WHERE empno NOT IN
4 (SELECT empno
5 FROM job);
no rows selected
SQL>
SQL>
SQL> -- clean the table
SQL> drop table Employee
2 /
Table dropped.
SQL> drop table job
2 /
Table dropped.
Using ALL with a Multiple Row Subquery
ALL operator compares a value with any value in a list.
You must place an =, <>, <, >, <=, or >= operator before ALL in your query.
SQL> -- create demo table
SQL> create table Employee(
2 ID VARCHAR2(4 BYTE) NOT NULL,
3 First_Name VARCHAR2(10 BYTE),
4 Last_Name VARCHAR2(10 BYTE),
5 Start_Date DATE,
6 End_Date DATE,
7 Salary Number(8,2),
8 City VARCHAR2(10 BYTE),
9 Description VARCHAR2(15 BYTE)
10 )
11 /
Table created.
SQL>
SQL> -- prepare data
SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)
2 values ("01","Jason", "Martin", to_date("19960725","YYYYMMDD"), to_date("20060725","YYYYMMDD"), 1234.56, "Toronto", "Programmer")
3 /
1 row created.
SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)
2 values("02","Alison", "Mathews", to_date("19760321","YYYYMMDD"), to_date("19860221","YYYYMMDD"), 6661.78, "Vancouver","Tester")
3 /
1 row created.
SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)
2 values("03","James", "Smith", to_date("19781212","YYYYMMDD"), to_date("19900315","YYYYMMDD"), 6544.78, "Vancouver","Tester")
3 /
1 row created.
SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)
2 values("04","Celia", "Rice", to_date("19821024","YYYYMMDD"), to_date("19990421","YYYYMMDD"), 2344.78, "Vancouver","Manager")
3 /
1 row created.
SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)
2 values("05","Robert", "Black", to_date("19840115","YYYYMMDD"), to_date("19980808","YYYYMMDD"), 2334.78, "Vancouver","Tester")
3 /
1 row created.
SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)
2 values("06","Linda", "Green", to_date("19870730","YYYYMMDD"), to_date("19960104","YYYYMMDD"), 4322.78,"New York", "Tester")
3 /
1 row created.
SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)
2 values("07","David", "Larry", to_date("19901231","YYYYMMDD"), to_date("19980212","YYYYMMDD"), 7897.78,"New York", "Manager")
3 /
1 row created.
SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)
2 values("08","James", "Cat", to_date("19960917","YYYYMMDD"), to_date("20020415","YYYYMMDD"), 1232.78,"Vancouver", "Tester")
3 /
1 row created.
SQL>
SQL>
SQL>
SQL> -- display data in the table
SQL> select * from Employee
2 /
ID FIRST_NAME LAST_NAME START_DAT END_DATE SALARY CITY DESCRIPTION
---- ---------- ---------- --------- --------- ---------- ---------- ---------------
01 Jason Martin 25-JUL-96 25-JUL-06 1234.56 Toronto Programmer
02 Alison Mathews 21-MAR-76 21-FEB-86 6661.78 Vancouver Tester
03 James Smith 12-DEC-78 15-MAR-90 6544.78 Vancouver Tester
04 Celia Rice 24-OCT-82 21-APR-99 2344.78 Vancouver Manager
05 Robert Black 15-JAN-84 08-AUG-98 2334.78 Vancouver Tester
06 Linda Green 30-JUL-87 04-JAN-96 4322.78 New York Tester
07 David Larry 31-DEC-90 12-FEB-98 7897.78 New York Manager
08 James Cat 17-SEP-96 15-APR-02 1232.78 Vancouver Tester
8 rows selected.
SQL>
SQL>
SQL> SELECT id, last_name
2 FROM employee
3 WHERE salary > ALL
4 (SELECT salary
5 FROM employee where city="Vancouver");
ID LAST_NAME
---- ----------
07 Larry
SQL>
SQL>
SQL> -- clean the table
SQL> drop table Employee
2 /
Table dropped.
SQL>
SQL>
Using ANY with a Multiple Row Subquery
ANY operator compares a value with any value in a list.
You must place an =, <>, <, >, <=, or >= operator before ANY in your query.
SQL> -- create demo table
SQL> create table Employee(
2 ID VARCHAR2(4 BYTE) NOT NULL,
3 First_Name VARCHAR2(10 BYTE),
4 Last_Name VARCHAR2(10 BYTE),
5 Start_Date DATE,
6 End_Date DATE,
7 Salary Number(8,2),
8 City VARCHAR2(10 BYTE),
9 Description VARCHAR2(15 BYTE)
10 )
11 /
Table created.
SQL>
SQL> -- prepare data
SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)
2 values ("01","Jason", "Martin", to_date("19960725","YYYYMMDD"), to_date("20060725","YYYYMMDD"), 1234.56, "Toronto", "Programmer")
3 /
1 row created.
SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)
2 values("02","Alison", "Mathews", to_date("19760321","YYYYMMDD"), to_date("19860221","YYYYMMDD"), 6661.78, "Vancouver","Tester")
3 /
1 row created.
SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)
2 values("03","James", "Smith", to_date("19781212","YYYYMMDD"), to_date("19900315","YYYYMMDD"), 6544.78, "Vancouver","Tester")
3 /
1 row created.
SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)
2 values("04","Celia", "Rice", to_date("19821024","YYYYMMDD"), to_date("19990421","YYYYMMDD"), 2344.78, "Vancouver","Manager")
3 /
1 row created.
SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)
2 values("05","Robert", "Black", to_date("19840115","YYYYMMDD"), to_date("19980808","YYYYMMDD"), 2334.78, "Vancouver","Tester")
3 /
1 row created.
SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)
2 values("06","Linda", "Green", to_date("19870730","YYYYMMDD"), to_date("19960104","YYYYMMDD"), 4322.78,"New York", "Tester")
3 /
1 row created.
SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)
2 values("07","David", "Larry", to_date("19901231","YYYYMMDD"), to_date("19980212","YYYYMMDD"), 7897.78,"New York", "Manager")
3 /
1 row created.
SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)
2 values("08","James", "Cat", to_date("19960917","YYYYMMDD"), to_date("20020415","YYYYMMDD"), 1232.78,"Vancouver", "Tester")
3 /
1 row created.
SQL>
SQL>
SQL>
SQL> -- display data in the table
SQL> select * from Employee
2 /
ID FIRST_NAME LAST_NAME START_DAT END_DATE SALARY CITY DESCRIPTION
---- ---------- ---------- --------- --------- ---------- ---------- ---------------
01 Jason Martin 25-JUL-96 25-JUL-06 1234.56 Toronto Programmer
02 Alison Mathews 21-MAR-76 21-FEB-86 6661.78 Vancouver Tester
03 James Smith 12-DEC-78 15-MAR-90 6544.78 Vancouver Tester
04 Celia Rice 24-OCT-82 21-APR-99 2344.78 Vancouver Manager
05 Robert Black 15-JAN-84 08-AUG-98 2334.78 Vancouver Tester
06 Linda Green 30-JUL-87 04-JAN-96 4322.78 New York Tester
07 David Larry 31-DEC-90 12-FEB-98 7897.78 New York Manager
08 James Cat 17-SEP-96 15-APR-02 1232.78 Vancouver Tester
8 rows selected.
SQL>
SQL>
SQL> SELECT id, last_name
2 FROM employees
3 WHERE id < ANY
4 (SELECT id
5 FROM employee where city="Vancouver");
FROM employees
*
ERROR at line 2:
ORA-00942: table or view does not exist
SQL>
SQL>
SQL> -- clean the table
SQL> drop table Employee
2 /
Table dropped.
SQL>
SQL>
Using IN with a Multiple Row Subquery
SQL> -- create demo table
SQL> create table Employee(
2 ID VARCHAR2(4 BYTE) NOT NULL,
3 First_Name VARCHAR2(10 BYTE),
4 Last_Name VARCHAR2(10 BYTE),
5 Start_Date DATE,
6 End_Date DATE,
7 Salary Number(8,2),
8 City VARCHAR2(10 BYTE),
9 Description VARCHAR2(15 BYTE)
10 )
11 /
Table created.
SQL>
SQL> -- prepare data
SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)
2 values ("01","Jason", "Martin", to_date("19960725","YYYYMMDD"), to_date("20060725","YYYYMMDD"), 1234.56, "Toronto", "Programmer")
3 /
1 row created.
SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)
2 values("02","Alison", "Mathews", to_date("19760321","YYYYMMDD"), to_date("19860221","YYYYMMDD"), 6661.78, "Vancouver","Tester")
3 /
1 row created.
SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)
2 values("03","James", "Smith", to_date("19781212","YYYYMMDD"), to_date("19900315","YYYYMMDD"), 6544.78, "Vancouver","Tester")
3 /
1 row created.
SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)
2 values("04","Celia", "Rice", to_date("19821024","YYYYMMDD"), to_date("19990421","YYYYMMDD"), 2344.78, "Vancouver","Manager")
3 /
1 row created.
SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)
2 values("05","Robert", "Black", to_date("19840115","YYYYMMDD"), to_date("19980808","YYYYMMDD"), 2334.78, "Vancouver","Tester")
3 /
1 row created.
SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)
2 values("06","Linda", "Green", to_date("19870730","YYYYMMDD"), to_date("19960104","YYYYMMDD"), 4322.78,"New York", "Tester")
3 /
1 row created.
SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)
2 values("07","David", "Larry", to_date("19901231","YYYYMMDD"), to_date("19980212","YYYYMMDD"), 7897.78,"New York", "Manager")
3 /
1 row created.
SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)
2 values("08","James", "Cat", to_date("19960917","YYYYMMDD"), to_date("20020415","YYYYMMDD"), 1232.78,"Vancouver", "Tester")
3 /
1 row created.
SQL>
SQL>
SQL>
SQL> -- display data in the table
SQL> select * from Employee
2 /
ID FIRST_NAME LAST_NAME START_DAT END_DATE SALARY CITY DESCRIPTION
---- ---------- ---------- --------- --------- ---------- ---------- ---------------
01 Jason Martin 25-JUL-96 25-JUL-06 1234.56 Toronto Programmer
02 Alison Mathews 21-MAR-76 21-FEB-86 6661.78 Vancouver Tester
03 James Smith 12-DEC-78 15-MAR-90 6544.78 Vancouver Tester
04 Celia Rice 24-OCT-82 21-APR-99 2344.78 Vancouver Manager
05 Robert Black 15-JAN-84 08-AUG-98 2334.78 Vancouver Tester
06 Linda Green 30-JUL-87 04-JAN-96 4322.78 New York Tester
07 David Larry 31-DEC-90 12-FEB-98 7897.78 New York Manager
08 James Cat 17-SEP-96 15-APR-02 1232.78 Vancouver Tester
8 rows selected.
SQL>
SQL>
SQL>
SQL> SELECT id, first_name
2 FROM employee
3 WHERE id IN
4 (SELECT id
5 FROM employee
6 WHERE first_name LIKE "%e%");
ID FIRST_NAME
---- ----------
03 James
04 Celia
05 Robert
08 James
SQL>
SQL>
SQL> -- clean the table
SQL> drop table Employee
2 /
Table dropped.
SQL>
SQL>
Writing Multiple Column Subqueries
SQL>
SQL>
SQL>
SQL> -- create demo table
SQL> create table Employee(
2 ID VARCHAR2(4 BYTE) NOT NULL,
3 First_Name VARCHAR2(10 BYTE),
4 Last_Name VARCHAR2(10 BYTE),
5 Start_Date DATE,
6 End_Date DATE,
7 Salary Number(8,2),
8 City VARCHAR2(10 BYTE),
9 Description VARCHAR2(15 BYTE)
10 )
11 /
Table created.
SQL>
SQL> -- prepare data
SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)
2 values ("01","Jason", "Martin", to_date("19960725","YYYYMMDD"), to_date("20060725","YYYYMMDD"), 1234.56, "Toronto", "Programmer")
3 /
1 row created.
SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)
2 values("02","Alison", "Mathews", to_date("19760321","YYYYMMDD"), to_date("19860221","YYYYMMDD"), 6661.78, "Vancouver","Tester")
3 /
1 row created.
SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)
2 values("03","James", "Smith", to_date("19781212","YYYYMMDD"), to_date("19900315","YYYYMMDD"), 6544.78, "Vancouver","Tester")
3 /
1 row created.
SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)
2 values("04","Celia", "Rice", to_date("19821024","YYYYMMDD"), to_date("19990421","YYYYMMDD"), 2344.78, "Vancouver","Manager")
3 /
1 row created.
SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)
2 values("05","Robert", "Black", to_date("19840115","YYYYMMDD"), to_date("19980808","YYYYMMDD"), 2334.78, "Vancouver","Tester")
3 /
1 row created.
SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)
2 values("06","Linda", "Green", to_date("19870730","YYYYMMDD"), to_date("19960104","YYYYMMDD"), 4322.78,"New York", "Tester")
3 /
1 row created.
SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)
2 values("07","David", "Larry", to_date("19901231","YYYYMMDD"), to_date("19980212","YYYYMMDD"), 7897.78,"New York", "Manager")
3 /
1 row created.
SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)
2 values("08","James", "Cat", to_date("19960917","YYYYMMDD"), to_date("20020415","YYYYMMDD"), 1232.78,"Vancouver", "Tester")
3 /
1 row created.
SQL>
SQL>
SQL>
SQL> -- display data in the table
SQL> select * from Employee
2 /
ID FIRST_NAME LAST_NAME START_DAT END_DATE SALARY CITY DESCRIPTION
---- ---------- ---------- --------- --------- ---------- ---------- ---------------
01 Jason Martin 25-JUL-96 25-JUL-06 1234.56 Toronto Programmer
02 Alison Mathews 21-MAR-76 21-FEB-86 6661.78 Vancouver Tester
03 James Smith 12-DEC-78 15-MAR-90 6544.78 Vancouver Tester
04 Celia Rice 24-OCT-82 21-APR-99 2344.78 Vancouver Manager
05 Robert Black 15-JAN-84 08-AUG-98 2334.78 Vancouver Tester
06 Linda Green 30-JUL-87 04-JAN-96 4322.78 New York Tester
07 David Larry 31-DEC-90 12-FEB-98 7897.78 New York Manager
08 James Cat 17-SEP-96 15-APR-02 1232.78 Vancouver Tester
8 rows selected.
SQL>
SQL>
SQL> SELECT id, first_name, salary
2 FROM employee
3 WHERE (id, salary) IN
4 (SELECT id, MIN(salary)
5 FROM employee
6 GROUP BY id);
ID FIRST_NAME SALARY
---- ---------- ----------
01 Jason 1234.56
02 Alison 6661.78
03 James 6544.78
04 Celia 2344.78
05 Robert 2334.78
06 Linda 4322.78
07 David 7897.78
08 James 1232.78
8 rows selected.
SQL>
SQL>
SQL> -- clean the table
SQL> drop table Employee
2 /
Table dropped.
SQL>
SQL>
Writing Multiple Row Subqueries
A multiple row subquery returns one or more rows to the outer SQL statement.
The outer query may use the IN, ANY, or ALL operator to handle a subquery that returns multiple rows.
2. 38. Multiple Row Subquery 2. 38. 1. Writing Multiple Row Subqueries 2. 38. 2. <A href="/Tutorial/Oracle/0040__Query-Select/UsingINwithaMultipleRowSubquery.htm">Using IN with a Multiple Row Subquery</a> 2. 38. 3. <A href="/Tutorial/Oracle/0040__Query-Select/Updatepriceofproductsthatarentselling.htm">Update price of products that aren"t selling</a> 2. 38. 4. <A href="/Tutorial/Oracle/0040__Query-Select/MultirowsubqueriesShowproductsthatarentselling.htm">Multi-row subqueries: Show products that aren"t selling</a> 2. 38. 5. <A href="/Tutorial/Oracle/0040__Query-Select/UsesNOTINtocheckifanidisnotinthelistofidvaluesintheemployeetable.htm">Uses NOT IN to check if an id is not in the list of id values in the employee table</a> 2. 38. 6. <A href="/Tutorial/Oracle/0040__Query-Select/UsingANYwithaMultipleRowSubquery.htm">Using ANY with a Multiple Row Subquery</a> 2. 38. 7. <A href="/Tutorial/Oracle/0040__Query-Select/UsingALLwithaMultipleRowSubquery.htm">Using ALL with a Multiple Row Subquery</a> 2. 38. 8. <A href="/Tutorial/Oracle/0040__Query-Select/WritingMultipleColumnSubqueries.htm">Writing Multiple Column Subqueries</a> 2. 38. 9. <A href="/Tutorial/Oracle/0040__Query-Select/Selectfromanotherselectstatement.htm">Select from another select statement</a> 2. 38. 10. <A href="/Tutorial/Oracle/0040__Query-Select/SubqueriesThatReturnMultipleResults.htm">Subqueries That Return Multiple Results</a> 2. 38. 11. <A href="/Tutorial/Oracle/0040__Query-Select/Firstthreerowsfromsubquery.htm">First three rows from subquery</a>
