Oracle PL/SQL Tutorial/Date Timestamp Functions/MONTHS BETWEEN — различия между версиями
Admin (обсуждение | вклад) м (1 версия) |
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Текущая версия на 10:04, 26 мая 2010
Содержание
Months between birthday and now
SQL> create table emp
2 ( empno NUMBER(4) constraint E_PK primary key
3 , ename VARCHAR2(8)
4 , init VARCHAR2(5)
5 , job VARCHAR2(8)
6 , mgr NUMBER(4)
7 , bdate DATE
8 , sal NUMBER(6,2)
9 , comm NUMBER(6,2)
10 , deptno NUMBER(2) default 10
11 ) ;
Table created.
SQL> insert into emp values(1,"Tom","N", "Coder", 13,date "1965-12-17", 800 , NULL, 20);
1 row created.
SQL> insert into emp values(2,"Jack","JAM", "Tester",6,date "1961-02-20", 1600, 300, 30);
1 row created.
SQL> insert into emp values(3,"Wil","TF" , "Tester",6,date "1962-02-22", 1250, 500, 30);
1 row created.
SQL> insert into emp values(4,"Jane","JM", "Designer", 9,date "1967-04-02", 2975, NULL, 20);
1 row created.
SQL> insert into emp values(5,"Mary","P", "Tester",6,date "1956-09-28", 1250, 1400, 30);
1 row created.
SQL> insert into emp values(6,"Black","R", "Designer", 9,date "1963-11-01", 2850, NULL, 30);
1 row created.
SQL> insert into emp values(7,"Chris","AB", "Designer", 9,date "1965-06-09", 2450, NULL, 10);
1 row created.
SQL> insert into emp values(8,"Smart","SCJ", "Coder", 4,date "1959-11-26", 3000, NULL, 20);
1 row created.
SQL> insert into emp values(9,"Peter","CC", "Designer",NULL,date "1952-11-17", 5000, NULL, 10);
1 row created.
SQL> insert into emp values(10,"Take","JJ", "Tester",6,date "1968-09-28", 1500, 0, 30);
1 row created.
SQL> insert into emp values(11,"Ana","AA", "Coder", 8,date "1966-12-30", 1100, NULL, 20);
1 row created.
SQL> insert into emp values(12,"Jane","R", "Manager", 6,date "1969-12-03", 800 , NULL, 30);
1 row created.
SQL> insert into emp values(13,"Fake","MG", "Coder", 4,date "1959-02-13", 3000, NULL, 20);
1 row created.
SQL> insert into emp values(14,"Mike","TJA","Manager", 7,date "1962-01-23", 1300, NULL, 10);
1 row created.
SQL>
SQL> select ename
2 , months_between(sysdate,bdate)
3 from emp
4 where deptno = 10;
ENAME MONTHS_BETWEEN(SYSDATE,BDATE)
-------- -----------------------------
Chris 532.561911
Peter 683.303846
Mike 573.110298
SQL>
SQL>
SQL> drop table emp;
Table dropped.
months_between current time and birthday
SQL>
SQL>
SQL> create table employees(
2 empno NUMBER(4)
3 , ename VARCHAR2(8)
4 , init VARCHAR2(5)
5 , job VARCHAR2(8)
6 , mgr NUMBER(4)
7 , bdate DATE
8 , msal NUMBER(6,2)
9 , comm NUMBER(6,2)
10 , deptno NUMBER(2) ) ;
Table created.
SQL>
SQL>
SQL> insert into employees values(1,"Jason", "N", "TRAINER", 2, date "1965-12-18", 800 , NULL, 10);
1 row created.
SQL> insert into employees values(2,"Jerry", "J", "SALESREP",3, date "1966-11-19", 1600, 300, 10);
1 row created.
SQL> insert into employees values(3,"Jord", "T" , "SALESREP",4, date "1967-10-21", 1700, 500, 20);
1 row created.
SQL> insert into employees values(4,"Mary", "J", "MANAGER", 5, date "1968-09-22", 1800, NULL, 20);
1 row created.
SQL> insert into employees values(5,"Joe", "P", "SALESREP",6, date "1969-08-23", 1900, 1400, 30);
1 row created.
SQL> insert into employees values(6,"Black", "R", "MANAGER", 7, date "1970-07-24", 2000, NULL, 30);
1 row created.
SQL> insert into employees values(7,"Red", "A", "MANAGER", 8, date "1971-06-25", 2100, NULL, 40);
1 row created.
SQL> insert into employees values(8,"White", "S", "TRAINER", 9, date "1972-05-26", 2200, NULL, 40);
1 row created.
SQL> insert into employees values(9,"Yellow", "C", "DIRECTOR",10, date "1973-04-27", 2300, NULL, 20);
1 row created.
SQL> insert into employees values(10,"Pink", "J", "SALESREP",null,date "1974-03-28", 2400, 0, 30);
1 row created.
SQL>
SQL>
SQL> select ename
2 , months_between(sysdate,bdate)
3 from employees;
ENAME MONTHS_BETWEEN(SYSDATE,BDATE)
-------- -----------------------------
Jason 511.218995
Jerry 500.186737
Jord 489.122221
Mary 478.089963
Joe 467.057705
Black 456
Red 444.993189
White 433.960931
Yellow 422.928673
Pink 411.896415
10 rows selected.
SQL>
SQL> drop table employees;
Table dropped.
MONTHS_BETWEEN(x, y): get the number of months between x and y.
Returned result is a positive number of months
SQL> SELECT MONTHS_BETWEEN("25-MAY-2005", "15-JAN-2005") FROM dual;
MONTHS_BETWEEN("25-MAY-2005","15-JAN-2005")
-------------------------------------------
4.32258065
SQL>
Returned result is a negative number of months
SQL>
SQL> SELECT MONTHS_BETWEEN("15-JAN-2005", "25-MAY-2005") FROM dual;
MONTHS_BETWEEN("15-JAN-2005","25-MAY-2005")
-------------------------------------------
-4.3225806
SQL>
SELECT MONTHS_BETWEEN("15-JAN-2005", "25-MAY-2005")
2 FROM dual;
MONTHS_BETWEEN("15-JAN-2005","25-MAY-2005")
-------------------------------------------
-4.3225806
SQL>
SQL>
Use the MONTHS_BETWEEN function
To find the time difference between two dates, use the MONTHS_BETWEEN function.
The MONTHS_BETWEEN function returns fractional months.
The general format of the function is: MONTHS_BETWEEN(date1, date2)
where the result will be date1 - date2.
SQL>
SQL> SELECT MONTHS_BETWEEN(TO_DATE("22SEP2006","ddMONyyyy"), TO_DATE("13OCT2001","ddMONyyyy")) "Months difference"
2 FROM dual;
Months difference
-----------------
59.2903226
SQL>