Oracle PL/SQL Tutorial/Collections/VARRAY Column — различия между версиями

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Текущая версия на 10:04, 26 мая 2010

Define function to get the first value in varray

SQL>
SQL> column numlist format a60
SQL>
SQL>
SQL> create table employees(
  2    empno      NUMBER(4)
  3  , ename      VARCHAR2(8)
  4  , init       VARCHAR2(5)
  5  , job        VARCHAR2(8)
  6  , mgr        NUMBER(4)
  7  , bdate      DATE
  8  , msal       NUMBER(6,2)
  9  , comm       NUMBER(6,2)
 10  , deptno     NUMBER(2) ) ;
Table created.
SQL>
SQL>
SQL> insert into employees values(1,"Jason",  "N",  "TRAINER", 2,   date "1965-12-18",  800 , NULL,  10);
1 row created.
SQL> insert into employees values(2,"Jerry",  "J",  "SALESREP",3,   date "1966-11-19",  1600, 300,   10);
1 row created.
SQL> insert into employees values(3,"Jord",   "T" , "SALESREP",4,   date "1967-10-21",  1700, 500,   20);
1 row created.
SQL> insert into employees values(4,"Mary",   "J",  "MANAGER", 5,   date "1968-09-22",  1800, NULL,  20);
1 row created.
SQL> insert into employees values(5,"Joe",    "P",  "SALESREP",6,   date "1969-08-23",  1900, 1400,  30);
1 row created.
SQL> insert into employees values(6,"Black",  "R",  "MANAGER", 7,   date "1970-07-24",  2000, NULL,  30);
1 row created.
SQL> insert into employees values(7,"Red",    "A",  "MANAGER", 8,   date "1971-06-25",  2100, NULL,  40);
1 row created.
SQL> insert into employees values(8,"White",  "S",  "TRAINER", 9,   date "1972-05-26",  2200, NULL,  40);
1 row created.
SQL> insert into employees values(9,"Yellow", "C",  "DIRECTOR",10,  date "1973-04-27",  2300, NULL,  20);
1 row created.
SQL> insert into employees values(10,"Pink",  "J",  "SALESREP",null,date "1974-03-28",  2400, 0,     30);
1 row created.
SQL>
SQL>
SQL>
SQL> create table e as select empno, ename, init, mgr, deptno from employees;
Table created.
SQL>
SQL>
SQL> create or replace type numberVarray as varray(4) of varchar2(20);
  2  /
Type created.
SQL>
SQL>
SQL> alter table e add (numlist numberVarray);
Table altered.
SQL>
SQL> describe e;
 Name                                      Null?    Type
 ----------------------------------------- -------- ----------------------------
 EMPNO                                              NUMBER(4)
 ENAME                                              VARCHAR2(8)
 INIT                                               VARCHAR2(5)
 MGR                                                NUMBER(4)
 DEPTNO                                             NUMBER(2)
 NUMLIST                                            NUMBERVARRAY
SQL>
SQL>
SQL> update e set numlist = numberVarray("4231","06-12345678");
10 rows updated.
SQL>
SQL>
SQL> create or replace function ext(p_varray_in numberVarray)
  2  return varchar2
  3  is
  4    v_ext varchar2(20);
  5  begin
  6    v_ext := p_varray_in(1);
  7    return v_ext;
  8  end;
  9  /
Function created.
SQL>
SQL> col ext(numlist) format a12
SQL>
SQL> select ename, init, ext(numlist) from   e;
     last_name       INIT  EXT(NUMLIST)
-------------------- ----- ------------
Jason                N     4231
Jerry                J     4231
Jord                 T     4231
Mary                 J     4231
Joe                  P     4231
Black                R     4231
Red                  A     4231
White                S     4231
Yellow               C     4231
Pink                 J     4231
10 rows selected.
SQL>
SQL> drop table e;
Table dropped.
SQL>
SQL> drop table employees;
Table dropped.


DELETE on varray column

SQL>
SQL> CREATE OR REPLACE TYPE numberVarryType AS VARRAY(10)OF NUMBER(10);
  2  /
Type created.
SQL>
SQL> CREATE TABLE address_list (
  2      list_id VARCHAR2(6)PRIMARY KEY,
  3      direct_addresses numberVarryType
  4  );
Table created.
SQL>
SQL>
SQL> DELETE FROM address_list
  2  WHERE list_id ="OFF102";
0 rows deleted.
SQL>
SQL> drop table address_list;
Table dropped.


Display the structure of a table with a valarray column

SQL>
SQL> CREATE Or Replace TYPE addressVarray AS VARRAY(2) OF VARCHAR2(50);
  2  /
Type created.
SQL> CREATE TABLE employee (
  2    id         INTEGER PRIMARY KEY,
  3    first_name VARCHAR2(10),
  4    last_name  VARCHAR2(10),
  5    addresses  addressVarray
  6  );
Table created.
SQL>
SQL> DESCRIBE employee
 Name         Null?    Type
-------------------------------------
 ID           NOT NULL NUMBER(38)
 FIRST_NAME            VARCHAR2(10)
 LAST_NAME             VARCHAR2(10)
 ADDRESSES             ADDRESSVARRAY
SQL>
SQL> drop table employee;
Table dropped.
SQL>
SQL>


Insert on whole VARRAYS

SQL> -- INSERT
SQL>
SQL> CREATE OR REPLACE TYPE numberVarryType AS VARRAY(10)OF NUMBER(10);
  2  /
Type created.
SQL>
SQL> CREATE TABLE address_list (
  2      list_id VARCHAR2(6)PRIMARY KEY,
  3      direct_addresses numberVarryType
  4  );
Table created.
SQL>
SQL>
SQL> INSERT INTO address_list VALUES("O1",numberVarryType(1001,1002,1003,1004));
1 row created.
SQL>
SQL> DECLARE
  2    v_add_varray numberVarryType :=numberVarryType(2001,2002);
  3  BEGIN
  4    INSERT INTO address_list VALUES ("OFF102",v_add_varray);
  5  END;
  6  /
PL/SQL procedure successfully completed.
SQL>
SQL> drop table address_list;
Table dropped.
SQL>


Modifying Varray Elements

The elements in a varray can only be modified as a whole.



SQL> CREATE Or Replace TYPE addressVarray AS VARRAY(2) OF VARCHAR2(50);
  2  /
Type created.
SQL> CREATE TABLE employee (
  2    id         INTEGER PRIMARY KEY,
  3    first_name VARCHAR2(10),
  4    last_name  VARCHAR2(10),
  5    addresses  addressVarray
  6  );
Table created.
SQL>
SQL> DESCRIBE employee;
 Name          Null?    Type
 ID            NOT NULL NUMBER(38)
 FIRST_NAME             VARCHAR2(10)
 LAST_NAME              VARCHAR2(10)
 ADDRESSES              ADDRESSVARRAY
SQL>
SQL> INSERT INTO employee VALUES (
  2    1, "Steve", "Brown",
  3    addressVarray(
  4      "AAAAAAAAAAAAAAAA",
  5      "BBBBBBBBBBBBBBBB"
  6    )
  7  );
1 row created.
SQL>
SQL> SELECT *
  2  FROM employee;
ID FIRST_NAME LAST_NAME        ADDRESSES
------------------------------------------------------------------------------------
1 Steve      Brown            ADDRESSVARRAY("AAAAAAAAAAAAAAAA", "BBBBBBBBBBBBBBBB")

SQL>
SQL>
SQL> UPDATE employee
  2    SET addresses = addressVarray(
  3      "CCCCCCCCCCCCCCC",
  4      "BBBBBBBBBBBBBBB"
  5    )
  6  WHERE id = 1;
1 row updated.
SQL>
SQL> SELECT *
  2  FROM employee;
ID FIRST_NAME LAST_NAME     ADDRESSES
------------------------------------------------------------------------
1 Steve      Brown         ADDRESSVARRAY("CCCCCCCCCCCCCCC", "BBBBBBBBBBBBBBB")

SQL>
SQL>
SQL> drop table employee;
Table dropped.
SQL>
SQL>


Populating a Varray with Elements

You can populate the elements in a varray using an INSERT statement.



SQL>
SQL>
SQL> CREATE Or Replace TYPE addressVarray AS VARRAY(2) OF VARCHAR2(50);
  2  /
Type created.
SQL> CREATE TABLE employee (
  2    id         INTEGER PRIMARY KEY,
  3    first_name VARCHAR2(10),
  4    last_name  VARCHAR2(10),
  5    addresses  addressVarray
  6  );
Table created.
SQL>
SQL> DESCRIBE employee;
 Name            Null?    Type
 ID              NOT NULL NUMBER(38)
 FIRST_NAME               VARCHAR2(10)
 LAST_NAME                VARCHAR2(10)
 ADDRESSES                ADDRESSVARRAY
SQL>
SQL> INSERT INTO employee VALUES (
  2    1, "Steve", "Brown",
  3    addressVarray(
  4      "AAAAAAAAAAAAAAAA",
  5      "BBBBBBBBBBBBBBBB"
  6    )
  7  );
1 row created.
SQL>
SQL> SELECT *
  2  FROM employee;
ID FIRST_NAME LAST_NAME           ADDRESSES
----------------------------------------------------------------------------------------
1 Steve      Brown                ADDRESSVARRAY("AAAAAAAAAAAAAAAA", "BBBBBBBBBBBBBBBB")

SQL>
SQL>
SQL> drop table employee;
Table dropped.
SQL>
SQL>


Selecting Varray Elements

SQL>
SQL>
SQL>
SQL> CREATE Or Replace TYPE addressVarray AS VARRAY(2) OF VARCHAR2(50);
  2  /
Type created.
SQL>
SQL> CREATE TABLE employee (
  2    id         INTEGER PRIMARY KEY,
  3    first_name VARCHAR2(10),
  4    last_name  VARCHAR2(10),
  5    addresses  addressVarray
  6  );
Table created.
SQL>
SQL> DESCRIBE employee
 Name           Null?    Type
 ID             NOT NULL NUMBER(38)
 FIRST_NAME              VARCHAR2(10)
 LAST_NAME               VARCHAR2(10)
 ADDRESSES               ADDRESSVARRAY
SQL>
SQL> INSERT INTO employee VALUES (
  2    1, "Steve", "Brown",
  3    addressVarray(
  4      "AAAAAAAAAAAAAAAA",
  5      "BBBBBBBBBBBBBBBB"
  6    )
  7  );
1 row created.
SQL>
SQL> SELECT *
  2  FROM employee;
ID FIRST_NAME LAST_NAME            ADDRESSES
------------------------------------------------------------------------------------------
1 Steve      Brown                ADDRESSVARRAY("AAAAAAAAAAAAAAAA", "BBBBBBBBBBBBBBBB")

SQL>
SQL> SELECT addresses
  2  FROM employee;
ADDRESSES
--------------------------------------------------------
ADDRESSVARRAY("AAAAAAAAAAAAAAAA", "BBBBBBBBBBBBBBBB")
SQL>
SQL>
SQL> drop table employee;
Table dropped.
SQL>


SELECT into with varray column

SQL>
SQL>
SQL> CREATE OR REPLACE TYPE numberVarryType AS VARRAY(10)OF NUMBER(10);
  2  /
Type created.
SQL>
SQL> CREATE TABLE address_list (
  2      list_id VARCHAR2(6)PRIMARY KEY,
  3      direct_addresses numberVarryType
  4  );
Table created.
SQL>
SQL>
SQL> DECLARE
  2    v_add_varray address_list.direct_addresses%TYPE;
  3  BEGIN
  4    SELECT direct_addresses INTO v_add_varray FROM address_list WHERE list_id ="OFF101";
  5
  6    FOR idx IN 1..v_add_varray.COUNT LOOP
  7      DBMS_OUTPUT.PUT_LINE(TO_CHAR(v_add_varray(idx)));
  8    END LOOP;
  9  EXCEPTION WHEN OTHERS THEN
 10    DBMS_OUTPUT.PUT_LINE(SQLERRM);
 11  END;
 12  /
ORA-01403: no data found
PL/SQL procedure successfully completed.
SQL>
SQL> drop table address_list;
Table dropped.


Set empty varray value

SQL>
SQL>
SQL> column numlist format a60
SQL>
SQL>
SQL> create table employees(
  2    empno      NUMBER(4)
  3  , ename      VARCHAR2(8)
  4  , init       VARCHAR2(5)
  5  , job        VARCHAR2(8)
  6  , mgr        NUMBER(4)
  7  , bdate      DATE
  8  , msal       NUMBER(6,2)
  9  , comm       NUMBER(6,2)
 10  , deptno     NUMBER(2) ) ;
Table created.
SQL>
SQL>
SQL> insert into employees values(1,"Jason",  "N",  "TRAINER", 2,   date "1965-12-18",  800 , NULL,  10);
1 row created.
SQL> insert into employees values(2,"Jerry",  "J",  "SALESREP",3,   date "1966-11-19",  1600, 300,   10);
1 row created.
SQL> insert into employees values(3,"Jord",   "T" , "SALESREP",4,   date "1967-10-21",  1700, 500,   20);
1 row created.
SQL> insert into employees values(4,"Mary",   "J",  "MANAGER", 5,   date "1968-09-22",  1800, NULL,  20);
1 row created.
SQL> insert into employees values(5,"Joe",    "P",  "SALESREP",6,   date "1969-08-23",  1900, 1400,  30);
1 row created.
SQL> insert into employees values(6,"Black",  "R",  "MANAGER", 7,   date "1970-07-24",  2000, NULL,  30);
1 row created.
SQL> insert into employees values(7,"Red",    "A",  "MANAGER", 8,   date "1971-06-25",  2100, NULL,  40);
1 row created.
SQL> insert into employees values(8,"White",  "S",  "TRAINER", 9,   date "1972-05-26",  2200, NULL,  40);
1 row created.
SQL> insert into employees values(9,"Yellow", "C",  "DIRECTOR",10,  date "1973-04-27",  2300, NULL,  20);
1 row created.
SQL> insert into employees values(10,"Pink",  "J",  "SALESREP",null,date "1974-03-28",  2400, 0,     30);
1 row created.
SQL>
SQL>
SQL>
SQL> create table e
  2  as
  3  select empno, ename, init, mgr, deptno
  4  from   employees;
Table created.
SQL>
SQL>
SQL> create or replace type numberVarray
  2  as varray(4) of varchar2(20);
  3  /
Type created.
SQL>
SQL>
SQL> alter table e add (numlist numberVarray);
Table altered.
SQL>
SQL> describe e;
 Name                                      Null?    Type
 ----------------------------------------- -------- ----------------------------
 EMPNO                                              NUMBER(4)
 ENAME                                              VARCHAR2(8)
 INIT                                               VARCHAR2(5)
 MGR                                                NUMBER(4)
 DEPTNO                                             NUMBER(2)
 NUMLIST                                            NUMBERVARRAY
SQL>
SQL>
SQL>
SQL> update e
  2  set    numlist = numberVarray();
10 rows updated.

SQL>
SQL> drop table e;
Table dropped.
SQL>
SQL> drop table employees;
Table dropped.
SQL>
SQL> drop type numberVarray;
Type dropped.


Stored VARRAYS

SQL> CREATE OR REPLACE TYPE numberVarryType AS VARRAY(10)OF NUMBER(10);
  2  /
Type created.
SQL>
SQL> CREATE TABLE address_list (
  2      list_id VARCHAR2(6)PRIMARY KEY,
  3      direct_addresses numberVarryType
  4  );
Table created.
SQL>
SQL> drop table address_list;
Table dropped.
SQL>
SQL>


UPDATE on varray column

SQL> CREATE OR REPLACE TYPE numberVarryType AS VARRAY(10)OF NUMBER(10);
  2  /
Type created.
SQL>
SQL> CREATE TABLE address_list (
  2      list_id VARCHAR2(6)PRIMARY KEY,
  3      direct_addresses numberVarryType
  4  );
Table created.
SQL>
SQL> UPDATE address_list
  2  SET direct_addresses =numberVarryType(1011,1012,1013)
  3  WHERE list_id ="OFF102";
0 rows updated.
SQL>
SQL>
SQL> drop table address_list;
Table dropped.


UPDATE on varray column in PL/SQL block

SQL>
SQL> CREATE OR REPLACE TYPE numberVarryType AS VARRAY(10)OF NUMBER(10);
  2  /
Type created.
SQL>
SQL> CREATE TABLE address_list (
  2      list_id VARCHAR2(6)PRIMARY KEY,
  3      direct_addresses numberVarryType
  4  );
Table created.
SQL>
SQL> DECLARE
  2    v_add_varray numberVarryType :=numberVarryType(1011,1012,1013);
  3  BEGIN
  4    UPDATE address_list
  5    SET direct_addresses =v_add_varray
  6    WHERE list_id ="OFF102";
  7  END;
  8  /
PL/SQL procedure successfully completed.
SQL>
SQL> drop table address_list;
Table dropped.
SQL>
SQL>
SQL>


Using a Varray Type to Define a Column in a Table

SQL>
SQL> CREATE Or Replace TYPE addressVarray AS VARRAY(2) OF VARCHAR2(50);
  2  /
Type created.
SQL> CREATE TABLE employee (
  2    id         INTEGER PRIMARY KEY,
  3    first_name VARCHAR2(10),
  4    last_name  VARCHAR2(10),
  5    addresses  addressVarray
  6  );
Table created.
SQL>
SQL> drop table employee;
Table dropped.
SQL>
SQL>