Oracle PL/SQL/Regular Expressions/Wild Card — различия между версиями

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Версия 13:45, 26 мая 2010

"." matches anything

SQL> create table TestTable(
  2    ID                    VARCHAR2(4 BYTE)         NOT NULL,
  3    Description           VARCHAR2(40 BYTE)
  4  )
  5  /
Table created.
SQL>
SQL>
SQL> insert into TestTable (ID, Description) values("1","1234 5th Street");
1 row created.
SQL> insert into TestTable (ID, Description) values("2","1 Culloden Street");
1 row created.
SQL> insert into TestTable (ID, Description) values("3","1234 Road");
1 row created.
SQL> insert into TestTable (ID, Description) values("4","33 Thrid Road");
1 row created.
SQL> insert into TestTable (ID, Description) values("5","One than another");
1 row created.
SQL> insert into TestTable (ID, Description) values("6","2003 Movie");
1 row created.
SQL> insert into TestTable (ID, Description) values("7","Start With Letters");
1 row created.
SQL>
SQL> select * from TestTable;
ID   DESCRIPTION
---- ----------------------------------------
1    1234 5th Street
2    1 Culloden Street
3    1234 Road
4    33 Thrid Road
5    One than another
6    2003 Movie
7    Start With Letters
7 rows selected.
SQL>
SQL>
SQL>
SQL> --"." matches anything.
SQL>
SQL> SELECT Description, REGEXP_INSTR(Description,"O.e") where_it_is
  2  FROM testTable
  3  WHERE REGEXP_INSTR(Description,"O.e") > 0;
DESCRIPTION                              WHERE_IT_IS
---------------------------------------- -----------
One than another                                   1
SQL>
SQL>
SQL>
SQL>
SQL>
SQL> drop table TestTable;
Table dropped.
SQL>
SQL>
SQL>



"?": match exactly zero or one repetition

SQL> --"?": match exactly zero or one repetition
SQL>
SQL> SELECT REGEXP_SUBSTR("Yababa dababa do","a.?a") FROM dual;
REG
---
aba
SQL>



"+": match one or more repetitions

SQL> -- "+": match one or more repetitions
SQL>
SQL> SELECT REGEXP_SUBSTR("Yababa dababa do","a.+a") FROM dual;
REGEXP_SUBST
------------
ababa dababa
SQL>



"*" (match zero or more repetitions)

SQL> --"*" (match zero or more repetitions):
SQL>
SQL> SELECT REGEXP_SUBSTR("Yababa dababa do","a.*a") FROM dual;
REGEXP_SUBST
------------
ababa dababa
SQL>



REGEXP_INSTR(description, "e.+e"): An "e" followed by any number of other characters and then another "e"

SQL> create table TestTable(
  2    ID                    VARCHAR2(4 BYTE)         NOT NULL,
  3    Description           VARCHAR2(30 BYTE)
  4  )
  5  /
Table created.
SQL>
SQL>
SQL> insert into TestTable (ID, Description) values("1","1234 5th Street");
1 row created.
SQL> insert into TestTable (ID, Description) values("2","1 Culloden Street");
1 row created.
SQL> insert into TestTable (ID, Description) values("3","1234 Road");
1 row created.
SQL> insert into TestTable (ID, Description) values("4","33 Thrid Road");
1 row created.
SQL> insert into TestTable (ID, Description) values("5","One than another");
1 row created.
SQL> insert into TestTable (ID, Description) values("6","2003 Movie");
1 row created.
SQL> insert into TestTable (ID, Description) values("7","Start With Letters");
1 row created.
SQL>
SQL> select * from TestTable;
ID   DESCRIPTION
---- ------------------------------
1    1234 5th Street
2    1 Culloden Street
3    1234 Road
4    33 Thrid Road
5    One than another
6    2003 Movie
7    Start With Letters
7 rows selected.
SQL>
SQL>
SQL> -- REGEXP_INSTR(description, "e.+e"): An "e" followed by any number of other characters and then another "e"
SQL>
SQL> SELECT description,
  2      REGEXP_SUBSTR(description,"e.+e"),
  3      REGEXP_INSTR(description, "e.+e") "@"
  4  FROM testTable;
DESCRIPTION                    REGEXP_SUBSTR(DESCRIPTION,"E.+          @
------------------------------ ------------------------------ ----------
1234 5th Street                                                        0
1 Culloden Street              en Stree                                9
1234 Road                                                              0
33 Thrid Road                                                          0
One than another               e than anothe                           3
2003 Movie                                                             0
Start With Letters             ette                                   13
7 rows selected.
SQL>
SQL> drop table TestTable;
Table dropped.
SQL>
SQL>
SQL>



REGEXP_INSTR(description,"e.e"): Find a letter and then whatever until there was another of the same letter

SQL> create table TestTable(
  2    ID                    VARCHAR2(4 BYTE)         NOT NULL,
  3    Description           VARCHAR2(30 BYTE)
  4  )
  5  /
Table created.
SQL>
SQL>
SQL> insert into TestTable (ID, Description) values("1","1234 5th Street");
1 row created.
SQL> insert into TestTable (ID, Description) values("2","1 Culloden Street");
1 row created.
SQL> insert into TestTable (ID, Description) values("3","1234 Road");
1 row created.
SQL> insert into TestTable (ID, Description) values("4","33 Thrid Road");
1 row created.
SQL> insert into TestTable (ID, Description) values("5","One than another");
1 row created.
SQL> insert into TestTable (ID, Description) values("6","2003 Movie");
1 row created.
SQL> insert into TestTable (ID, Description) values("7","eSetarte With Letterse");
1 row created.
SQL>
SQL> select * from TestTable;
ID   DESCRIPTION
---- ------------------------------
1    1234 5th Street
2    1 Culloden Street
3    1234 Road
4    33 Thrid Road
5    One than another
6    2003 Movie
7    eSetarte With Letterse
7 rows selected.
SQL>
SQL> -- Find a letter and then whatever until there was another of the same letter
SQL>
SQL>
SQL> SELECT description,
  2      REGEXP_INSTR(description,"e.e") where_pattern_starts
  3  FROM testTable
  4  WHERE REGEXP_INSTR(description,"e.e") > 0;
DESCRIPTION                    WHERE_PATTERN_STARTS
------------------------------ --------------------
eSetarte With Letterse                            1
SQL>
SQL> drop table TestTable;
Table dropped.
SQL>
SQL>



REGEXP_INSTR(description,"F.")

SQL> create table TestTable(
  2    ID                    VARCHAR2(4 BYTE)         NOT NULL,
  3    Description           VARCHAR2(40 BYTE)
  4  )
  5  /
Table created.
SQL>
SQL>
SQL> insert into TestTable (ID, Description) values("1","1234 5th Street");
1 row created.
SQL> insert into TestTable (ID, Description) values("2","1 Culloden Street");
1 row created.
SQL> insert into TestTable (ID, Description) values("3","1234 First Road");
1 row created.
SQL> insert into TestTable (ID, Description) values("4","33 Thrid Road");
1 row created.
SQL> insert into TestTable (ID, Description) values("5","One than another");
1 row created.
SQL> insert into TestTable (ID, Description) values("6","2003 Movie");
1 row created.
SQL> insert into TestTable (ID, Description) values("7","Start With Letters");
1 row created.
SQL>
SQL> select * from TestTable;
ID   DESCRIPTION
---- ----------------------------------------
1    1234 5th Street
2    1 Culloden Street
3    1234 First Road
4    33 Thrid Road
5    One than another
6    2003 Movie
7    Start With Letters
7 rows selected.
SQL>
SQL>
SQL>
SQL> SELECT description, REGEXP_INSTR(description,"F.") where_it_is
  2  FROM testTable
  3  WHERE REGEXP_INSTR(description,"F.") > 0;
DESCRIPTION                              WHERE_IT_IS
---------------------------------------- -----------
1234 First Road                                    6
SQL>
SQL>
SQL>
SQL> drop table TestTable;
Table dropped.
SQL>
SQL>
SQL>



REGEXP_INSTR(description,"i.i"): "i" followed by any one character, followed by another "i"

SQL> create table TestTable(
  2    ID                    VARCHAR2(4 BYTE)         NOT NULL,
  3    Description           VARCHAR2(30 BYTE)
  4  )
  5  /
Table created.
SQL>
SQL>
SQL> insert into TestTable (ID, Description) values("1","1234 5th Street");
1 row created.
SQL> insert into TestTable (ID, Description) values("2","1 Culloden Street");
1 row created.
SQL> insert into TestTable (ID, Description) values("3","1234 Road");
1 row created.
SQL> insert into TestTable (ID, Description) values("4","33 Thrid Road");
1 row created.
SQL> insert into TestTable (ID, Description) values("5","One than another");
1 row created.
SQL> insert into TestTable (ID, Description) values("6","2003 Movie");
1 row created.
SQL> insert into TestTable (ID, Description) values("7","iSitart With Letters");
1 row created.
SQL>
SQL> select * from TestTable;
ID   DESCRIPTION
---- ------------------------------
1    1234 5th Street
2    1 Culloden Street
3    1234 Road
4    33 Thrid Road
5    One than another
6    2003 Movie
7    iSitart With Letters
7 rows selected.
SQL>
SQL>
SQL> -- REGEXP_INSTR(description,"i.i"): "i" followed by any one character, followed by another "i"
SQL>
SQL> SELECT description,
  2      REGEXP_INSTR(description,"i.i") where_pattern_starts
  3  FROM testTable
  4  WHERE REGEXP_INSTR(description,"i.i") > 0;
DESCRIPTION                    WHERE_PATTERN_STARTS
------------------------------ --------------------
iSitart With Letters                              1
SQL>
SQL>
SQL>
SQL> drop table TestTable;
Table dropped.
SQL>
SQL>



REGEXP_SUBSTR("a","ab+")

SQL>
SQL> SELECT REGEXP_SUBSTR("a","ab+") FROM dual;
R
-

SQL>



REGEXP_SUBSTR("abbbb","ab+")

SQL> --if we have succeeding "b"s, we get the same greedy result as with "*":
SQL>
SQL> SELECT REGEXP_SUBSTR("abbbb","ab+") FROM dual;
REGEX
-----
abbbb
SQL>
SQL>



REGEXP_SUBSTR("abbbb","ab*") (2)

SQL>
SQL> SELECT REGEXP_SUBSTR("abbbb","ab*") FROM dual;
REGEX
-----
abbbb
SQL>



REGEXP_SUBSTR(description,"e.*e")

SQL> create table TestTable(
  2    ID                    VARCHAR2(4 BYTE)         NOT NULL,
  3    Description           VARCHAR2(30 BYTE)
  4  )
  5  /
Table created.
SQL>
SQL>
SQL> insert into TestTable (ID, Description) values("1","1234 5th Street");
1 row created.
SQL> insert into TestTable (ID, Description) values("2","1 Culloden Street");
1 row created.
SQL> insert into TestTable (ID, Description) values("3","1234 Road");
1 row created.
SQL> insert into TestTable (ID, Description) values("4","33 Thrid Road");
1 row created.
SQL> insert into TestTable (ID, Description) values("5","One than another");
1 row created.
SQL> insert into TestTable (ID, Description) values("6","2003 Movie");
1 row created.
SQL> insert into TestTable (ID, Description) values("7","Start With Letters");
1 row created.
SQL>
SQL> select * from TestTable;
ID   DESCRIPTION
---- ------------------------------
1    1234 5th Street
2    1 Culloden Street
3    1234 Road
4    33 Thrid Road
5    One than another
6    2003 Movie
7    Start With Letters
7 rows selected.
SQL>
SQL>
SQL> -- Note the greedy "+" finding one or more things between "e"s; it "stretches" the 
--letters between "e"s as far as possible. Note that the query returned "eenbrie" and not just "ee".
SQL>
SQL> SELECT description, REGEXP_SUBSTR(description,"e.*e") FROM testTable;
DESCRIPTION                    REGEXP_SUBSTR(DESCRIPTION,"E.*
------------------------------ ------------------------------
1234 5th Street                ee
1 Culloden Street              en Stree
1234 Road
33 Thrid Road
One than another               e than anothe
2003 Movie
Start With Letters             ette
7 rows selected.
SQL>
SQL>
SQL>
SQL> drop table TestTable;
Table dropped.
SQL>
SQL>
SQL>



REGEXP_SUBSTR("Yababa dababa do","a.a")

SQL> SELECT REGEXP_SUBSTR("Yababa dababa do","a.a") FROM dual;
REG
---
aba
SQL>



To see the difference between "*" and "+"

SQL> -- To see the difference between "*" and "+", consider the next four queries.
SQL>
SQL> -- Here, we are asking to match an "a" and zero or more "b"s:
SQL>
SQL> SELECT REGEXP_SUBSTR("a","ab*") FROM dual;
R
-
a
SQL>
SQL>



Use the non-greedy "?"

SQL> create table TestTable(
  2    ID                    VARCHAR2(4 BYTE)         NOT NULL,
  3    Description           VARCHAR2(30 BYTE)
  4  )
  5  /
Table created.
SQL>
SQL>
SQL> insert into TestTable (ID, Description) values("1","1234 5th Street");
1 row created.
SQL> insert into TestTable (ID, Description) values("2","1 Culloden Street");
1 row created.
SQL> insert into TestTable (ID, Description) values("3","1234 Road");
1 row created.
SQL> insert into TestTable (ID, Description) values("4","33 Thrid Road");
1 row created.
SQL> insert into TestTable (ID, Description) values("5","One than another");
1 row created.
SQL> insert into TestTable (ID, Description) values("6","2003 Movie");
1 row created.
SQL> insert into TestTable (ID, Description) values("7","Start With Letters");
1 row created.
SQL>
SQL> select * from TestTable;
ID   DESCRIPTION
---- ------------------------------
1    1234 5th Street
2    1 Culloden Street
3    1234 Road
4    33 Thrid Road
5    One than another
6    2003 Movie
7    Start With Letters
7 rows selected.
SQL>
SQL>
SQL> -- Use the non-greedy "?";
SQL>
SQL> SELECT description,
  2      REGEXP_SUBSTR(description,"e.?e")
  3  FROM testTable;
DESCRIPTION                    REGEXP_SUBSTR(DESCRIPTION,"E.?
------------------------------ ------------------------------
1234 5th Street                ee
1 Culloden Street              ee
1234 Road
33 Thrid Road
One than another
2003 Movie
Start With Letters
7 rows selected.
SQL>
SQL> drop table TestTable;
Table dropped.
SQL>
SQL>
SQL>