Oracle PL/SQL/PL SQL/sqlcode — различия между версиями
Admin (обсуждение | вклад) м (1 версия) |
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Текущая версия на 09:59, 26 мая 2010
Get error count from sql%bulk_exceptions.count
SQL> create table myTable (
2 x number not null );
Table created.
SQL>
SQL> set serverout on
SQL> declare
2 type numlist is table of number
3 index by binary_integer;
4 n numlist;
5 begin
6 for i in 1 .. 50 loop
7 n(i) := i;
8 end loop;
9
10 n(37) := null; -- will cause a problem
11
12 forall i in 1 .. 50 save exceptions
13 insert into myTable values (n(i));
14
15 exception when others then
16 dbms_output.put_line("Errors:"||sql%bulk_exceptions.count);
17 for i in 1 .. sql%bulk_exceptions.count loop
18 dbms_output.put_line("index:"||sql%bulk_exceptions(i).error_index);
19 dbms_output.put_line("code:"||sql%bulk_exceptions(i).error_code);
20 dbms_output.put_line("message:");
21 dbms_output.put_line(sqlerrm(sql%bulk_exceptions(i).error_code));
22 end loop;
23 end;
24 /
Errors:1
index:37
code:1400
message:
-1400: non-ORACLE exception
PL/SQL procedure successfully completed.
SQL>
SQL>
SQL> drop table myTable;
Table dropped.
sql code and sql errm
SQL> set serverout on;
SQL> -- create demo table
SQL> create table Employee(
2 ID VARCHAR2(4 BYTE) NOT NULL,
3 First_Name VARCHAR2(10 BYTE),
4 Last_Name VARCHAR2(10 BYTE),
5 Start_Date DATE,
6 End_Date DATE,
7 Salary Number(8,2),
8 City VARCHAR2(10 BYTE),
9 Description VARCHAR2(15 BYTE)
10 )
11 /
Table created.
SQL>
SQL> -- prepare data
SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)
2 values ("01","Jason", "Martin", to_date("19960725","YYYYMMDD"), to_date("20060725","YYYYMMDD"), 1234.56, "Toronto", "Programmer")
3 /
1 row created.
SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)
2 values("02","Alison", "Mathews", to_date("19760321","YYYYMMDD"), to_date("19860221","YYYYMMDD"), 6661.78, "Vancouver","Tester")
3 /
1 row created.
SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)
2 values("03","James", "Smith", to_date("19781212","YYYYMMDD"), to_date("19900315","YYYYMMDD"), 6544.78, "Vancouver","Tester")
3 /
1 row created.
SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)
2 values("04","Celia", "Rice", to_date("19821024","YYYYMMDD"), to_date("19990421","YYYYMMDD"), 2344.78, "Vancouver","Manager")
3 /
1 row created.
SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)
2 values("05","Robert", "Black", to_date("19840115","YYYYMMDD"), to_date("19980808","YYYYMMDD"), 2334.78, "Vancouver","Tester")
3 /
1 row created.
SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)
2 values("06","Linda", "Green", to_date("19870730","YYYYMMDD"), to_date("19960104","YYYYMMDD"), 4322.78,"New York", "Tester")
3 /
1 row created.
SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)
2 values("07","David", "Larry", to_date("19901231","YYYYMMDD"), to_date("19980212","YYYYMMDD"), 7897.78,"New York", "Manager")
3 /
1 row created.
SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)
2 values("08","James", "Cat", to_date("19960917","YYYYMMDD"), to_date("20020415","YYYYMMDD"), 1232.78,"Vancouver", "Tester")
3 /
1 row created.
SQL>
SQL>
SQL>
SQL> -- display data in the table
SQL> select * from Employee
2 /
ID FIRST_NAME LAST_NAME START_DAT END_DATE SALARY CITY DESCRIPTION
---- ---------- ---------- --------- --------- ---------- ---------- ---------------
01 Jason Martin 25-JUL-96 25-JUL-06 1234.56 Toronto Programmer
02 Alison Mathews 21-MAR-76 21-FEB-86 6661.78 Vancouver Tester
03 James Smith 12-DEC-78 15-MAR-90 6544.78 Vancouver Tester
04 Celia Rice 24-OCT-82 21-APR-99 2344.78 Vancouver Manager
05 Robert Black 15-JAN-84 08-AUG-98 2334.78 Vancouver Tester
06 Linda Green 30-JUL-87 04-JAN-96 4322.78 New York Tester
07 David Larry 31-DEC-90 12-FEB-98 7897.78 New York Manager
08 James Cat 17-SEP-96 15-APR-02 1232.78 Vancouver Tester
8 rows selected.
SQL>
SQL>
SQL> -- sql code and sql errm
SQL>
SQL> declare
2 l_emp employee%rowtype;
3 begin
4 select * into l_emp from employee;
5
6 dbms_output.put_line("EMPNO: " || l_emp.id);
7 dbms_output.put_line("ENAME: " || l_emp.first_name);
8 exception
9 when others then
10 dbms_output.put("Exception encountered! (");
11 dbms_output.put_line(sqlcode || "): " || sqlerrm);
12 raise;
13 end;
14 /
Exception encountered! (-1422): ORA-01422: exact fetch returns more than requested number of rows
declare
*
ERROR at line 1:
ORA-01422: exact fetch returns more than requested number of rows
ORA-06512: at line 12
SQL>
SQL>
SQL>
SQL>
SQL> -- clean the table
SQL> drop table Employee
2 /
Table dropped.
SQL>
SQL>
This script demonstrates error functions SQLERRM and SQLCODE
SQL>
SQL> SET SERVEROUTPUT ON
SQL> DECLARE
2 v_error VARCHAR2(10);
3 BEGIN
4 SELECT dummy INTO v_error FROM dual WHERE 1=2;
5 EXCEPTION
6 WHEN OTHERS
7 THEN
8 DBMS_OUTPUT.PUT_LINE("SQLERRM: "||SQLERRM);
9 DBMS_OUTPUT.PUT_LINE("SQLCODE: "||SQLCODE);
10 END;
11 /
SQLERRM: ORA-01403: no data found
SQLCODE: 100
PL/SQL procedure successfully completed.
SQL>
SQL>