SQL Server/T-SQL Tutorial/Date Functions/DATENAME — различия между версиями

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м (1 версия)
 
(нет различий)

Текущая версия на 10:23, 26 мая 2010

Combining this with DATEADD allows you to find out the month name in two months time:

16>
17> SELECT DATENAME(mm,DATEADD(mm,2,GETDATE()))
18> GO
------------------------------
December
(1 rows affected)
Year - yy, yyyy
Month - mm, m
Week - wk, ww
Day - dd, d
Hour - hh
Minute - mi, n
quarter - qq
day of year - dy
seconds - ss
milliseconds - ms


DATENAME returns date"s character string representation: DATENAME(datepart,date)

4>
5> SELECT DATENAME(DW,"10/01/97")
6> GO
------------------------------
Wednesday
(1 rows affected)
1>


Displaying the String Value for Part of a Date

DATENAME returns a string value for the part of a date specified in the datepart code. The syntax is:
DATENAME ( datepart , date )
The second parameter designates the date to base the string value on.


Displaying the String Value for Part of a Date: Show the start Date"s day of the week

3>
4> CREATE TABLE employee(
5>    id          INTEGER NOT NULL PRIMARY KEY,
6>    first_name  VARCHAR(10),
7>    last_name   VARCHAR(10),
8>    salary      DECIMAL(10,2),
9>    start_Date  DATETIME,
10>    region      VARCHAR(10),
11>    city        VARCHAR(20),
12>    managerid   INTEGER
13> );
14> GO
1> INSERT INTO employee VALUES (1, "Jason" ,  "Martin", 5890,"2005-03-22","North","Vancouver",3);
2> GO
(1 rows affected)
1> INSERT INTO employee VALUES (2, "Alison",  "Mathews",4789,"2003-07-21","South","Utown",4);
2> GO
(1 rows affected)
1> INSERT INTO employee VALUES (3, "James" ,  "Smith",  6678,"2001-12-01","North","Paris",5);
2> GO
(1 rows affected)
1> INSERT INTO employee VALUES (4, "Celia" ,  "Rice",   5567,"2006-03-03","South","London",6);
2> GO
(1 rows affected)
1> INSERT INTO employee VALUES (5, "Robert",  "Black",  4467,"2004-07-02","East","Newton",7);
2> GO
(1 rows affected)
1> INSERT INTO employee VALUES (6, "Linda" ,  "Green" , 6456,"2002-05-19","East","Calgary",8);
2> GO
(1 rows affected)
1> INSERT INTO employee VALUES (7, "David" ,  "Larry",  5345,"2008-03-18","West","New York",9);
2> GO
(1 rows affected)
1> INSERT INTO employee VALUES (8, "James" ,  "Cat",    4234,"2007-07-17","West","Regina",9);
2> GO
(1 rows affected)
1> INSERT INTO employee VALUES (9, "Joan"  ,  "Act",    6123,"2001-04-16","North","Toronto",10);
2> GO
(1 rows affected)
1>
2> select * from employee;
3> GO
id          first_name last_name  salary       start_Date              region     city                 managerid
----------- ---------- ---------- ------------ ----------------------- ---------- -------------------- -----------
          1 Jason      Martin          5890.00 2005-03-22 00:00:00.000 North      Vancouver                      3
          2 Alison     Mathews         4789.00 2003-07-21 00:00:00.000 South      Utown                          4
          3 James      Smith           6678.00 2001-12-01 00:00:00.000 North      Paris                          5
          4 Celia      Rice            5567.00 2006-03-03 00:00:00.000 South      London                         6
          5 Robert     Black           4467.00 2004-07-02 00:00:00.000 East       Newton                         7
          6 Linda      Green           6456.00 2002-05-19 00:00:00.000 East       Calgary                        8
          7 David      Larry           5345.00 2008-03-18 00:00:00.000 West       New York                       9
          8 James      Cat             4234.00 2007-07-17 00:00:00.000 West       Regina                         9
          9 Joan       Act             6123.00 2001-04-16 00:00:00.000 North      Toronto                       10
(9 rows affected)
1>
2>
3>
4> SELECT ID,Start_Date,
5> DATENAME(dw, Start_Date) WeekDay
6> FROM Employee
7> GO
ID          Start_Date              WeekDay
----------- ----------------------- ------------------------------
          1 2005-03-22 00:00:00.000 Tuesday
          2 2003-07-21 00:00:00.000 Monday
          3 2001-12-01 00:00:00.000 Saturday
          4 2006-03-03 00:00:00.000 Friday
          5 2004-07-02 00:00:00.000 Friday
          6 2002-05-19 00:00:00.000 Sunday
          7 2008-03-18 00:00:00.000 Tuesday
          8 2007-07-17 00:00:00.000 Tuesday
          9 2001-04-16 00:00:00.000 Monday
(9 rows affected)
1>
2> drop table employee;
3> GO


select DATENAME(day, "2002-35:00")

2> select DATENAME(day, "2002-09-30 11:35:00")
3> GO
------------------------------
30
(1 rows affected)
1>


select DATENAME(dayofyear, "2002-35:00")

2> select DATENAME(dayofyear, "2002-09-30 11:35:00")
3>
6> GO
------------------------------
273
(1 rows affected)


select DATENAME(hour, "2002-35:00")

2> select DATENAME(hour, "2002-09-30 11:35:00")
3> GO
------------------------------
11
(1 rows affected)
1>


select DATENAME(minute, "2002-35:00")

3> select DATENAME(minute, "2002-09-30 11:35:00")
4> GO
------------------------------
35
(1 rows affected)
1>


select DATENAME(month,"2002-09-30")

3> select DATENAME(month,"2002-09-30")
4> GO
------------------------------
September
(1 rows affected)


select DATENAME(month, "2002-35:00")

3> select DATENAME(month, "2002-09-30 11:35:00")
4> GO
------------------------------
September
(1 rows affected)
1>


select DATENAME(quarter, "2002-35:00")

3> select DATENAME(quarter, "2002-09-30 11:35:00")
4> GO
------------------------------
3
(1 rows affected)


select DATENAME(second, "2002-35:00")

3> select DATENAME(second, "2002-09-30 11:35:00")
4> GO
------------------------------
0
(1 rows affected)
1>


select DATENAME(week, "2002-35:00")

5> select DATENAME(week, "2002-09-30 11:35:00")
------------------------------
40
(1 rows affected)


select DATENAME(weekday, "2002-35:00")

2> select DATENAME(weekday, "2002-09-30 11:35:00")
3> GO
------------------------------
Monday
(1 rows affected)
1>


select DATENAME(year, "2002-35:00")

3> select DATENAME(year, "2002-09-30 11:35:00")
4> GO
------------------------------
2002
(1 rows affected)