SQL Server/T-SQL/Math Functions/FLOOR — различия между версиями

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м (1 версия)
 
(нет различий)

Текущая версия на 10:20, 26 мая 2010

FLOOR(23.7)

1> SELECT FLOOR(23.7)
2> GO
-----
   23
(1 rows affected)
1>



Floor a value

1> create table employee(
2>     ID          int,
3>     name        nvarchar (10),
4>     salary      int,
5>     start_date  datetime,
6>     city        nvarchar (10),
7>     region      char (1))
8> GO
1>
2> insert into employee (ID, name,    salary, start_date, city,       region)
3>               values (1,  "Jason", 40420,  "02/01/94", "New York", "W")
4> GO
(1 rows affected)
1> insert into employee (ID, name,    salary, start_date, city,       region)
2>               values (2,  "Robert",14420,  "01/02/95", "Vancouver","N")
3> GO
(1 rows affected)
1> insert into employee (ID, name,    salary, start_date, city,       region)
2>               values (3,  "Celia", 24020,  "12/03/96", "Toronto",  "W")
3> GO
(1 rows affected)
1> insert into employee (ID, name,    salary, start_date, city,       region)
2>               values (4,  "Linda", 40620,  "11/04/97", "New York", "N")
3> GO
(1 rows affected)
1> insert into employee (ID, name,    salary, start_date, city,       region)
2>               values (5,  "David", 80026,  "10/05/98", "Vancouver","W")
3> GO
(1 rows affected)
1> insert into employee (ID, name,    salary, start_date, city,       region)
2>               values (6,  "James", 70060,  "09/06/99", "Toronto",  "N")
3> GO
(1 rows affected)
1> insert into employee (ID, name,    salary, start_date, city,       region)
2>               values (7,  "Alison",90620,  "08/07/00", "New York", "W")
3> GO
(1 rows affected)
1> insert into employee (ID, name,    salary, start_date, city,       region)
2>               values (8,  "Chris", 26020,  "07/08/01", "Vancouver","N")
3> GO
(1 rows affected)
1> insert into employee (ID, name,    salary, start_date, city,       region)
2>               values (9,  "Mary",  60020,  "06/09/02", "Toronto",  "W")
3> GO
(1 rows affected)
1>
2> select * from employee
3> GO
ID          name       salary      start_date              city       region
----------- ---------- ----------- ----------------------- ---------- ------
          1 Jason            40420 1994-02-01 00:00:00.000 New York   W
          2 Robert           14420 1995-01-02 00:00:00.000 Vancouver  N
          3 Celia            24020 1996-12-03 00:00:00.000 Toronto    W
          4 Linda            40620 1997-11-04 00:00:00.000 New York   N
          5 David            80026 1998-10-05 00:00:00.000 Vancouver  W
          6 James            70060 1999-09-06 00:00:00.000 Toronto    N
          7 Alison           90620 2000-08-07 00:00:00.000 New York   W
          8 Chris            26020 2001-07-08 00:00:00.000 Vancouver  N
          9 Mary             60020 2002-06-09 00:00:00.000 Toronto    W
(9 rows affected)
1>
2> DECLARE @Markup     money
3> DECLARE @Multiplier money
4>
5> SELECT @Markup = .10             -- Change the markup here
6> SELECT @Multiplier = @Markup + 1 -- We want the end price, not the amount
7>                                  -- of the increase, so add 1
8> SELECT ID, Name, salary,
9>    Salary * @Multiplier AS "Marked Up salary", "New salary" =
10>    CASE WHEN FLOOR(salary * @Multiplier + .24) > FLOOR(salary * @Multiplier)
11>                      THEN FLOOR(salary * @Multiplier) + .95
12>         WHEN FLOOR(salary * @Multiplier + .5) >  FLOOR(salary * @Multiplier)
13>                      THEN FLOOR(salary * @Multiplier) + .75
14>         ELSE FLOOR(salary * @Multiplier) + .49
15>   END
16> FROM Employee
17> GO
ID          Name       salary      Marked Up salary      New salary
----------- ---------- ----------- --------------------- ----------------------
          1 Jason            40420            44462.0000             44462.4900
          2 Robert           14420            15862.0000             15862.4900
          3 Celia            24020            26422.0000             26422.4900
          4 Linda            40620            44682.0000             44682.4900
          5 David            80026            88028.6000             88028.7500
          6 James            70060            77066.0000             77066.4900
          7 Alison           90620            99682.0000             99682.4900
          8 Chris            26020            28622.0000             28622.4900
          9 Mary             60020            66022.0000             66022.4900
(9 rows affected)
1>
2> drop table employee
3> GO
1>



FLOOR: return the largest integer less than the given value

1> -- FLOOR: return the largest integer less than the given value.
2>
3> SELECT FLOOR(-145.677)
4> GO
--------
    -146
(1 rows affected)