Oracle PL/SQL/Numeric Math Functions/EXP

EXP(2)

SQL> select EXP(2) from dual;
    EXP(2)
----------
 7.3890561
SQL>
SQL>

EXP: Returns e raised to a value

SQL>
SQL> -- create demo table
SQL> create table TestTable(
  2    ID                 VARCHAR2(4 BYTE)         NOT NULL,
  3    MyName             VARCHAR2(10 BYTE),
  4    MyDate             DATE,
  5    MyNumber           Number(8,2)
  6  )
  7  /
Table created.
SQL>
SQL>
SQL> insert into TestTable (ID, MyName, MyDate, MyNumber) values("1","Alison",to_date("19960711","YYYYMMDD"),12.12);
1 row created.
SQL> insert into TestTable (ID, MyName, MyDate, MyNumber) values("1","Alison",to_date("19970622","YYYYMMDD"),-12.12);
1 row created.
SQL> insert into TestTable (ID, MyName, MyDate, MyNumber) values("1","Alison",to_date("19980513","YYYYMMDD"),22.1);
1 row created.
SQL> insert into TestTable (ID, MyName, MyDate, MyNumber) values("1","Alison",to_date("19990624","YYYYMMDD"),-2.12);
1 row created.
SQL> insert into TestTable (ID, MyName, MyDate, MyNumber) values("1","Alison",to_date("20000415","YYYYMMDD"),2.1);
1 row created.
SQL>
SQL>
SQL> select * from TestTable
  2
SQL>
SQL> --EXP: Returns e raised to a value.
SQL> SELECT EXP(MyNumber) FROM TestTable;
EXP(MYNUMBER)
-------------
   183505.515
   5.4494E-06
   3961941421
   .120031629
   8.16616991
SQL>
SQL> drop table TestTable;

EXP() returns e raised to the nth power (n is the <numeric_expression> value), where e is equal to approximately 2.71828183.

 
SQL>
Syntax:EXP(<numeric expression>)
SQL>
SQL>
SQL> SELECT
  2     EXP(10) exponent from dual;
  EXPONENT
----------
22026.4658
SQL>
SQL>

EXP(x):Returns the result of the number e raised to the power x

SQL> --EXP(x):Returns the result of the number e raised to the power x, 
--where e is approximately 2.71828183.
SQL>
SQL> select EXP(1) from dual;
    EXP(1)
----------
2.71828183
SQL>