SQL Server/T-SQL Tutorial/Set Operations/INTERSECT — различия между версиями
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Admin (обсуждение | вклад) м (1 версия) |
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Текущая версия на 10:24, 26 мая 2010
Returning Distinct or Matching Rows using INTERSECT
3>
4> CREATE TABLE employee(
5> id INTEGER NOT NULL PRIMARY KEY,
6> first_name VARCHAR(10),
7> last_name VARCHAR(10),
8> salary DECIMAL(10,2),
9> start_Date DATETIME,
10> region VARCHAR(10),
11> city VARCHAR(20),
12> managerid INTEGER
13> );
14> GO
1> INSERT INTO employee VALUES (1, "Jason" , "Martin", 5890,"2005-03-22","North","Vancouver",3);
2> GO
(1 rows affected)
1> INSERT INTO employee VALUES (2, "Alison", "Mathews",4789,"2003-07-21","South","Utown",4);
2> GO
(1 rows affected)
1> INSERT INTO employee VALUES (3, "James" , "Smith", 6678,"2001-12-01","North","Paris",5);
2> GO
(1 rows affected)
1> INSERT INTO employee VALUES (4, "Celia" , "Rice", 5567,"2006-03-03","South","London",6);
2> GO
(1 rows affected)
1> INSERT INTO employee VALUES (5, "Robert", "Black", 4467,"2004-07-02","East","Newton",7);
2> GO
(1 rows affected)
1> INSERT INTO employee VALUES (6, "Linda" , "Green" , 6456,"2002-05-19","East","Calgary",8);
2> GO
(1 rows affected)
1> INSERT INTO employee VALUES (7, "David" , "Larry", 5345,"2008-03-18","West","New York",9);
2> GO
(1 rows affected)
1> INSERT INTO employee VALUES (8, "James" , "Cat", 4234,"2007-07-17","West","Regina",9);
2> GO
(1 rows affected)
1> INSERT INTO employee VALUES (9, "Joan" , "Act", 6123,"2001-04-16","North","Toronto",10);
2> GO
(1 rows affected)
1>
2> select * from employee;
3> GO
id first_name last_name salary start_Date region city managerid
----------- ---------- ---------- ------------ ----------------------- ---------- -------------------- -----------
1 Jason Martin 5890.00 2005-03-22 00:00:00.000 North Vancouver 3
2 Alison Mathews 4789.00 2003-07-21 00:00:00.000 South Utown 4
3 James Smith 6678.00 2001-12-01 00:00:00.000 North Paris 5
4 Celia Rice 5567.00 2006-03-03 00:00:00.000 South London 6
5 Robert Black 4467.00 2004-07-02 00:00:00.000 East Newton 7
6 Linda Green 6456.00 2002-05-19 00:00:00.000 East Calgary 8
7 David Larry 5345.00 2008-03-18 00:00:00.000 West New York 9
8 James Cat 4234.00 2007-07-17 00:00:00.000 West Regina 9
9 Joan Act 6123.00 2001-04-16 00:00:00.000 North Toronto 10
(9 rows affected)
1>
2>
3> SELECT ID,first_Name
4> FROM employee
5> where id > 3
6> INTERSECT
7> SELECT ID,first_Name
8> FROM employee
9> where id > 4;
10> GO
ID first_Name
----------- ----------
5 Robert
6 Linda
7 David
8 James
9 Joan
(5 rows affected)
1>
2>
3>
4> drop table employee;
5> GO
The intersection of two tables is the set of rows belonging to both tables.
The difference of two tables is the set of all rows, where the resulting rows belong to the first table but not to the second one.
5> CREATE TABLE employee(
6> id INTEGER NOT NULL PRIMARY KEY,
7> first_name VARCHAR(10),
8> last_name VARCHAR(10),
9> salary DECIMAL(10,2),
10> start_Date DATETIME,
11> region VARCHAR(10),
12> city VARCHAR(20)
13> );
14> GO
1> INSERT INTO employee VALUES (1, "Jason" , "Martin", 5890,"2005-03-22","North","Vancouver");
2> INSERT INTO employee VALUES (2, "Alison", "Mathews",4789,"2003-07-21","South","Utown");
3> INSERT INTO employee VALUES (3, "James" , "Smith", 6678,"2001-12-01","North","Paris");
4> INSERT INTO employee VALUES (4, "Celia" , "Rice", 5567,"2006-03-03","South","London");
5> INSERT INTO employee VALUES (5, "Robert", "Black", 4467,"2004-07-02","East","Newton");
6> INSERT INTO employee VALUES (6, "Linda" , "Green" , 6456,"2002-05-19","East","Calgary");
7> INSERT INTO employee VALUES (7, "David" , "Larry", 5345,"2008-03-18","West","New York");
8> INSERT INTO employee VALUES (8, "James" , "Cat", 4234,"2007-07-17","West","Regina");
9> INSERT INTO employee VALUES (9, "Joan" , "Act", 6123,"2001-04-16","North","Toronto");
10> GO
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
1> select * from employee;
2> GO
id first_name last_name salary start_Date region city
----------- ---------- ---------- ------------ ----------------------- ---------- --------------------
1 Jason Martin 5890.00 2005-03-22 00:00:00.000 North Vancouver
2 Alison Mathews 4789.00 2003-07-21 00:00:00.000 South Utown
3 James Smith 6678.00 2001-12-01 00:00:00.000 North Paris
4 Celia Rice 5567.00 2006-03-03 00:00:00.000 South London
5 Robert Black 4467.00 2004-07-02 00:00:00.000 East Newton
6 Linda Green 6456.00 2002-05-19 00:00:00.000 East Calgary
7 David Larry 5345.00 2008-03-18 00:00:00.000 West New York
8 James Cat 4234.00 2007-07-17 00:00:00.000 West Regina
9 Joan Act 6123.00 2001-04-16 00:00:00.000 North Toronto
(9 rows affected)
1>
2> CREATE TABLE title(
3> id INTEGER,
4> job_title VARCHAR(20)
5> );
6> GO
1> INSERT INTO title VALUES (1, "developer");
2> INSERT INTO title VALUES (1, "manager");
3> INSERT INTO title VALUES (2, "tester");
4> INSERT INTO title VALUES (2, "programmer");
5> INSERT INTO title VALUES (3, "boss");
6> INSERT INTO title VALUES (4, "sales");
7> INSERT INTO title VALUES (5, "market");
8> INSERT INTO title VALUES (6, "coder");
9> INSERT INTO title VALUES (7, "tester");
10> INSERT INTO title VALUES (8, "developer");
11> INSERT INTO title VALUES (9, "manager");
12> GO
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
1>
2> SELECT id FROM employee
3> INTERSECT
4> SELECT id FROM title
5> GO
id
-----------
1
2
3
4
5
6
7
8
9
(9 rows affected)
1>
2>
3>
4> drop table employee;
5> drop table title;
6> GO