SQL Server/T-SQL/Subquery/Subqueries IN — различия между версиями
Admin (обсуждение | вклад) м (1 версия) |
Admin (обсуждение | вклад) м (1 версия) |
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Текущая версия на 10:21, 26 мая 2010
Содержание
Nested three level subquery with IN operator
34>
35> CREATE TABLE employee (emp_no INTEGER NOT NULL,
36> emp_fname CHAR(20) NOT NULL,
37> emp_lname CHAR(20) NOT NULL,
38> dept_no CHAR(4) NULL)
39>
40> insert into employee values(1, "Matthew", "Smith", "d3")
41> insert into employee values(2, "Ann", "Jones", "d3")
42> insert into employee values(3, "John", "Barrimore","d1")
43> insert into employee values(4, "James", "James", "d2")
44> insert into employee values(5, "Elsa", "Bertoni", "d2")
45> insert into employee values(6, "Elke", "Hansel", "d2")
46> insert into employee values(7, "Sybill", "Moser", "d1")
47>
48> select * from employee
49> GO
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
emp_no emp_fname emp_lname dept_no
----------- -------------------- -------------------- -------
1 Matthew Smith d3
2 Ann Jones d3
3 John Barrimore d1
4 James James d2
5 Elsa Bertoni d2
6 Elke Hansel d2
7 Sybill Moser d1
(7 rows affected)
1>
2>
3> CREATE TABLE works_on (emp_no INTEGER NOT NULL,
4> project_no CHAR(4) NOT NULL,
5> job CHAR (15) NULL,
6> enter_date DATETIME NULL)
7> GO
1>
2> insert into works_on values (1, "p1", "analyst", "1997.10.1")
3> insert into works_on values (1, "p3", "manager", "1999.1.1")
4> insert into works_on values (2, "p2", "clerk", "1998.2.15")
5> insert into works_on values (2, "p2", NULL, "1998.6.1")
6> insert into works_on values (3, "p2", NULL, "1997.12.15")
7> insert into works_on values (4, "p3", "analyst", "1998.10.15")
8> insert into works_on values (5, "p1", "manager", "1998.4.15")
9> insert into works_on values (6, "p1", NULL, "1998.8.1")
10> insert into works_on values (7, "p2", "clerk", "1999.2.1")
11> insert into works_on values (8, "p3", "clerk", "1997.11.15")
12> insert into works_on values (7, "p1", "clerk", "1998.1.4")
13> GO
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
1>
2>
3> CREATE TABLE project (project_no CHAR(4) NOT NULL,
4> project_name CHAR(15) NOT NULL,
5> budget FLOAT NULL)
6> GO
1>
2> insert into project values ("p1", "Search Engine", 120000.00)
3> insert into project values ("p2", "Programming", 95000.00)
4> insert into project values ("p3", "SQL", 186500.00)
5> GO
(1 rows affected)
(1 rows affected)
(1 rows affected)
1>
2> -- Nested three level subquery with in operator
3>
4> SELECT emp_lname FROM employee WHERE emp_no IN
5> (SELECT emp_no FROM works_on WHERE project_no IN
6> (SELECT project_no FROM project WHERE project_name = "SQL"))
7> GO
emp_lname
--------------------
Smith
James
(2 rows affected)
1>
2> drop table employee
3> drop table works_on
4> drop table project
5> GO
1>
2>
Reversing the logic using the NOT IN operator
1>
2> create table job(
3> ID int,
4> title nvarchar (10),
5> averageSalary int)
6> GO
1>
2>
3> insert into employee (ID, name, salary) values (1, "Jason", 1234)
4> GO
(1 rows affected)
1> insert into employee (ID, name, salary) values (2, "Robert", 4321)
2> GO
(1 rows affected)
1> insert into employee (ID, name, salary) values (3, "Celia", 5432)
2> GO
(1 rows affected)
1> insert into employee (ID, name, salary) values (4, "Linda", 3456)
2> GO
(1 rows affected)
1> insert into employee (ID, name, salary) values (5, "David", 7654)
2> GO
(1 rows affected)
1> insert into employee (ID, name, salary) values (6, "James", 4567)
2> GO
(1 rows affected)
1> insert into employee (ID, name, salary) values (7, "Alison", 8744)
2> GO
(1 rows affected)
1> insert into employee (ID, name, salary) values (8, "Chris", 9875)
2> GO
(1 rows affected)
1> insert into employee (ID, name, salary) values (9, "Mary", 2345)
2> GO
(1 rows affected)
1>
2> insert into job(ID, title, averageSalary) values(1,"Developer",3000)
3> GO
(1 rows affected)
1> insert into job(ID, title, averageSalary) values(2,"Tester", 4000)
2> GO
(1 rows affected)
1> insert into job(ID, title, averageSalary) values(3,"Designer", 5000)
2> GO
(1 rows affected)
1> insert into job(ID, title, averageSalary) values(4,"Programmer", 6000)
2> GO
(1 rows affected)
1>
2>
3> select * from employee;
4> GO
ID name salary
----------- ---------- -----------
1 Jason 1234
2 Robert 4321
3 Celia 5432
4 Linda 3456
5 David 7654
6 James 4567
7 Alison 8744
8 Chris 9875
9 Mary 2345
(9 rows affected)
1> select * from job;
2> GO
ID title averageSalary
----------- ---------- -------------
1 Developer 3000
2 Tester 4000
3 Designer 5000
4 Programmer 6000
(4 rows affected)
1>
2> -- Reversing the logic using the NOT operator
3>
4> SELECT ID, Name
5> FROM Employee
6> WHERE ID NOT IN
7> (SELECT ID FROM Job)
8> GO
ID Name
----------- ----------
5 David
6 James
7 Alison
8 Chris
9 Mary
(5 rows affected)
1>
2> drop table employee;
3> drop table job;
4> GO
1>
2>
Subqueries and IN Operator
1>
2> CREATE TABLE employee (emp_no INTEGER NOT NULL,
3> emp_fname CHAR(20) NOT NULL,
4> emp_lname CHAR(20) NOT NULL,
5> dept_no CHAR(4) NULL)
6>
7> insert into employee values(1, "Matthew", "Smith", "d3")
8> insert into employee values(2, "Ann", "Jones", "d3")
9> insert into employee values(3, "John", "Barrimore","d1")
10> insert into employee values(4, "James", "James", "d2")
11> insert into employee values(5, "Elsa", "Bertoni", "d2")
12> insert into employee values(6, "Elke", "Hansel", "d2")
13> insert into employee values(7, "Sybill", "Moser", "d1")
14>
15> select * from employee
16> GO
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
emp_no emp_fname emp_lname dept_no
----------- -------------------- -------------------- -------
1 Matthew Smith d3
2 Ann Jones d3
3 John Barrimore d1
4 James James d2
5 Elsa Bertoni d2
6 Elke Hansel d2
7 Sybill Moser d1
(7 rows affected)
1>
2> CREATE TABLE department(dept_no CHAR(4) NOT NULL,
3> dept_name CHAR(25) NOT NULL,
4> location CHAR(30) NULL)
5>
6> insert into department values ("d1", "developer", "Dallas")
7> insert into department values ("d2", "tester", "Seattle")
8> insert into department values ("d3", "marketing", "Dallas")
9>
10> select * from department
11> GO
(1 rows affected)
(1 rows affected)
(1 rows affected)
dept_no dept_name location
------- ------------------------- ------------------------------
d1 developer Dallas
d2 tester Seattle
d3 marketing Dallas
(3 rows affected)
1>
2> -- Subqueries and IN Operator
3>
4> SELECT * FROM employee WHERE dept_no IN
5> (SELECT dept_no FROM department WHERE location = "Dallas")
6> GO
emp_no emp_fname emp_lname dept_no
----------- -------------------- -------------------- -------
1 Matthew Smith d3
2 Ann Jones d3
3 John Barrimore d1
7 Sybill Moser d1
(4 rows affected)
1>
2> drop table employee
3> drop table department
4> GO
1>
2>
Use IN operator for a single value
1> CREATE TABLE works_on (emp_no INTEGER NOT NULL,
2> project_no CHAR(4) NOT NULL,
3> job CHAR (15) NULL,
4> enter_date DATETIME NULL)
5>
6> insert into works_on values (1, "p1", "analyst", "1997.10.1")
7> insert into works_on values (1, "p3", "manager", "1999.1.1")
8> insert into works_on values (2, "p2", "clerk", "1998.2.15")
9> insert into works_on values (2, "p2", NULL, "1998.6.1")
10> insert into works_on values (3, "p2", NULL, "1997.12.15")
11> insert into works_on values (4, "p3", "analyst", "1998.10.15")
12> insert into works_on values (5, "p1", "manager", "1998.4.15")
13> insert into works_on values (6, "p1", NULL, "1998.8.1")
14> insert into works_on values (7, "p2", "clerk", "1999.2.1")
15> insert into works_on values (8, "p3", "clerk", "1997.11.15")
16> insert into works_on values (7, "p1", "clerk", "1998.1.4")
17>
18> select * from works_on
19> GO
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
emp_no project_no job enter_date
----------- ---------- --------------- -----------------------
1 p1 analyst 1997-10-01 00:00:00.000
1 p3 manager 1999-01-01 00:00:00.000
2 p2 clerk 1998-02-15 00:00:00.000
2 p2 NULL 1998-06-01 00:00:00.000
3 p2 NULL 1997-12-15 00:00:00.000
4 p3 analyst 1998-10-15 00:00:00.000
5 p1 manager 1998-04-15 00:00:00.000
6 p1 NULL 1998-08-01 00:00:00.000
7 p2 clerk 1999-02-01 00:00:00.000
8 p3 clerk 1997-11-15 00:00:00.000
7 p1 clerk 1998-01-04 00:00:00.000
(11 rows affected)
1>
2> CREATE TABLE employee (emp_no INTEGER NOT NULL,
3> emp_fname CHAR(20) NOT NULL,
4> emp_lname CHAR(20) NOT NULL,
5> dept_no CHAR(4) NULL)
6>
7> insert into employee values(1, "Matthew", "Smith", "d3")
8> insert into employee values(2, "Ann", "Jones", "d3")
9> insert into employee values(3, "John", "Barrimore","d1")
10> insert into employee values(4, "James", "James", "d2")
11> insert into employee values(5, "Elsa", "Bertoni", "d2")
12> insert into employee values(6, "Elke", "Hansel", "d2")
13> insert into employee values(7, "Sybill", "Moser", "d1")
14>
15> select * from employee
16> GO
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
emp_no emp_fname emp_lname dept_no
----------- -------------------- -------------------- -------
1 Matthew Smith d3
2 Ann Jones d3
3 John Barrimore d1
4 James James d2
5 Elsa Bertoni d2
6 Elke Hansel d2
7 Sybill Moser d1
(7 rows affected)
1>
2> SELECT emp_lname
3> FROM employee
4> WHERE "p3" IN
5> (SELECT project_no
6> FROM works_on
7> WHERE works_on.emp_no=employee.emp_no)
8> GO
emp_lname
--------------------
Smith
James
(2 rows affected)
1>
2> drop table employee
3> drop table works_on
4> GO
1>
2>
Using the IN() Function for subquery
1>
2> create table employee(
3> ID int,
4> name nvarchar (10),
5> salary int )
6> GO
1>
2> create table job(
3> ID int,
4> title nvarchar (10),
5> averageSalary int)
6> GO
1>
2>
3> insert into employee (ID, name, salary) values (1, "Jason", 1234)
4> GO
(1 rows affected)
1> insert into employee (ID, name, salary) values (2, "Robert", 4321)
2> GO
(1 rows affected)
1> insert into employee (ID, name, salary) values (3, "Celia", 5432)
2> GO
(1 rows affected)
1> insert into employee (ID, name, salary) values (4, "Linda", 3456)
2> GO
(1 rows affected)
1> insert into employee (ID, name, salary) values (5, "David", 7654)
2> GO
(1 rows affected)
1> insert into employee (ID, name, salary) values (6, "James", 4567)
2> GO
(1 rows affected)
1> insert into employee (ID, name, salary) values (7, "Alison", 8744)
2> GO
(1 rows affected)
1> insert into employee (ID, name, salary) values (8, "Chris", 9875)
2> GO
(1 rows affected)
1> insert into employee (ID, name, salary) values (9, "Mary", 2345)
2> GO
(1 rows affected)
1>
2> insert into job(ID, title, averageSalary) values(1,"Developer",3000)
3> GO
(1 rows affected)
1> insert into job(ID, title, averageSalary) values(2,"Tester", 4000)
2> GO
(1 rows affected)
1> insert into job(ID, title, averageSalary) values(3,"Designer", 5000)
2> GO
(1 rows affected)
1> insert into job(ID, title, averageSalary) values(4,"Programmer", 6000)
2> GO
(1 rows affected)
1>
2>
3> select * from employee;
4> GO
ID name salary
----------- ---------- -----------
1 Jason 1234
2 Robert 4321
3 Celia 5432
4 Linda 3456
5 David 7654
6 James 4567
7 Alison 8744
8 Chris 9875
9 Mary 2345
(9 rows affected)
1> select * from job;
2> GO
ID title averageSalary
----------- ---------- -------------
1 Developer 3000
2 Tester 4000
3 Designer 5000
4 Programmer 6000
(4 rows affected)
1>
2>
3> -- Using the IN() Function
4>
6>
7> SELECT ID, Name
8> FROM Employee
9> WHERE ID IN
10> ( SELECT ID FROM Job )
11> GO
ID Name
----------- ----------
1 Jason
2 Robert
3 Celia
4 Linda
(4 rows affected)
1>
2>
3>
4> drop table employee;
5> drop table job;
6> GO
1>
2>