SQL Server/T-SQL/Subquery/Subqueries IN — различия между версиями

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м (1 версия)
 
м (1 версия)
 
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Текущая версия на 10:21, 26 мая 2010

Nested three level subquery with IN operator

34>
35> CREATE TABLE employee  (emp_no    INTEGER NOT NULL,
36>                         emp_fname CHAR(20) NOT NULL,
37>                         emp_lname CHAR(20) NOT NULL,
38>                         dept_no   CHAR(4) NULL)
39>
40> insert into employee values(1,  "Matthew", "Smith",    "d3")
41> insert into employee values(2,  "Ann",     "Jones",    "d3")
42> insert into employee values(3,  "John",    "Barrimore","d1")
43> insert into employee values(4,  "James",   "James",    "d2")
44> insert into employee values(5,  "Elsa",    "Bertoni",  "d2")
45> insert into employee values(6,  "Elke",    "Hansel",   "d2")
46> insert into employee values(7,  "Sybill",  "Moser",    "d1")
47>
48> select * from employee
49> GO
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
emp_no      emp_fname            emp_lname            dept_no
----------- -------------------- -------------------- -------
          1 Matthew              Smith                d3
          2 Ann                  Jones                d3
          3 John                 Barrimore            d1
          4 James                James                d2
          5 Elsa                 Bertoni              d2
          6 Elke                 Hansel               d2
          7 Sybill               Moser                d1
(7 rows affected)
1>
2>
3> CREATE TABLE works_on        (emp_no       INTEGER NOT NULL,
4>                         project_no    CHAR(4) NOT NULL,
5>                         job CHAR (15) NULL,
6>                         enter_date    DATETIME NULL)
7> GO
1>
2> insert into works_on values (1, "p1", "analyst", "1997.10.1")
3> insert into works_on values (1, "p3", "manager", "1999.1.1")
4> insert into works_on values (2, "p2", "clerk",   "1998.2.15")
5> insert into works_on values (2, "p2",  NULL,     "1998.6.1")
6> insert into works_on values (3, "p2",  NULL,     "1997.12.15")
7> insert into works_on values (4, "p3", "analyst", "1998.10.15")
8> insert into works_on values (5, "p1", "manager", "1998.4.15")
9> insert into works_on values (6, "p1",  NULL,     "1998.8.1")
10> insert into works_on values (7, "p2", "clerk",   "1999.2.1")
11> insert into works_on values (8, "p3", "clerk",   "1997.11.15")
12> insert into works_on values (7, "p1", "clerk",   "1998.1.4")
13> GO
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
1>
2>
3> CREATE TABLE project   (project_no   CHAR(4) NOT NULL,
4>                         project_name CHAR(15) NOT NULL,
5>                         budget FLOAT NULL)
6> GO
1>
2> insert into project values ("p1", "Search Engine",        120000.00)
3> insert into project values ("p2", "Programming",          95000.00)
4> insert into project values ("p3", "SQL",                  186500.00)
5> GO
(1 rows affected)
(1 rows affected)
(1 rows affected)
1>
2> -- Nested three level subquery with in operator
3>
4> SELECT emp_lname FROM employee WHERE emp_no IN
5>        (SELECT emp_no FROM works_on WHERE project_no IN
6>          (SELECT project_no FROM project WHERE project_name = "SQL"))
7> GO
emp_lname
--------------------
Smith
James
(2 rows affected)
1>
2> drop table employee
3> drop table works_on
4> drop table project
5> GO
1>
2>



Reversing the logic using the NOT IN operator

1>
2> create table job(
3>     ID              int,
4>     title nvarchar  (10),
5>     averageSalary   int)
6> GO
1>
2>
3> insert into employee (ID, name, salary) values (1,  "Jason", 1234)
4> GO
(1 rows affected)
1> insert into employee (ID, name, salary) values (2,  "Robert", 4321)
2> GO
(1 rows affected)
1> insert into employee (ID, name, salary) values (3,  "Celia", 5432)
2> GO
(1 rows affected)
1> insert into employee (ID, name, salary) values (4,  "Linda", 3456)
2> GO
(1 rows affected)
1> insert into employee (ID, name, salary) values (5,  "David", 7654)
2> GO
(1 rows affected)
1> insert into employee (ID, name, salary) values (6,  "James", 4567)
2> GO
(1 rows affected)
1> insert into employee (ID, name, salary) values (7,  "Alison", 8744)
2> GO
(1 rows affected)
1> insert into employee (ID, name, salary) values (8,  "Chris", 9875)
2> GO
(1 rows affected)
1> insert into employee (ID, name, salary) values (9,  "Mary", 2345)
2> GO
(1 rows affected)
1>
2> insert into job(ID, title, averageSalary) values(1,"Developer",3000)
3> GO
(1 rows affected)
1> insert into job(ID, title, averageSalary) values(2,"Tester", 4000)
2> GO
(1 rows affected)
1> insert into job(ID, title, averageSalary) values(3,"Designer", 5000)
2> GO
(1 rows affected)
1> insert into job(ID, title, averageSalary) values(4,"Programmer", 6000)
2> GO
(1 rows affected)
1>
2>
3> select * from employee;
4> GO
ID          name       salary
----------- ---------- -----------
          1 Jason             1234
          2 Robert            4321
          3 Celia             5432
          4 Linda             3456
          5 David             7654
          6 James             4567
          7 Alison            8744
          8 Chris             9875
          9 Mary              2345
(9 rows affected)
1> select * from job;
2> GO
ID          title      averageSalary
----------- ---------- -------------
          1 Developer           3000
          2 Tester              4000
          3 Designer            5000
          4 Programmer          6000
(4 rows affected)
1>
2> -- Reversing the logic using the NOT operator
3>
4> SELECT ID, Name
5> FROM Employee
6> WHERE ID NOT IN
7>          (SELECT ID FROM Job)
8> GO
ID          Name
----------- ----------
          5 David
          6 James
          7 Alison
          8 Chris
          9 Mary
(5 rows affected)
1>
2> drop table employee;
3> drop table job;
4> GO
1>
2>



Subqueries and IN Operator

1>
2> CREATE TABLE employee  (emp_no    INTEGER NOT NULL,
3>                         emp_fname CHAR(20) NOT NULL,
4>                         emp_lname CHAR(20) NOT NULL,
5>                         dept_no   CHAR(4) NULL)
6>
7> insert into employee values(1,  "Matthew", "Smith",    "d3")
8> insert into employee values(2,  "Ann",     "Jones",    "d3")
9> insert into employee values(3,  "John",    "Barrimore","d1")
10> insert into employee values(4,  "James",   "James",    "d2")
11> insert into employee values(5,  "Elsa",    "Bertoni",  "d2")
12> insert into employee values(6,  "Elke",    "Hansel",   "d2")
13> insert into employee values(7,  "Sybill",  "Moser",    "d1")
14>
15> select * from employee
16> GO
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
emp_no      emp_fname            emp_lname            dept_no
----------- -------------------- -------------------- -------
          1 Matthew              Smith                d3
          2 Ann                  Jones                d3
          3 John                 Barrimore            d1
          4 James                James                d2
          5 Elsa                 Bertoni              d2
          6 Elke                 Hansel               d2
          7 Sybill               Moser                d1
(7 rows affected)
1>
2> CREATE TABLE department(dept_no   CHAR(4) NOT NULL,
3>                         dept_name CHAR(25) NOT NULL,
4>                         location  CHAR(30) NULL)
5>
6> insert into department values ("d1", "developer",   "Dallas")
7> insert into department values ("d2", "tester",      "Seattle")
8> insert into department values ("d3", "marketing",  "Dallas")
9>
10> select * from department
11> GO
(1 rows affected)
(1 rows affected)
(1 rows affected)
dept_no dept_name                 location
------- ------------------------- ------------------------------
d1      developer                 Dallas
d2      tester                    Seattle
d3      marketing                 Dallas
(3 rows affected)
1>
2> -- Subqueries and IN Operator
3>
4> SELECT * FROM employee WHERE dept_no IN
5>        (SELECT dept_no FROM department WHERE location = "Dallas")
6> GO
emp_no      emp_fname            emp_lname            dept_no
----------- -------------------- -------------------- -------
          1 Matthew              Smith                d3
          2 Ann                  Jones                d3
          3 John                 Barrimore            d1
          7 Sybill               Moser                d1
(4 rows affected)
1>
2> drop table employee
3> drop table department
4> GO
1>
2>



Use IN operator for a single value

1> CREATE TABLE works_on        (emp_no       INTEGER NOT NULL,
2>                         project_no    CHAR(4) NOT NULL,
3>                         job CHAR (15) NULL,
4>                         enter_date    DATETIME NULL)
5>
6> insert into works_on values (1, "p1", "analyst", "1997.10.1")
7> insert into works_on values (1, "p3", "manager", "1999.1.1")
8> insert into works_on values (2, "p2", "clerk",   "1998.2.15")
9> insert into works_on values (2, "p2",  NULL,     "1998.6.1")
10> insert into works_on values (3, "p2",  NULL,     "1997.12.15")
11> insert into works_on values (4, "p3", "analyst", "1998.10.15")
12> insert into works_on values (5, "p1", "manager", "1998.4.15")
13> insert into works_on values (6, "p1",  NULL,     "1998.8.1")
14> insert into works_on values (7, "p2", "clerk",   "1999.2.1")
15> insert into works_on values (8, "p3", "clerk",   "1997.11.15")
16> insert into works_on values (7, "p1", "clerk",   "1998.1.4")
17>
18> select * from works_on
19> GO
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
emp_no      project_no job             enter_date
----------- ---------- --------------- -----------------------
          1 p1         analyst         1997-10-01 00:00:00.000
          1 p3         manager         1999-01-01 00:00:00.000
          2 p2         clerk           1998-02-15 00:00:00.000
          2 p2         NULL            1998-06-01 00:00:00.000
          3 p2         NULL            1997-12-15 00:00:00.000
          4 p3         analyst         1998-10-15 00:00:00.000
          5 p1         manager         1998-04-15 00:00:00.000
          6 p1         NULL            1998-08-01 00:00:00.000
          7 p2         clerk           1999-02-01 00:00:00.000
          8 p3         clerk           1997-11-15 00:00:00.000
          7 p1         clerk           1998-01-04 00:00:00.000
(11 rows affected)
1>
2> CREATE TABLE employee  (emp_no    INTEGER NOT NULL,
3>                         emp_fname CHAR(20) NOT NULL,
4>                         emp_lname CHAR(20) NOT NULL,
5>                         dept_no   CHAR(4) NULL)
6>
7> insert into employee values(1,  "Matthew", "Smith",    "d3")
8> insert into employee values(2,  "Ann",     "Jones",    "d3")
9> insert into employee values(3,  "John",    "Barrimore","d1")
10> insert into employee values(4,  "James",   "James",    "d2")
11> insert into employee values(5,  "Elsa",    "Bertoni",  "d2")
12> insert into employee values(6,  "Elke",    "Hansel",   "d2")
13> insert into employee values(7,  "Sybill",  "Moser",    "d1")
14>
15> select * from employee
16> GO
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
emp_no      emp_fname            emp_lname            dept_no
----------- -------------------- -------------------- -------
          1 Matthew              Smith                d3
          2 Ann                  Jones                d3
          3 John                 Barrimore            d1
          4 James                James                d2
          5 Elsa                 Bertoni              d2
          6 Elke                 Hansel               d2
          7 Sybill               Moser                d1
(7 rows affected)
1>
2> SELECT emp_lname
3>        FROM employee
4>        WHERE "p3" IN
5>        (SELECT project_no
6>          FROM works_on
7>          WHERE works_on.emp_no=employee.emp_no)
8> GO
emp_lname
--------------------
Smith
James
(2 rows affected)
1>
2> drop table employee
3> drop table works_on
4> GO
1>
2>



Using the IN() Function for subquery

1>
2> create table employee(
3>     ID          int,
4>     name        nvarchar (10),
5>     salary      int )
6> GO
1>
2> create table job(
3>     ID              int,
4>     title nvarchar  (10),
5>     averageSalary   int)
6> GO
1>
2>
3> insert into employee (ID, name, salary) values (1,  "Jason", 1234)
4> GO
(1 rows affected)
1> insert into employee (ID, name, salary) values (2,  "Robert", 4321)
2> GO
(1 rows affected)
1> insert into employee (ID, name, salary) values (3,  "Celia", 5432)
2> GO
(1 rows affected)
1> insert into employee (ID, name, salary) values (4,  "Linda", 3456)
2> GO
(1 rows affected)
1> insert into employee (ID, name, salary) values (5,  "David", 7654)
2> GO
(1 rows affected)
1> insert into employee (ID, name, salary) values (6,  "James", 4567)
2> GO
(1 rows affected)
1> insert into employee (ID, name, salary) values (7,  "Alison", 8744)
2> GO
(1 rows affected)
1> insert into employee (ID, name, salary) values (8,  "Chris", 9875)
2> GO
(1 rows affected)
1> insert into employee (ID, name, salary) values (9,  "Mary", 2345)
2> GO
(1 rows affected)
1>
2> insert into job(ID, title, averageSalary) values(1,"Developer",3000)
3> GO
(1 rows affected)
1> insert into job(ID, title, averageSalary) values(2,"Tester", 4000)
2> GO
(1 rows affected)
1> insert into job(ID, title, averageSalary) values(3,"Designer", 5000)
2> GO
(1 rows affected)
1> insert into job(ID, title, averageSalary) values(4,"Programmer", 6000)
2> GO
(1 rows affected)
1>
2>
3> select * from employee;
4> GO
ID          name       salary
----------- ---------- -----------
          1 Jason             1234
          2 Robert            4321
          3 Celia             5432
          4 Linda             3456
          5 David             7654
          6 James             4567
          7 Alison            8744
          8 Chris             9875
          9 Mary              2345
(9 rows affected)
1> select * from job;
2> GO
ID          title      averageSalary
----------- ---------- -------------
          1 Developer           3000
          2 Tester              4000
          3 Designer            5000
          4 Programmer          6000
(4 rows affected)
1>
2>
3> -- Using the IN() Function
4>
6>
7> SELECT ID, Name
8> FROM Employee
9> WHERE ID IN
10>       (  SELECT ID FROM Job )
11> GO
ID          Name
----------- ----------
          1 Jason
          2 Robert
          3 Celia
          4 Linda
(4 rows affected)
1>
2>
3>
4> drop table employee;
5> drop table job;
6> GO
1>
2>