SQL Server/T-SQL/Transact SQL/Continue — различия между версиями
Admin (обсуждение | вклад) м (1 версия) |
Admin (обсуждение | вклад) м (1 версия) |
(нет различий)
|
Текущая версия на 10:20, 26 мая 2010
Continue statement Demo
1> create table employee(
2> ID int,
3> name nvarchar (10),
4> salary int,
5> start_date datetime,
6> city nvarchar (10),
7> region char (1))
8> GO
1>
2> insert into employee (ID, name, salary, start_date, city, region)
3> values (1, "Jason", 40420, "02/01/94", "New York", "W")
4> GO
(1 rows affected)
1> insert into employee (ID, name, salary, start_date, city, region)
2> values (2, "Robert",14420, "01/02/95", "Vancouver","N")
3> GO
(1 rows affected)
1> insert into employee (ID, name, salary, start_date, city, region)
2> values (3, "Celia", 24020, "12/03/96", "Toronto", "W")
3> GO
(1 rows affected)
1> insert into employee (ID, name, salary, start_date, city, region)
2> values (4, "Linda", 40620, "11/04/97", "New York", "N")
3> GO
(1 rows affected)
1> insert into employee (ID, name, salary, start_date, city, region)
2> values (5, "David", 80026, "10/05/98", "Vancouver","W")
3> GO
(1 rows affected)
1> insert into employee (ID, name, salary, start_date, city, region)
2> values (6, "James", 70060, "09/06/99", "Toronto", "N")
3> GO
(1 rows affected)
1> insert into employee (ID, name, salary, start_date, city, region)
2> values (7, "Alison",90620, "08/07/00", "New York", "W")
3> GO
(1 rows affected)
1> insert into employee (ID, name, salary, start_date, city, region)
2> values (8, "Chris", 26020, "07/08/01", "Vancouver","N")
3> GO
(1 rows affected)
1> insert into employee (ID, name, salary, start_date, city, region)
2> values (9, "Mary", 60020, "06/09/02", "Toronto", "W")
3> GO
(1 rows affected)
1>
2> select * from employee
3> GO
ID name salary start_date city region
----------- ---------- ----------- ----------------------- ---------- ------
1 Jason 40420 1994-02-01 00:00:00.000 New York W
2 Robert 14420 1995-01-02 00:00:00.000 Vancouver N
3 Celia 24020 1996-12-03 00:00:00.000 Toronto W
4 Linda 40620 1997-11-04 00:00:00.000 New York N
5 David 80026 1998-10-05 00:00:00.000 Vancouver W
6 James 70060 1999-09-06 00:00:00.000 Toronto N
7 Alison 90620 2000-08-07 00:00:00.000 New York W
8 Chris 26020 2001-07-08 00:00:00.000 Vancouver N
9 Mary 60020 2002-06-09 00:00:00.000 Toronto W
(9 rows affected)
1>
2> -- BREAK exits the WHILE structure, resuming execution after the END statement.
3>
4> WHILE (SELECT AVG(Salary) FROM Employee) < $92000
5> BEGIN
6> UPDATE Employee SET Salary = Salary * 1.25
7> SELECT MAX(Salary) FROM Employee
8> IF (SELECT MAX(Salary) FROM Employee) > $10000
9> BEGIN
10> PRINT "is too high, quit."
11> BREAK
12> END
13> ELSE
14> BEGIN
15> PRINT "Continue to loop."
16> CONTINUE
17> END
18> END
19> PRINT "Done."
20> GO
(9 rows affected)
-----------
113275
(1 rows affected)
is too high, quit.
(1 rows affected)
Done.
1>
2> drop table employee
3> GO
1>
CONTINUE stops only the current execution
24>
25> CREATE TABLE project (project_no CHAR(4) NOT NULL,
26> project_name CHAR(15) NOT NULL,
27> budget FLOAT NULL)
28>
29> insert into project values ("p1", "Search Engine", 120000.00)
30> insert into project values ("p2", "Programming", 95000.00)
31> insert into project values ("p3", "SQL", 186500.00)
32>
33> select * from project
34> GO
(1 rows affected)
(1 rows affected)
(1 rows affected)
project_no project_name budget
---------- --------------- ------------------------
p1 Search Engine 120000
p2 Programming 95000
p3 SQL 186500
(3 rows affected)
1>
2> -- CONTINUE stops only the current execution
3>
4>
5> WHILE (SELECT SUM(budget) FROM project) < 500000
6> BEGIN
7> UPDATE project SET budget = budget*1.1
8> IF (SELECT MAX(budget) FROM project) > 240000
9> BREAK
10> ELSE
11> CONTINUE
12> END
13>
14> select * from project
15> GO
(3 rows affected)
(3 rows affected)
(3 rows affected)
project_no project_name budget
---------- --------------- ------------------------
p1 Search Engine 159720
p2 Programming 126445.00000000004
p3 SQL 248231.50000000009
(3 rows affected)
1>
2> drop table project
3> GO
1>