PostgreSQL/String Functions/substr — различия между версиями
Admin (обсуждение | вклад) м (1 версия) |
Admin (обсуждение | вклад) м (1 версия) |
(нет различий)
|
Текущая версия на 10:13, 26 мая 2010
Содержание
substr("1234", 3)
postgres=# SELECT substr("1234", 3);
substr
--------
34
(1 row)
postgres=#
substr( (substring the digits)
postgres=# SELECT substr(1234, 3);
substr
--------
34
(1 row)
postgres=#
substr(CAST (1234 AS text), 3)
postgres=# SELECT substr(CAST (1234 AS text), 3);
substr
--------
34
(1 row)
postgres=#
postgres=#
substr(CAST (varchar "1234" AS text), 3)
postgres=# SELECT substr(CAST (varchar "1234" AS text), 3);
substr
--------
34
(1 row)
postgres=#
substr: return the substring
postgres=# CREATE TABLE employee (
postgres(# ID int,
postgres(# name varchar(10),
postgres(# salary real,
postgres(# start_date date,
postgres(# city varchar(10),
postgres(# region char(1)
postgres(# );
CREATE TABLE
postgres=#
postgres=# insert into employee (ID, name, salary, start_date, city, region)
postgres-# values (1, "Jason", 40420, "02/01/94", "New York", "W");
INSERT 0 1
postgres=# insert into employee (ID, name, salary, start_date, city, region)
postgres-# values (2, "Robert",14420, "01/02/95", "Vancouver","N");
INSERT 0 1
postgres=# insert into employee (ID, name, salary, start_date, city, region)
postgres-# values (3, "Celia", 24020, "12/03/96", "Toronto", "W");
INSERT 0 1
postgres=# insert into employee (ID, name, salary, start_date, city, region)
postgres-# values (4, "Linda", 40620, "11/04/97", "New York", "N");
INSERT 0 1
postgres=# insert into employee (ID, name, salary, start_date, city, region)
postgres-# values (5, "David", 80026, "10/05/98", "Vancouver","W");
INSERT 0 1
postgres=# insert into employee (ID, name, salary, start_date, city, region)
postgres-# values (6, "James", 70060, "09/06/99", "Toronto", "N");
INSERT 0 1
postgres=# insert into employee (ID, name, salary, start_date, city, region)
postgres-# values (7, "Alison",90620, "08/07/00", "New York", "W");
INSERT 0 1
postgres=# insert into employee (ID, name, salary, start_date, city, region)
postgres-# values (8, "Chris", 26020, "07/08/01", "Vancouver","N");
INSERT 0 1
postgres=# insert into employee (ID, name, salary, start_date, city, region)
postgres-# values (9, "Mary", 60020, "06/09/02", "Toronto", "W");
INSERT 0 1
postgres=#
postgres=# select * from employee;
id | name | salary | start_date | city | region
----+--------+--------+------------+-----------+--------
1 | Jason | 40420 | 1994-02-01 | New York | W
2 | Robert | 14420 | 1995-01-02 | Vancouver | N
3 | Celia | 24020 | 1996-12-03 | Toronto | W
4 | Linda | 40620 | 1997-11-04 | New York | N
5 | David | 80026 | 1998-10-05 | Vancouver | W
6 | James | 70060 | 1999-09-06 | Toronto | N
7 | Alison | 90620 | 2000-08-07 | New York | W
8 | Chris | 26020 | 2001-07-08 | Vancouver | N
9 | Mary | 60020 | 2002-06-09 | Toronto | W
(9 rows)
postgres=#
postgres=# SELECT name, substr(name, 15), substr(name, 5, 9)
postgres-# FROM employee
postgres-# ORDER BY name DESC
postgres-# LIMIT 3;
name | substr | substr
--------+--------+--------
Robert | | rt
Mary | |
Linda | | a
(3 rows)
postgres=#
postgres=#
postgres=# drop table employee;
DROP TABLE
postgres=#
substr(varchar "1234", 3)
postgres=# SELECT substr(varchar "1234", 3);
substr
--------
34
(1 row)
postgres=#