Oracle PL/SQL Tutorial/Character String Functions/SUBSTR — различия между версиями

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Текущая версия на 10:11, 26 мая 2010

A retrieval with no third argument: it starts at begin and retrieves the rest of the string

SQL> SELECT SUBSTR("My address is 123 Fourth St.",6) FROM dual;
SUBSTR("MYADDRESSIS123F
-----------------------
dress is 123 Fourth St.
SQL>


Combine DECODE and SUBSTR together

SQL>
SQL>
SQL> -- create demo table
SQL> create table Employee(
  2    ID                 VARCHAR2(4 BYTE)         NOT NULL,
  3    First_Name         VARCHAR2(10 BYTE),
  4    Last_Name          VARCHAR2(10 BYTE),
  5    Start_Date         DATE,
  6    End_Date           DATE,
  7    Salary             Number(8,2),
  8    City               VARCHAR2(10 BYTE),
  9    Description        VARCHAR2(15 BYTE)
 10  )
 11  /
Table created.
SQL>
SQL> -- prepare data
SQL> insert into Employee(ID,  First_Name, Last_Name, Start_Date,                     End_Date,                       Salary,  City,       Description)
  2               values ("01","Jason",    "Martin",  to_date("19960725","YYYYMMDD"), to_date("20060725","YYYYMMDD"), 1234.56, "Toronto",  "Programmer")
  3  /
1 row created.
SQL> insert into Employee(ID,  First_Name, Last_Name, Start_Date,                     End_Date,                       Salary,  City,       Description)
  2                values("02","Alison",   "Mathews", to_date("19760321","YYYYMMDD"), to_date("19860221","YYYYMMDD"), 6661.78, "Vancouver","Tester")
  3  /
1 row created.
SQL> insert into Employee(ID,  First_Name, Last_Name, Start_Date,                     End_Date,                       Salary,  City,       Description)
  2                values("03","James",    "Smith",   to_date("19781212","YYYYMMDD"), to_date("19900315","YYYYMMDD"), 6544.78, "Vancouver","Tester")
  3  /
1 row created.
SQL> insert into Employee(ID,  First_Name, Last_Name, Start_Date,                     End_Date,                       Salary,  City,       Description)
  2                values("04","Celia",    "Rice",    to_date("19821024","YYYYMMDD"), to_date("19990421","YYYYMMDD"), 2344.78, "Vancouver","Manager")
  3  /
1 row created.
SQL> insert into Employee(ID,  First_Name, Last_Name, Start_Date,                     End_Date,                       Salary,  City,       Description)
  2                values("05","Robert",   "Black",   to_date("19840115","YYYYMMDD"), to_date("19980808","YYYYMMDD"), 2334.78, "Vancouver","Tester")
  3  /
1 row created.
SQL> insert into Employee(ID,  First_Name, Last_Name, Start_Date,                     End_Date,                       Salary, City,        Description)
  2                values("06","Linda",    "Green",   to_date("19870730","YYYYMMDD"), to_date("19960104","YYYYMMDD"), 4322.78,"New York",  "Tester")
  3  /
1 row created.
SQL> insert into Employee(ID,  First_Name, Last_Name, Start_Date,                     End_Date,                       Salary, City,        Description)
  2                values("07","David",    "Larry",   to_date("19901231","YYYYMMDD"), to_date("19980212","YYYYMMDD"), 7897.78,"New York",  "Manager")
  3  /
1 row created.
SQL> insert into Employee(ID,  First_Name, Last_Name, Start_Date,                     End_Date,                       Salary, City,        Description)
  2                values("08","James",    "Cat",     to_date("19960917","YYYYMMDD"), to_date("20020415","YYYYMMDD"), 1232.78,"Vancouver", "Tester")
  3  /
1 row created.
SQL>
SQL>
SQL>
SQL> -- display data in the table
SQL> select * from Employee
  2  /

ID   FIRST_NAME LAST_NAME  START_DAT END_DATE      SALARY CITY       DESCRIPTION
---- ---------- ---------- --------- --------- ---------- ---------- ---------------
01   Jason      Martin     25-JUL-96 25-JUL-06    1234.56 Toronto    Programmer
02   Alison     Mathews    21-MAR-76 21-FEB-86    6661.78 Vancouver  Tester
03   James      Smith      12-DEC-78 15-MAR-90    6544.78 Vancouver  Tester
04   Celia      Rice       24-OCT-82 21-APR-99    2344.78 Vancouver  Manager
05   Robert     Black      15-JAN-84 08-AUG-98    2334.78 Vancouver  Tester
06   Linda      Green      30-JUL-87 04-JAN-96    4322.78 New York   Tester
07   David      Larry      31-DEC-90 12-FEB-98    7897.78 New York   Manager
08   James      Cat        17-SEP-96 15-APR-02    1232.78 Vancouver  Tester
8 rows selected.
SQL>
SQL> SELECT DECODE(SUBSTR(first_name, 1, 2),
  2                "Ja", "Western",
  3                "Ro", "Eastern",
  4                "* Unknown *"
  5                ) "Name"
  6  FROM   employee;

Name
-----------
Western
* Unknown *
Western
* Unknown *
Eastern
* Unknown *
* Unknown *
Western
8 rows selected.
SQL>
SQL> -- clean the table
SQL> drop table Employee
  2  /
Table dropped.
SQL>
SQL>
SQL>


Combine SUBSTR and INSTR to deal with a table column

SQL>
SQL>
SQL> -- create demo table
SQL> create table Employee(
  2    ID                 VARCHAR2(4 BYTE) ,
  3    First_Name         VARCHAR2(10 BYTE),
  4    Last_Name          VARCHAR2(10 BYTE),
  5    Start_Date         DATE,
  6    End_Date           DATE,
  7    Salary             Number(8,2),
  8    City               VARCHAR2(10 BYTE),
  9    Description        VARCHAR2(15 BYTE)
 10  )
 11  /
Table created.
SQL>
SQL> -- prepare data
SQL> insert into Employee(ID,  First_Name, Last_Name, Start_Date,                     End_Date,                       Salary,  City,       Description)
  2               values ("01","Jason",    "Martin",  to_date("19960725","YYYYMMDD"), to_date("20060725","YYYYMMDD"), 1234.56, "Toronto",  "Programmer")
  3  /
1 row created.
SQL> insert into Employee(ID,  First_Name, Last_Name, Start_Date,                     End_Date,                       Salary,  City,       Description)
  2                values("02","Alison",   "Mathews", to_date("19760321","YYYYMMDD"), to_date("19860221","YYYYMMDD"), 6661.78, "Vancouver","Tester")
  3  /
1 row created.
SQL> insert into Employee(ID,  First_Name, Last_Name, Start_Date,                     End_Date,                       Salary,  City,       Description)
  2                values("03","James",    "Smith",   to_date("19781212","YYYYMMDD"), to_date("19900315","YYYYMMDD"), 6544.78, "Vancouver","Tester")
  3  /
1 row created.
SQL> insert into Employee(ID,  First_Name, Last_Name, Start_Date,                     End_Date,                       Salary,  City,       Description)
  2                values("04","Celia",    "Rice",    to_date("19821024","YYYYMMDD"), to_date("19990421","YYYYMMDD"), 2344.78, "Vancouver","Manager")
  3  /
1 row created.
SQL> insert into Employee(ID,  First_Name, Last_Name, Start_Date,                     End_Date,                       Salary,  City,       Description)
  2                values("05","Robert",   "Black",   to_date("19840115","YYYYMMDD"), to_date("19980808","YYYYMMDD"), 2334.78, "Vancouver","Tester")
  3  /
1 row created.
SQL> insert into Employee(ID,  First_Name, Last_Name, Start_Date,                     End_Date,                       Salary, City,        Description)
  2                values("06","Linda",    "Green",   to_date("19870730","YYYYMMDD"), to_date("19960104","YYYYMMDD"), 4322.78,"New York",  "Tester")
  3  /
1 row created.
SQL> insert into Employee(ID,  First_Name, Last_Name, Start_Date,                     End_Date,                       Salary, City,        Description)
  2                values("07","David",    "Larry",   to_date("19901231","YYYYMMDD"), to_date("19980212","YYYYMMDD"), 7897.78,"New York",  "Manager")
  3  /
1 row created.
SQL> insert into Employee(ID,  First_Name, Last_Name, Start_Date,                     End_Date,                       Salary, City,        Description)
  2                values("08","James",    "Cat",     to_date("19960917","YYYYMMDD"), to_date("20020415","YYYYMMDD"), 1232.78,"Vancouver", "Tester")
  3  /
1 row created.
SQL>
SQL>
SQL>
SQL> -- display data in the table
SQL> select * from Employee
  2  /
ID   FIRST_NAME           LAST_NAME            START_DAT END_DATE      SALARY CITY       DESCRIPTION
---- -------------------- -------------------- --------- --------- ---------- ---------- ---------------
01   Jason                Martin               25-JUL-96 25-JUL-06    1234.56 Toronto    Programmer
02   Alison               Mathews              21-MAR-76 21-FEB-86    6661.78 Vancouver  Tester
03   James                Smith                12-DEC-78 15-MAR-90    6544.78 Vancouver  Tester
04   Celia                Rice                 24-OCT-82 21-APR-99    2344.78 Vancouver  Manager
05   Robert               Black                15-JAN-84 08-AUG-98    2334.78 Vancouver  Tester
06   Linda                Green                30-JUL-87 04-JAN-96    4322.78 New York   Tester
07   David                Larry                31-DEC-90 12-FEB-98    7897.78 New York   Manager
08   James                Cat                  17-SEP-96 15-APR-02    1232.78 Vancouver  Tester
8 rows selected.
SQL>
SQL> SELECT description, SUBSTR(description, 1, INSTR(description, "r", 1 ) -1 )FROM   employee;
DESCRIPTION     SUBSTR(DESCRIPT
--------------- ---------------
Programmer      P
Tester          Teste
Tester          Teste
Manager         Manage
Tester          Teste
Tester          Teste
Manager         Manage
Tester          Teste
8 rows selected.
SQL>
SQL>
SQL> drop table Employee
  2  /
Table dropped.
SQL>


Compare substring in where statement

SQL>
SQL> CREATE TABLE employee
  2  (employee_id         NUMBER(7),
  3   last_name           VARCHAR2(25),
  4   first_name          VARCHAR2(25),
  5   userid              VARCHAR2(8),
  6   start_date          DATE,
  7   comments            VARCHAR2(255),
  8   manager_id          NUMBER(7),
  9   title               VARCHAR2(25),
 10   department_id       NUMBER(7),
 11   salary              NUMBER(11, 2),
 12   commission_pct      NUMBER(4, 2)
 13  );
Table created.
SQL>
SQL> INSERT INTO employee VALUES (1, "V", "Ben", "cv",to_date("03-MAR-90 8:30", "dd-mon-yy hh24:mi"),NULL, NULL, "PRESIDENT", 50, 2500, NULL);
1 row created.
SQL> INSERT INTO employee VALUES (2, "N", "Haidy", "ln", "08-MAR-90", NULL,1, "VP, OPERATIONS", 41, 1450, NULL);
1 row created.
SQL> INSERT INTO employee VALUES (3, "N", "Molly", "mn", "17-JUN-91",NULL, 1, "VP, SALES", 31, 1400, NULL);
1 row created.
SQL> INSERT INTO employee VALUES (4, "S", "Mark", "mq", "07-APR-90",NULL, 1, "VP, FINANCE", 10, 1450, NULL);
1 row created.
SQL> INSERT INTO employee VALUES (5, "R", "AUDRY", "ar", "04-MAR-90",NULL, 1, "VP, ADMINISTRATION", 50, 1550, NULL);
1 row created.
SQL> INSERT INTO employee VALUES (6, "U", "MOLLY", "mu", "18-JAN-91",NULL, 2, "WAREHOUSE MANAGER", 41, 1200, NULL);
1 row created.
SQL> INSERT INTO employee VALUES (7, "M", "ROBERTA", "rm", "14-MAY-90",NULL, 2, "WAREHOUSE MANAGER", 41, 1250, NULL);
1 row created.
SQL> INSERT INTO employee VALUES (8, "B", "BEN", "ry", "07-APR-90", NULL, 2,"WAREHOUSE MANAGER", 41, 1100, NULL);
1 row created.
SQL> INSERT INTO employee VALUES (9, "C", "Jane", "ac", "09-FEB-92",NULL, 2, "WAREHOUSE MANAGER", 41, 1300, NULL);
1 row created.
SQL> INSERT INTO employee VALUES (10, "H", "Mart", "mh", "27-FEB-91", NULL, 2,"WAREHOUSE MANAGER", 41, 1307, NULL);
1 row created.
SQL>
SQL>
SQL> SELECT last_name, first_name
  2  FROM   employee
  3  WHERE  substr(employee_id,1,5) = 76031;
no rows selected
SQL>
SQL>
SQL> drop table employee;
Table dropped.
SQL>
SQL>


Example SELECT output using SUBSTR().

SQL>
SQL> select substr(owner,1,10) owner,
  2      substr(object_name,1,10) object_name,
  3      substr(object_type, 1,10) object_type,
  4      to_char(last_ddl_time,"dd-mon-yyyy hh24:mi") last_ddl_time
  5  from dba_objects
  6  where owner="SYSTEM" and rownum < 50;
OWNER      OBJECT_NAM OBJECT_TYP LAST_DDL_TIME
---------- ---------- ---------- -----------------
SYSTEM     SYSCATALOG SYNONYM    07-feb-2006 22:12
SYSTEM     CATALOG    SYNONYM    07-feb-2006 22:12
SYSTEM     TAB        SYNONYM    07-feb-2006 22:12
SYSTEM     COL        SYNONYM    07-feb-2006 22:12
SYSTEM     TABQUOTAS  SYNONYM    07-feb-2006 22:12
SYSTEM     SYSFILES   SYNONYM    07-feb-2006 22:12
SYSTEM     PUBLICSYN  SYNONYM    07-feb-2006 22:12
SYSTEM     MVIEW$_ADV TABLE      07-feb-2006 22:13
SYSTEM     MVIEW$_ADV INDEX      07-feb-2006 22:13
SYSTEM     MVIEW$_ADV INDEX      07-feb-2006 22:13
SYSTEM     MVIEW$_ADV TABLE      07-feb-2006 22:13
SYSTEM     MVIEW$_ADV INDEX      07-feb-2006 22:13
SYSTEM     MVIEW$_ADV TABLE      07-feb-2006 22:13
SYSTEM     MVIEW$_ADV INDEX      07-feb-2006 22:13
SYSTEM     MVIEW$_ADV TABLE      07-feb-2006 22:13
SYSTEM     MVIEW$_ADV INDEX      07-feb-2006 22:13
SYSTEM     MVIEW$_ADV TABLE      07-feb-2006 22:13
SYSTEM     MVIEW$_ADV INDEX      07-feb-2006 22:13
SYSTEM     MVIEW$_ADV TABLE      07-feb-2006 22:13
SYSTEM     MVIEW$_ADV INDEX      07-feb-2006 22:13
SYSTEM     MVIEW$_ADV TABLE      07-feb-2006 22:13
SYSTEM     MVIEW$_ADV INDEX      07-feb-2006 22:13
SYSTEM     MVIEW$_ADV TABLE      07-feb-2006 22:13
SYSTEM     MVIEW$_ADV TABLE      07-feb-2006 22:13
SYSTEM     MVIEW$_ADV INDEX      07-feb-2006 22:13
SYSTEM     MVIEW$_ADV TABLE      07-feb-2006 22:13
SYSTEM     MVIEW$_ADV INDEX      07-feb-2006 22:13
SYSTEM     MVIEW$_ADV TABLE      07-feb-2006 22:13
SYSTEM     MVIEW$_ADV INDEX      07-feb-2006 22:13
SYSTEM     MVIEW$_ADV TABLE      07-feb-2006 22:13
SYSTEM     MVIEW$_ADV INDEX      07-feb-2006 22:13
SYSTEM     MVIEW$_ADV TABLE      07-feb-2006 22:13
SYSTEM     MVIEW$_ADV INDEX      07-feb-2006 22:13
SYSTEM     MVIEW$_ADV TABLE      07-feb-2006 22:13
SYSTEM     MVIEW$_ADV INDEX      07-feb-2006 22:13
SYSTEM     MVIEW$_ADV TABLE      07-feb-2006 22:13
SYSTEM     MVIEW$_ADV INDEX      07-feb-2006 22:13
SYSTEM     MVIEW$_ADV TABLE      07-feb-2006 22:13
SYSTEM     MVIEW$_ADV INDEX      07-feb-2006 22:13
SYSTEM     MVIEW$_ADV TABLE      07-feb-2006 22:13
SYSTEM     MVIEW$_ADV TABLE      07-feb-2006 22:13
SYSTEM     MVIEW$_ADV INDEX      07-feb-2006 22:13
SYSTEM     MVIEW$_ADV TABLE      07-feb-2006 22:13
SYSTEM     MVIEW$_ADV INDEX      07-feb-2006 22:13
SYSTEM     MVIEW$_ADV TABLE      07-feb-2006 22:13
SYSTEM     MVIEW$_ADV INDEX      07-feb-2006 22:13
SYSTEM     MVIEW$_ADV TABLE      07-feb-2006 22:13
SYSTEM     MVIEW$_ADV SEQUENCE   07-feb-2006 22:13
SYSTEM     MVIEW$_ADV SEQUENCE   07-feb-2006 22:13
49 rows selected.
SQL>
SQL>
SQL>


If begin is negative, then retrieval occurs from the right-hand side of original string

SQL> SELECT SUBSTR("My address is 123 Fourth St.",-9,5)FROM dual;
SUBST
-----
ourth
SQL>


Manipulating Strings: SUBSTR and concatenation

SQL>
SQL> CREATE TABLE emp (
  2     empID INT NOT NULL PRIMARY KEY,
  3     Name      VARCHAR(50) NOT NULL);
Table created.
SQL> INSERT INTO emp (empID,Name) VALUES (1,"Tom");
1 row created.
SQL> INSERT INTO emp (empID,Name) VALUES (2,"Jack");
1 row created.
SQL> INSERT INTO emp (empID,Name) VALUES (3,"Mary");
1 row created.
SQL> INSERT INTO emp (empID,Name) VALUES (4,"Bill");
1 row created.
SQL> INSERT INTO emp (empID,Name) VALUES (5,"Cat");
1 row created.
SQL> INSERT INTO emp (empID,Name) VALUES (6,"Victor");
1 row created.
SQL>
SQL>
SQL>
SQL> SELECT
  2     SUBSTR(Name, INSTR(Name, " ") + 1) || ", " ||
  3     SUBSTR(Name, 1, INSTR(Name, " ") - 1) AS empName
  4  FROM emp
  5  ORDER BY empName;
EMPNAME
--------------------------------------------------------------------------------
Bill,
Cat,
Jack,
Mary,
Tom,
Victor,
6 rows selected.
SQL>
SQL>
SQL> drop table emp;
Table dropped.


Retrieval begins at position 5 and again goes for 12 characters

SQL> SELECT SUBSTR("My address is 1234 Fourth St.",5,12)FROM dual;
SUBSTR("MYAD
------------
ddress is 12
SQL>


SUBSTR and INSTR used together

SQL> SELECT SUBSTR("H, J E", INSTR("H, J E",", ")+2) FROM dual;
SUB
---
J E
SQL>


substr(,) and substr(,,)

SQL>
SQL> create table departments
  2  ( deptno NUMBER(2)
  3  , dname  VARCHAR2(10)
  4  , location VARCHAR2(20)
  5  , mgr    NUMBER(4)
  6  ) ;
Table created.
SQL>
SQL> insert into departments values (10,"ACCOUNTING","NEW YORK" ,  2);
1 row created.
SQL> insert into departments values (20,"TRAINING",  "VANCOUVER",  3);
1 row created.
SQL> insert into departments values (30,"SALES",     "CHICAGO",    4);
1 row created.
SQL> insert into departments values (40,"HR",        "BOSTON",     5);
1 row created.
SQL>
SQL>
SQL>
SQL> select dname
  2  ,      substr(dname,4)      as substr1
  3  ,      substr(dname,4,3)    as substr2
  4  from   departments;
DNAME      SUBSTR1 SUBSTR2
---------- ------- -------
ACCOUNTING OUNTING OUN
TRAINING   INING   INI
SALES      ES      ES
HR
SQL>
SQL> drop table departments;
Table dropped.


substr birthday

SQL>
SQL>
SQL> create table employees(
  2    empno      NUMBER(4)
  3  , ename      VARCHAR2(8)
  4  , init       VARCHAR2(5)
  5  , job        VARCHAR2(8)
  6  , mgr        NUMBER(4)
  7  , bdate      DATE
  8  , msal       NUMBER(6,2)
  9  , comm       NUMBER(6,2)
 10  , deptno     NUMBER(2) ) ;
Table created.
SQL>
SQL>
SQL> insert into employees values(1,"Jason",  "N",  "TRAINER", 2,   date "1965-12-18",  800 , NULL,  10);
1 row created.
SQL> insert into employees values(2,"Jerry",  "J",  "SALESREP",3,   date "1966-11-19",  1600, 300,   10);
1 row created.
SQL> insert into employees values(3,"Jord",   "T" , "SALESREP",4,   date "1967-10-21",  1700, 500,   20);
1 row created.
SQL> insert into employees values(4,"Mary",   "J",  "MANAGER", 5,   date "1968-09-22",  1800, NULL,  20);
1 row created.
SQL> insert into employees values(5,"Joe",    "P",  "SALESREP",6,   date "1969-08-23",  1900, 1400,  30);
1 row created.
SQL> insert into employees values(6,"Black",  "R",  "MANAGER", 7,   date "1970-07-24",  2000, NULL,  30);
1 row created.
SQL> insert into employees values(7,"Red",    "A",  "MANAGER", 8,   date "1971-06-25",  2100, NULL,  40);
1 row created.
SQL> insert into employees values(8,"White",  "S",  "TRAINER", 9,   date "1972-05-26",  2200, NULL,  40);
1 row created.
SQL> insert into employees values(9,"Yellow", "C",  "DIRECTOR",10,  date "1973-04-27",  2300, NULL,  20);
1 row created.
SQL> insert into employees values(10,"Pink",  "J",  "SALESREP",null,date "1974-03-28",  2400, 0,     30);
1 row created.
SQL>
SQL>
SQL> select ename, substr(bdate,8)+16
  2  from   employees;
ENAME    SUBSTR(BDATE,8)+16
-------- ------------------
Jason                    81
Jerry                    82
Jord                     83
Mary                     84
Joe                      85
Black                    86
Red                      87
White                    88
Yellow                   89
Pink                     90
10 rows selected.
SQL>
SQL> drop table employees;
Table dropped.


substr(date value,8)+16

SQL> create table emp
  2  ( empno      NUMBER(4)    constraint E_PK primary key
  3  , ename      VARCHAR2(8)
  4  , init       VARCHAR2(5)
  5  , job        VARCHAR2(8)
  6  , mgr        NUMBER(4)
  7  , bdate      DATE
  8  , sal        NUMBER(6,2)
  9  , comm       NUMBER(6,2)
 10  , deptno     NUMBER(2)    default 10
 11  ) ;
Table created.
SQL> insert into emp values(1,"Tom","N",   "Coder", 13,date "1965-12-17",  800 , NULL,  20);
1 row created.
SQL> insert into emp values(2,"Jack","JAM", "Tester",6,date "1961-02-20",  1600, 300,   30);
1 row created.
SQL> insert into emp values(3,"Wil","TF" ,  "Tester",6,date "1962-02-22",  1250, 500,   30);
1 row created.
SQL> insert into emp values(4,"Jane","JM",  "Designer", 9,date "1967-04-02",  2975, NULL,  20);
1 row created.
SQL> insert into emp values(5,"Mary","P",  "Tester",6,date "1956-09-28",  1250, 1400,  30);
1 row created.
SQL> insert into emp values(6,"Black","R",   "Designer", 9,date "1963-11-01",  2850, NULL,  30);
1 row created.
SQL> insert into emp values(7,"Chris","AB",  "Designer", 9,date "1965-06-09",  2450, NULL,  10);
1 row created.
SQL> insert into emp values(8,"Smart","SCJ", "Coder", 4,date "1959-11-26",  3000, NULL,  20);
1 row created.
SQL> insert into emp values(9,"Peter","CC",   "Designer",NULL,date "1952-11-17",  5000, NULL,  10);
1 row created.
SQL> insert into emp values(10,"Take","JJ", "Tester",6,date "1968-09-28",  1500, 0,     30);
1 row created.
SQL> insert into emp values(11,"Ana","AA",  "Coder", 8,date "1966-12-30",  1100, NULL,  20);
1 row created.
SQL> insert into emp values(12,"Jane","R",   "Manager",   6,date "1969-12-03",  800 , NULL,  30);
1 row created.
SQL> insert into emp values(13,"Fake","MG",   "Coder", 4,date "1959-02-13",  3000, NULL,  20);
1 row created.
SQL> insert into emp values(14,"Mike","TJA","Manager",   7,date "1962-01-23",  1300, NULL,  10);
1 row created.
SQL>
SQL> select ename, substr(bdate,8)+16
  2  from   emp
  3  where  deptno = 10;
ENAME    SUBSTR(BDATE,8)+16
-------- ------------------
Chris                   981
Peter                   968
Mike                    978
SQL>
SQL> drop table emp;
Table dropped.


Substr retrieves a portion of the string

The general format for this function is:

SUBSTR(string, start_at_position, number_of_characters_to_retrieve)



SQL>
SQL> SELECT SUBSTR("Mississippi", 5, 3) FROM dual;
SUB
---
iss
SQL>


SUBSTR(x, start [, length]) returns a substring of x that begins at the position specified by start.

You can also provide an optional length for the substring.

The following example uses SUBSTR() to select a two-character substring starting at position 2 from the first name column of the employee table:



SQL> -- create demo table
SQL> create table Employee(
  2    ID                 VARCHAR2(4 BYTE)         NOT NULL,
  3    First_Name         VARCHAR2(10 BYTE),
  4    Last_Name          VARCHAR2(10 BYTE),
  5    Start_Date         DATE,
  6    End_Date           DATE,
  7    Salary             Number(8,2),
  8    City               VARCHAR2(10 BYTE),
  9    Description        VARCHAR2(15 BYTE)
 10  )
 11  /
Table created.
SQL>
SQL> -- prepare data
SQL> insert into Employee(ID,  First_Name, Last_Name, Start_Date,                     End_Date,                       Salary,  City,       Description)
  2               values ("01","Jason",    "Martin",  to_date("19960725","YYYYMMDD"), to_date("20060725","YYYYMMDD"), 1234.56, "Toronto",  "Programmer")
  3  /
1 row created.
SQL> insert into Employee(ID,  First_Name, Last_Name, Start_Date,                     End_Date,                       Salary,  City,       Description)
  2                values("02","Alison",   "Mathews", to_date("19760321","YYYYMMDD"), to_date("19860221","YYYYMMDD"), 6661.78, "Vancouver","Tester")
  3  /
1 row created.
SQL> insert into Employee(ID,  First_Name, Last_Name, Start_Date,                     End_Date,                       Salary,  City,       Description)
  2                values("03","James",    "Smith",   to_date("19781212","YYYYMMDD"), to_date("19900315","YYYYMMDD"), 6544.78, "Vancouver","Tester")
  3  /
1 row created.
SQL> insert into Employee(ID,  First_Name, Last_Name, Start_Date,                     End_Date,                       Salary,  City,       Description)
  2                values("04","Celia",    "Rice",    to_date("19821024","YYYYMMDD"), to_date("19990421","YYYYMMDD"), 2344.78, "Vancouver","Manager")
  3  /
1 row created.
SQL> insert into Employee(ID,  First_Name, Last_Name, Start_Date,                     End_Date,                       Salary,  City,       Description)
  2                values("05","Robert",   "Black",   to_date("19840115","YYYYMMDD"), to_date("19980808","YYYYMMDD"), 2334.78, "Vancouver","Tester")
  3  /
1 row created.
SQL> insert into Employee(ID,  First_Name, Last_Name, Start_Date,                     End_Date,                       Salary, City,        Description)
  2                values("06","Linda",    "Green",   to_date("19870730","YYYYMMDD"), to_date("19960104","YYYYMMDD"), 4322.78,"New York",  "Tester")
  3  /
1 row created.
SQL> insert into Employee(ID,  First_Name, Last_Name, Start_Date,                     End_Date,                       Salary, City,        Description)
  2                values("07","David",    "Larry",   to_date("19901231","YYYYMMDD"), to_date("19980212","YYYYMMDD"), 7897.78,"New York",  "Manager")
  3  /
1 row created.
SQL> insert into Employee(ID,  First_Name, Last_Name, Start_Date,                     End_Date,                       Salary, City,        Description)
  2                values("08","James",    "Cat",     to_date("19960917","YYYYMMDD"), to_date("20020415","YYYYMMDD"), 1232.78,"Vancouver", "Tester")
  3  /
1 row created.
SQL>
SQL>
SQL>
SQL> -- display data in the table
SQL> select * from Employee
  2  /
ID   FIRST_NAME LAST_NAME  START_DAT END_DATE      SALARY CITY       DESCRIPTION
---- ---------- ---------- --------- --------- ---------- ---------- ---------------
01   Jason      Martin     25-JUL-96 25-JUL-06    1234.56 Toronto    Programmer
02   Alison     Mathews    21-MAR-76 21-FEB-86    6661.78 Vancouver  Tester
03   James      Smith      12-DEC-78 15-MAR-90    6544.78 Vancouver  Tester
04   Celia      Rice       24-OCT-82 21-APR-99    2344.78 Vancouver  Manager
05   Robert     Black      15-JAN-84 08-AUG-98    2334.78 Vancouver  Tester
06   Linda      Green      30-JUL-87 04-JAN-96    4322.78 New York   Tester
07   David      Larry      31-DEC-90 12-FEB-98    7897.78 New York   Manager
08   James      Cat        17-SEP-96 15-APR-02    1232.78 Vancouver  Tester
8 rows selected.
SQL>
SQL>
SQL>
SQL> SELECT SUBSTR(first_name, 2, 2) FROM employee;
SU
--
as
li
am
el
ob
in
av
am
8 rows selected.
SQL>
SQL>
SQL>
SQL> -- clean the table
SQL> drop table Employee
  2  /
Table dropped.


The SUBSTR Function

The SUBSTR function returns part of a string.

The general syntax of the function is as follows:

SUBSTR(original string, begin [,how far])

An original string is to be dissected beginning at the begin character.

If "how far" amount is not specified, then the rest of the string from the begin point is retrieved.

If begin is negative, then retrieval occurs from the right-hand side of original string.



SQL> SELECT SUBSTR("My address is 123 Fourth St.",1,12)FROM dual
  2  /
SUBSTR("MYAD
------------
My address i
SQL>