Oracle PL/SQL/Insert Delete Update/Update subquery — различия между версиями
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Текущая версия на 09:56, 26 мая 2010
Update records in one table based on values in another table
SQL> CREATE TABLE EMP (EMPNO NUMBER(4) NOT NULL,
2 ENAME VARCHAR2(10),
3 JOB VARCHAR2(9),
4 MGR NUMBER(4),
5 HIREDATE DATE,
6 SAL NUMBER(7, 2),
7 COMM NUMBER(7, 2),
8 DEPTNO NUMBER(2));
SQL>
SQL> INSERT INTO EMP VALUES (7369, "SMITH", "CLERK", 7902, TO_DATE("17-DEC-1980", "DD-MON-YYYY"), 800, NULL, 20);
SQL> INSERT INTO EMP VALUES (7499, "ALLEN", "SALESMAN", 7698, TO_DATE("20-FEB-1981", "DD-MON-YYYY"), 1600, 300, 30);
SQL> INSERT INTO EMP VALUES (7521, "WARD", "SALESMAN", 7698, TO_DATE("22-FEB-1981", "DD-MON-YYYY"), 1250, 500, 30);
SQL> INSERT INTO EMP VALUES (7566, "JONES", "MANAGER", 7839, TO_DATE("2-APR-1981", "DD-MON-YYYY"), 2975, NULL, 20);
SQL> INSERT INTO EMP VALUES (7654, "MARTIN", "SALESMAN", 7698,TO_DATE("28-SEP-1981", "DD-MON-YYYY"), 1250, 1400, 30);
SQL> INSERT INTO EMP VALUES (7698, "BLAKE", "MANAGER", 7839,TO_DATE("1-MAY-1981", "DD-MON-YYYY"), 2850, NULL, 30);
SQL> INSERT INTO EMP VALUES (7782, "CLARK", "MANAGER", 7839,TO_DATE("9-JUN-1981", "DD-MON-YYYY"), 2450, NULL, 10);
SQL> INSERT INTO EMP VALUES (7788, "SCOTT", "ANALYST", 7566,TO_DATE("09-DEC-1982", "DD-MON-YYYY"), 3000, NULL, 20);
SQL> INSERT INTO EMP VALUES (7839, "KING", "PRESIDENT", NULL,TO_DATE("17-NOV-1981", "DD-MON-YYYY"), 5000, NULL, 10);
SQL> INSERT INTO EMP VALUES (7844, "TURNER", "SALESMAN", 7698,TO_DATE("8-SEP-1981", "DD-MON-YYYY"), 1500, 0, 30);
SQL> INSERT INTO EMP VALUES (7876, "ADAMS", "CLERK", 7788,TO_DATE("12-JAN-1983", "DD-MON-YYYY"), 1100, NULL, 20);
SQL> INSERT INTO EMP VALUES (7900, "JAMES", "CLERK", 7698,TO_DATE("3-DEC-1981", "DD-MON-YYYY"), 950, NULL, 30);
SQL> INSERT INTO EMP VALUES (7902, "FORD", "ANALYST", 7566,TO_DATE("3-DEC-1981", "DD-MON-YYYY"), 3000, NULL, 20);
SQL> INSERT INTO EMP VALUES (7934, "MILLER", "CLERK", 7782,TO_DATE("23-JAN-1982", "DD-MON-YYYY"), 1300, NULL, 10);
SQL>
SQL> CREATE TABLE DEPT (DEPTNO NUMBER(2),DNAME VARCHAR2(14),LOC VARCHAR2(13) );
SQL>
SQL> INSERT INTO DEPT VALUES (10, "ACCOUNTING", "NEW YORK");
SQL> INSERT INTO DEPT VALUES (20, "RESEARCH", "DALLAS");
SQL> INSERT INTO DEPT VALUES (30, "SALES", "CHICAGO");
SQL> INSERT INTO DEPT VALUES (40, "OPERATIONS", "BOSTON");
SQL>
SQL> select * from emp;
EMPNO ENAME JOB MGR HIREDATE SAL COMM DEPTNO
---------- ---------- --------- ---------- --------- ---------- ---------- ----------
7369 SMITH CLERK 7902 17-DEC-80 800 20
7499 ALLEN SALESMAN 7698 20-FEB-81 1600 300 30
7521 WARD SALESMAN 7698 22-FEB-81 1250 500 30
7566 JONES MANAGER 7839 02-APR-81 2975 20
7654 MARTIN SALESMAN 7698 28-SEP-81 1250 1400 30
7698 BLAKE MANAGER 7839 01-MAY-81 2850 30
7782 CLARK MANAGER 7839 09-JUN-81 2450 10
7788 SCOTT ANALYST 7566 09-DEC-82 3000 20
7839 KING PRESIDENT 17-NOV-81 5000 10
7844 TURNER SALESMAN 7698 08-SEP-81 1500 0 30
7876 ADAMS CLERK 7788 12-JAN-83 1100 20
EMPNO ENAME JOB MGR HIREDATE SAL COMM DEPTNO
---------- ---------- --------- ---------- --------- ---------- ---------- ----------
7900 JAMES CLERK 7698 03-DEC-81 950 30
7902 FORD ANALYST 7566 03-DEC-81 3000 20
7934 MILLER CLERK 7782 23-JAN-82 1300 10
SQL>
SQL> select * from dept;
DEPTNO DNAME LOC
---------- -------------- -------------
10 ACCOUNTING NEW YORK
20 RESEARCH DALLAS
30 SALES CHICAGO
40 OPERATIONS BOSTON
SQL>
SQL> -- update records in one table based on values in another table.
SQL>
SQL> UPDATE emp
2 SET ename = ( SELECT dname
3 FROM dept
4 WHERE emp.deptno = dept.deptno)
5 WHERE EXISTS
6 ( SELECT dname
7 FROM dept
8 WHERE emp.deptno = dept.deptno);
SQL>
SQL>
SQL>
SQL> select * from emp;
EMPNO ENAME JOB MGR HIREDATE SAL COMM DEPTNO
---------- ---------- --------- ---------- --------- ---------- ---------- ----------
7369 RESEARCH CLERK 7902 17-DEC-80 800 20
7499 SALES SALESMAN 7698 20-FEB-81 1600 300 30
7521 SALES SALESMAN 7698 22-FEB-81 1250 500 30
7566 RESEARCH MANAGER 7839 02-APR-81 2975 20
7654 SALES SALESMAN 7698 28-SEP-81 1250 1400 30
7698 SALES MANAGER 7839 01-MAY-81 2850 30
7782 ACCOUNTING MANAGER 7839 09-JUN-81 2450 10
7788 RESEARCH ANALYST 7566 09-DEC-82 3000 20
7839 ACCOUNTING PRESIDENT 17-NOV-81 5000 10
7844 SALES SALESMAN 7698 08-SEP-81 1500 0 30
7876 RESEARCH CLERK 7788 12-JAN-83 1100 20
EMPNO ENAME JOB MGR HIREDATE SAL COMM DEPTNO
---------- ---------- --------- ---------- --------- ---------- ---------- ----------
7900 SALES CLERK 7698 03-DEC-81 950 30
7902 RESEARCH ANALYST 7566 03-DEC-81 3000 20
7934 ACCOUNTING CLERK 7782 23-JAN-82 1300 10
SQL>
SQL> drop table dept;
SQL> drop table emp;
SQL>
SQL>
Update salary based on average salary
SQL>
SQL>
SQL>
SQL> create table emp(
2 emp_no integer primary key,
3 lastname varchar2(20) not null,
4 firstname varchar2(15) not null,
5 midinit varchar2(1),
6 street varchar2(30),
7 city varchar2(20),
8 state varchar2(2),
9 zip varchar2(5),
10 shortZipCode varchar2(4),
11 area_code varchar2(3),
12 phone varchar2(8),
13 salary number(5,2),
14 birthdate date,
15 startDate date,
16 title varchar2(20),
17 dept_no integer,
18 mgr integer,
19 region number,
20 division number,
21 total_sales number
22 );
Table created.
SQL> -- emp Table Inserts:
SQL> insert into emp(emp_no, lastname, firstname, midinit, street, city, state, zip,shortZipCode, area_code, phone, birthdate, title)values
2 (1,"Z","Joy","R","1 Ave","New York","NY","12122","2333","212","200-1111","12-nov-1962","President");
1 row created.
SQL> insert into emp(emp_no, lastname, firstname, midinit, street, city, state, zip,shortZipCode, area_code, phone, salary, birthdate, startDate,title, dept_no, mgr, region, division, total_sales)valu
es
2 (2,"X","Lucy","J","1 Street","New York","NY","43552","6633","212","234-4444",7.75,"21-mar-1976","1-feb-1994","Sales Manager",2,1,100,10,40000);
1 row created.
SQL> insert into emp(emp_no, lastname, firstname, midinit, street, city, state, zip,shortZipCode, area_code, phone, salary, birthdate, startDate,title, dept_no, mgr, region, division, total_sales)valu
es
2 (3,"Y","Jordan","E","1 Drive","New York","NY","76822","8763","212","222-2222",7.75,"14-feb-1963","15-mar-1995","Sales Clerk",2,2,100,10,10000);
1 row created.
SQL>
SQL> select dept_no, lastname, salary from emp;
DEPT_NO LASTNAME SALARY
---------- -------------------- ----------
Z
2 X 7.75
2 Y 7.75
SQL>
SQL> UPDATE emp e1
2 SET salary = 1.1 * (SELECT avg(salary) from emp e2 where e1.dept_no = e2.dept_no);
3 rows updated.
SQL>
SQL>
SQL> drop table emp;
Table dropped.
Writing an UPDATE Statement Containing a Subquery
SQL>
SQL> -- create demo table
SQL> create table Employee(
2 ID VARCHAR2(4 BYTE) NOT NULL,
3 First_Name VARCHAR2(10 BYTE),
4 Last_Name VARCHAR2(10 BYTE),
5 Start_Date DATE,
6 End_Date DATE,
7 Salary Number(8,2),
8 City VARCHAR2(10 BYTE),
9 Description VARCHAR2(15 BYTE)
10 )
11 /
Table created.
SQL>
SQL> -- prepare data
SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)
2 values ("01","Jason", "Martin", to_date("19960725","YYYYMMDD"), to_date("20060725","YYYYMMDD"), 1234.56, "Toronto", "Programmer")
3 /
1 row created.
SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)
2 values("02","Alison", "Mathews", to_date("19760321","YYYYMMDD"), to_date("19860221","YYYYMMDD"), 6661.78, "Vancouver","Tester")
3 /
1 row created.
SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)
2 values("03","James", "Smith", to_date("19781212","YYYYMMDD"), to_date("19900315","YYYYMMDD"), 6544.78, "Vancouver","Tester")
3 /
1 row created.
SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)
2 values("04","Celia", "Rice", to_date("19821024","YYYYMMDD"), to_date("19990421","YYYYMMDD"), 2344.78, "Vancouver","Manager")
3 /
1 row created.
SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)
2 values("05","Robert", "Black", to_date("19840115","YYYYMMDD"), to_date("19980808","YYYYMMDD"), 2334.78, "Vancouver","Tester")
3 /
1 row created.
SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)
2 values("06","Linda", "Green", to_date("19870730","YYYYMMDD"), to_date("19960104","YYYYMMDD"), 4322.78,"New York", "Tester")
3 /
1 row created.
SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)
2 values("07","David", "Larry", to_date("19901231","YYYYMMDD"), to_date("19980212","YYYYMMDD"), 7897.78,"New York", "Manager")
3 /
1 row created.
SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)
2 values("08","James", "Cat", to_date("19960917","YYYYMMDD"), to_date("20020415","YYYYMMDD"), 1232.78,"Vancouver", "Tester")
3 /
1 row created.
SQL>
SQL>
SQL>
SQL> -- display data in the table
SQL> select * from Employee
2 /
ID FIRST_NAME LAST_NAME START_DATE END_DATE SALARY CITY DESCRIPTION
---- ---------- ---------- ----------- ----------- ---------- ---------- ---------------
01 Jason Martin 1996-JUL-25 2006-JUL-25 1234.56 Toronto Programmer
02 Alison Mathews 1976-MAR-21 1986-FEB-21 6661.78 Vancouver Tester
03 James Smith 1978-DEC-12 1990-MAR-15 6544.78 Vancouver Tester
04 Celia Rice 1982-OCT-24 1999-APR-21 2344.78 Vancouver Manager
05 Robert Black 1984-JAN-15 1998-AUG-08 2334.78 Vancouver Tester
06 Linda Green 1987-JUL-30 1996-JAN-04 4322.78 New York Tester
07 David Larry 1990-DEC-31 1998-FEB-12 7897.78 New York Manager
08 James Cat 1996-SEP-17 2002-APR-15 1232.78 Vancouver Tester
8 rows selected.
SQL>
SQL>
SQL> -- Writing an UPDATE Statement Containing a Subquery
SQL>
SQL> -- Set the new column value equal to the result returned by a single row subquery
SQL>
SQL> UPDATE employee
2 SET salary =
3 (SELECT AVG(salary)
4 FROM employee);
8 rows updated.
SQL>
SQL> select * from employee;
ID FIRST_NAME LAST_NAME START_DATE END_DATE SALARY CITY DESCRIPTION
---- ---------- ---------- ----------- ----------- ---------- ---------- ---------------
01 Jason Martin 1996-JUL-25 2006-JUL-25 4071.75 Toronto Programmer
02 Alison Mathews 1976-MAR-21 1986-FEB-21 4071.75 Vancouver Tester
03 James Smith 1978-DEC-12 1990-MAR-15 4071.75 Vancouver Tester
04 Celia Rice 1982-OCT-24 1999-APR-21 4071.75 Vancouver Manager
05 Robert Black 1984-JAN-15 1998-AUG-08 4071.75 Vancouver Tester
06 Linda Green 1987-JUL-30 1996-JAN-04 4071.75 New York Tester
07 David Larry 1990-DEC-31 1998-FEB-12 4071.75 New York Manager
08 James Cat 1996-SEP-17 2002-APR-15 4071.75 Vancouver Tester
8 rows selected.
SQL>
SQL> -- clean the table
SQL> drop table Employee
2 /
Table dropped.
SQL>
SQL>