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Oracle PL/SQL/System Tables Views/all users - История изменений
2026-05-25T20:27:22Z
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в 13:45, 26 мая 2010
2010-05-26T13:45:19Z
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Admin: 1 версия
2010-05-26T10:01:05Z
<p>1 версия</p>
<p><b>Новая страница</b></p><div>==Join all_objects and all_users to list user and its object count==<br />
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<!-- start source code --><br />
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<source lang="sql"><br />
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SQL><br />
SQL><br />
SQL> select a.username, (select count(*)<br />
2 from all_objects b<br />
3 where b.owner = a.username) cnt<br />
4 from all_users a<br />
5 /<br />
USERNAME CNT<br />
------------------------------ ----------<br />
SYS 6520<br />
SYSTEM 422<br />
OUTLN 7<br />
DIP 0<br />
TSMSYS 2<br />
INV15 2<br />
DBSNMP 46<br />
INV10 2<br />
CTXSYS 338<br />
XDB 334<br />
ANONYMOUS 0<br />
USERNAME CNT<br />
------------------------------ ----------<br />
MDSYS 458<br />
HR 34<br />
FLOWS_FILES 11<br />
FLOWS_020100 1085<br />
sqle 530<br />
INV11 2<br />
INV12 2<br />
INV13 2<br />
INV14 2<br />
PLSQL 0<br />
INV16 2<br />
USERNAME CNT<br />
------------------------------ ----------<br />
INV17 2<br />
INV18 2<br />
INV19 2<br />
INV20 2<br />
DEFINER 4<br />
27 rows selected.<br />
SQL><br />
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</source><br />
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==User and its average object id==<br />
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<!-- start source code --><br />
<br />
<source lang="sql"><br />
<br />
SQL><br />
SQL> select a.username, (select count(*) from all_objects b where b.owner = a.username) cnt,<br />
2 (select avg(object_id ) from all_objects b where b.owner = a.username) avg<br />
3 from all_users a<br />
4 /<br />
USERNAME CNT AVG<br />
------------------------------ ---------- ----------<br />
SYS 6520 5009.74064<br />
SYSTEM 422 6095.87678<br />
OUTLN 7 1172.57143<br />
DIP 0<br />
TSMSYS 2 8606.5<br />
INV15 2 16237.5<br />
DBSNMP 46 9592.65217<br />
INV10 2 16227.5<br />
CTXSYS 338 9877.92012<br />
XDB 334 10800.7485<br />
ANONYMOUS 0<br />
USERNAME CNT AVG<br />
------------------------------ ---------- ----------<br />
MDSYS 458 11667.2009<br />
HR 34 12104.5<br />
FLOWS_FILES 11 12717.2727<br />
FLOWS_020100 1085 12813.424<br />
sqle 530 16254.6849<br />
INV11 2 16229.5<br />
INV12 2 16231.5<br />
INV13 2 16233.5<br />
INV14 2 16235.5<br />
PLSQL 0<br />
INV16 2 16239.5<br />
USERNAME CNT AVG<br />
------------------------------ ---------- ----------<br />
INV17 2 16241.5<br />
INV18 2 16243.5<br />
INV19 2 16245.5<br />
INV20 2 16247.5<br />
DEFINER 4 16250.5<br />
27 rows selected.<br />
SQL><br />
SQL><br />
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</source></div>
Admin